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(a)
To Explain: a few sentences comparing the distribution of seed mass for the two groups of plants.
(a)
Answer to Problem AP2.24CPT
Skewed with the same centre and a higher spread for the cicada plants
Explanation of Solution
Given:
By seeing the distribution, it is observed that the distribution of the cicada plants is slightly skewed to the right, where the distribution of the control plants is skewed to the left.
Centre: The
Spread: the cicada plants have a large spread, where the box plot is wider.
Outlines: neither distributions appears to contain outliers as there are no “
(b)
To find: the distribution likely has the larger mean.
(b)
Answer to Problem AP2.24CPT
Cicada plants group
Explanation of Solution
Given:
In the previous part (a), it is concluded that the control plants group contained more skewed. Since the mean is strongly influenced by skewed the mean is too more influenced by the left-skewed in the control plants distribution, since a left-skewed distribution contains unusually small values, these small values will decrease the mean and therefore the mean of the control plants group will be lower than the mean of the cicada plants group.
(c)
To Explain: the purpose of the random assignment in this study.
(c)
Answer to Problem AP2.24CPT
For the surety that the two groups are as similar as possible, prior to the experiment
Explanation of Solution
Given:
The random assignments to the groups ensure that the two groups are as similar as possible prior to the experiment and then it also knows that the results of the experiment are due to the treatments.
(d)
To Explain: the name one benefit and one drawback of only using American bellflowers in the study.
(d)
Answer to Problem AP2.24CPT
Advantage: differences between control group and treatment are small
Disadvantage: result of experiment cannot be generalized to other flowers.
Explanation of Solution
Given:
A benefit is that the differences between the treatment and control group will be very small, because all flowers will be of the same type.
A drawback is that you will only have data for one type of flower and therefore the results of the experiment could not be generalized to other flowers.
Chapter 7 Solutions
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University Calculus: Early Transcendentals (4th Edition)
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- (a+b) R2L 2+2*0=? Ma state without proof the uniqueness theorm of probability function suppose thatPandQ are probability measures defined on the same probability space (Q, F)and that Fis generated by a π-system if P(A)=Q(A) tax for all A EthenP=Q i. e. P(A)=Q(A) for alla g // معدلة 2:23 صarrow_forward6. Show that 1{AU B} = max{1{A}, I{B}} = I{A} + I{B} - I{A} I{B}; I{AB} = min{I{A}, I{B}} = I{A} I{B}; I{A A B} = I{A} + I{B}-21{A} I {B} = (I{A} - I{B})².arrow_forwardTheorem 3.5 Suppose that P and Q are probability measures defined on the same probability space (2, F), and that F is generated by a л-system A. If P(A) = Q(A) for all A = A, then P = Q, i.e., P(A) = Q(A) for all A = F.arrow_forward
- 6. Show that, for any random variable, X, and a > 0, Lo P(x -00 P(x < xarrow_forward5. Suppose that X is an integer valued random variable, and let mЄ N. Show that 8 11118 P(narrow_forward食食假 6. Show that I(AUB) = max{1{A}, I{B}} = I{A} + I{B} - I{A} I{B}; I(AB)= min{I{A}, I{B}} = I{A} I{B}; I{A A B} = I{A} + I{B}-21{A} I{B} = (I{A} - I{B})². -arrow_forward11. Suppose that the events (An, n ≥ 1) are independent. Show that the inclusion- exclusion formula reduces to P(UAL)-1-(1-P(Ak)). k=1 k=1arrow_forward8. Show that, if {Xn, n≥ 1} are independent random variables, then sup X,, A) < ∞ for some A.arrow_forward20. Define the o-field R2. Explain its relation to the o-field R.arrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_iosRecommended textbooks for you
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