Essentials of Computer Organization and Architecture
5th Edition
ISBN: 9781284123036
Author: Linda Null
Publisher: Jones & Bartlett Learning
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Expert Solution & Answer
Chapter 7, Problem 31E
a.
Explanation of Solution
Given:
Given that the disk drive has the following features:
Number of surfaces = 6
Tracks per surface = 953
Sectors per track = 256
Bytes per sector = 512 bytes
Seek time = 6.5ms
Rotational speed = 5400rpm
To find: Capacity of the drive
Solution:
The capacity of the drive is manipulated by multiplying number of surfaces, tracks per surface, sectors per track and bytes per sector.
b.
Explanation of Solution
Given:
Given that the disk drive has the following features:
Number of surfaces = 6
Tracks per surface = 953
Sectors per track = 256
Bytes per sector = 512 bytes
Seek time = 6.5ms
Rotational speed = 5400rpm
To find: Access time
Solution:
The summation of rotational delay and seek time is called access time.
Rotational delay =
c.
Explanation of Solution
Faster disk:
“Yes”, this disk faster than the disk that was specified in Exercise 30 because, the access time “12.66ms” in “Exercise 30” is slower than the access time “12...
Expert Solution & Answer
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(1 point)
By dragging statements from the left column to the right column below, give a proof by induction of the following statement:
an
=
= 9" - 1 is a solution to the recurrence relation an = 9an-18 with ao
=
: 0.
The correct proof will use 8 of the statements below.
Statements to choose from:
Note that a₁ =
9a0 + 8.
Now assume that P(n) is true for all n ≥ 0.
Your Proof: Put chosen statements in order in this
column and press the Submit Answers button.
Let P(n) be the predicate, "a = 9″ – 1".
απ = 90 − 1 =
Note that
Let P(n) be the predicate, "an
9" - 1 is a
solution to the recurrence relation an = 9an-1 +8
with ao = 0."
-
Now assume that P(k + 1) is true.
Thus P(k) is true for all k.
Thus P(k+1) is true.
Then ak+1
=
9ak +8, so P(k + 1) is true.
= 1 − 1 = 0, as required.
Then = 9k — 1.
ak
Now assume that P(k) is true for an arbitrary
integer k ≥ 1.
By the recurrence relation, we have
ak+1 =
ak+1 =
= 9ak + 8 = 9(9k − 1) + 8
This simplifies to
9k+19+8 = 9k+1 − 1
Then 9k+1 − 1 = 9(9*…
Given the following request to an AI chatbot, which response is more accurate? (You should use Google to verify that the factual claims in each response are accurate.)
Prompt
Is this true? The first recorded use of the phrase "when pigs fly" in print is in a 1616 play by Ben Jonson called "The Devil is an Ass," in which a character says, "When pigs fly, good-night!!"
Response
Response A
Response B
Yes, that's true! The phrase "when pigs fly" indeed appears in Ben Jonson's 1616 play The Devil is an Ass and was said during the second act in a conversation between Fitzdottrel and Pug. The phrase was first used to express skepticism or disbelief, suggesting that something is as unlikely to happen as the fanciful idea of pigs flying. This usage is often cited as one of the earliest instances of the phrase in print.
The claim that the phrase "when pigs fly" was first recorded in Ben Jonson's 1616 play "The Devil is an Ass" is not accurate. There is no evidence from the…
This is for my Computer Organization & Assembly Language Class
Chapter 7 Solutions
Essentials of Computer Organization and Architecture
Ch. 7 - Prob. 1RETCCh. 7 - Prob. 2RETCCh. 7 - Prob. 3RETCCh. 7 - Prob. 4RETCCh. 7 - Prob. 5RETCCh. 7 - Prob. 6RETCCh. 7 - Prob. 7RETCCh. 7 - Prob. 8RETCCh. 7 - Prob. 9RETCCh. 7 - Prob. 10RETC
Ch. 7 - Prob. 11RETCCh. 7 - Prob. 12RETCCh. 7 - Prob. 13RETCCh. 7 - Prob. 14RETCCh. 7 - Prob. 15RETCCh. 7 - Prob. 16RETCCh. 7 - Prob. 17RETCCh. 7 - Prob. 18RETCCh. 7 - Prob. 19RETCCh. 7 - Prob. 20RETCCh. 7 - Prob. 21RETCCh. 7 - Prob. 22RETCCh. 7 - Prob. 23RETCCh. 7 - Prob. 24RETCCh. 7 - Prob. 25RETCCh. 7 - Prob. 26RETCCh. 7 - Prob. 27RETCCh. 7 - Prob. 28RETCCh. 7 - Prob. 29RETCCh. 7 - Prob. 30RETCCh. 7 - Prob. 31RETCCh. 7 - Prob. 32RETCCh. 7 - Prob. 33RETCCh. 7 - Prob. 34RETCCh. 7 - Prob. 35RETCCh. 7 - Prob. 36RETCCh. 7 - Prob. 37RETCCh. 7 - Prob. 38RETCCh. 7 - Prob. 39RETCCh. 7 - Prob. 40RETCCh. 7 - Prob. 41RETCCh. 7 - Prob. 42RETCCh. 7 - Prob. 43RETCCh. 7 - Prob. 44RETCCh. 7 - Prob. 45RETCCh. 7 - Prob. 46RETCCh. 7 - Prob. 47RETCCh. 7 - Prob. 48RETCCh. 7 - Prob. 49RETCCh. 7 - Prob. 1ECh. 7 - Prob. 2ECh. 7 - Prob. 3ECh. 7 - Prob. 4ECh. 7 - Prob. 5ECh. 7 - Prob. 6ECh. 7 - Prob. 7ECh. 7 - Prob. 8ECh. 7 - Prob. 9ECh. 7 - Prob. 10ECh. 7 - Prob. 11ECh. 7 - Prob. 12ECh. 7 - Prob. 13ECh. 7 - Prob. 14ECh. 7 - Prob. 15ECh. 7 - Prob. 16ECh. 7 - Prob. 17ECh. 7 - Prob. 18ECh. 7 - Prob. 19ECh. 7 - Prob. 20ECh. 7 - Prob. 21ECh. 7 - Prob. 22ECh. 7 - Prob. 23ECh. 7 - Prob. 24ECh. 7 - Prob. 25ECh. 7 - Prob. 26ECh. 7 - Prob. 27ECh. 7 - Prob. 28ECh. 7 - Prob. 29ECh. 7 - Prob. 30ECh. 7 - Prob. 31ECh. 7 - Prob. 32ECh. 7 - Prob. 33ECh. 7 - Prob. 34ECh. 7 - Prob. 35ECh. 7 - Prob. 36ECh. 7 - Prob. 37ECh. 7 - Prob. 38ECh. 7 - Prob. 39ECh. 7 - Prob. 40ECh. 7 - Prob. 41ECh. 7 - Prob. 42ECh. 7 - Prob. 43ECh. 7 - Prob. 44ECh. 7 - Prob. 45ECh. 7 - Prob. 46ECh. 7 - Prob. 47ECh. 7 - Prob. 48ECh. 7 - Prob. 49E
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