Essentials of Computer Organization and Architecture
5th Edition
ISBN: 9781284123036
Author: Linda Null
Publisher: Jones & Bartlett Learning
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Chapter 7, Problem 9E
a.
Program Plan Intro
Given:
The fraction of work performed by CPU (f) = 55%=55100=0.55
The fraction of work performed by DISK (f) = 45%=45100=0.45
Speedup of CPU (k) = 1.4
Speedup of the DISK (k) = 2.5
To Find: Overall speedup of the CPU and DISK
Solution:
According to Amdahl’s law; Overall speedup (S)=1(1-f)+(fk) --- (1)
Substitute the value for “f” and “k” in the above equation. So, the equation (1) becomes,
Finding overall speedup for CPU:
SCPU=1(1-0.55)+(0.551.4)SCPU=10.45+0.39SCPU=10.84
SCPU=1.19
Convert 1.19 to percentage:
=>1.19×100%=119%. Subtract 100% from 119% to get the overall speedup percentage of the new system.
Overall speedup percentage of CPU = 119% - 100% = 19%
Finding overall speedup for DISK:
SDISK=1(1-0.45)+(0.452.5)SDISK=10.55+0.18SDISK=10.73
SDISK=1.37
Convert 1.37 to percentage:
=>1.37×100%=137%. Subtract 100% from 137% to get the overall speedup percentage of the new system.
Overall speedup percentage of DISK = 137% - 100% = 37%
b.
Explanation of Solution
If one does not care about money, then, one would go for the upgrade of disk activity because:
From the above part (a), it is clear that the speed of the DISK activity SDISK=37% is more when compared with
c.
Explanation of Solution
Breakeven points for the upgrade:
From the part (a):
Overall speedup for CPU is: 19%
Money needed to upgrade CPU is: $263.15
Overall speedup for DISK is: 37%
Money needed to upgrade DISK is: $216.22
The breakeven points for the upgrades are:
Breakeven point = Money to upgrade CPU × speedup of DISKBreakeven point = $263.15 × 37%Breakeven point = 9736
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Chapter 7 Solutions
Essentials of Computer Organization and Architecture
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