Essentials of Computer Organization and Architecture
Essentials of Computer Organization and Architecture
5th Edition
ISBN: 9781284123036
Author: Linda Null
Publisher: Jones & Bartlett Learning
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Chapter 7, Problem 4RETC

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Three types of durable storage:

  • Magnetic disk
  • Magnetic tape
  • Optical media

Magnetic disk:

  • Magnetic disk is a storage device in a computer which uses a magnetization process to write, rewrite and access the data.
  • It stores the data in the form of tracks, spots and sectors and it is enclosed by a magnetic coat.
  • Hard disk, floppy disk are examples of magnetic disk.
  • It takes more time to retrieve data from magnetic disk than compared when retrieving from the main memory.

Magnetic tape:

  • Magnetic tape is a data storage device used in a computer for storing digital information.
  • It uses the magnetic recording which is made of thin, long narrow strip of plastic film.
  • Magnetic tape drives are the primary storage device used in first generation computers...

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(1 point) By dragging statements from the left column to the right column below, give a proof by induction of the following statement: an = = 9" - 1 is a solution to the recurrence relation an = 9an-18 with ao = : 0. The correct proof will use 8 of the statements below. Statements to choose from: Note that a₁ = 9a0 + 8. Now assume that P(n) is true for all n ≥ 0. Your Proof: Put chosen statements in order in this column and press the Submit Answers button. Let P(n) be the predicate, "a = 9″ – 1". απ = 90 − 1 = Note that Let P(n) be the predicate, "an 9" - 1 is a solution to the recurrence relation an = 9an-1 +8 with ao = 0." - Now assume that P(k + 1) is true. Thus P(k) is true for all k. Thus P(k+1) is true. Then ak+1 = 9ak +8, so P(k + 1) is true. = 1 − 1 = 0, as required. Then = 9k — 1. ak Now assume that P(k) is true for an arbitrary integer k ≥ 1. By the recurrence relation, we have ak+1 = ak+1 = = 9ak + 8 = 9(9k − 1) + 8 This simplifies to 9k+19+8 = 9k+1 − 1 Then 9k+1 − 1 = 9(9*…
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Chapter 7 Solutions

Essentials of Computer Organization and Architecture

Ch. 7 - Prob. 11RETCCh. 7 - Prob. 12RETCCh. 7 - Prob. 13RETCCh. 7 - Prob. 14RETCCh. 7 - Prob. 15RETCCh. 7 - Prob. 16RETCCh. 7 - Prob. 17RETCCh. 7 - Prob. 18RETCCh. 7 - Prob. 19RETCCh. 7 - Prob. 20RETCCh. 7 - Prob. 21RETCCh. 7 - Prob. 22RETCCh. 7 - Prob. 23RETCCh. 7 - Prob. 24RETCCh. 7 - Prob. 25RETCCh. 7 - Prob. 26RETCCh. 7 - Prob. 27RETCCh. 7 - Prob. 28RETCCh. 7 - Prob. 29RETCCh. 7 - Prob. 30RETCCh. 7 - Prob. 31RETCCh. 7 - Prob. 32RETCCh. 7 - Prob. 33RETCCh. 7 - Prob. 34RETCCh. 7 - Prob. 35RETCCh. 7 - Prob. 36RETCCh. 7 - Prob. 37RETCCh. 7 - Prob. 38RETCCh. 7 - Prob. 39RETCCh. 7 - Prob. 40RETCCh. 7 - Prob. 41RETCCh. 7 - Prob. 42RETCCh. 7 - Prob. 43RETCCh. 7 - Prob. 44RETCCh. 7 - Prob. 45RETCCh. 7 - Prob. 46RETCCh. 7 - Prob. 47RETCCh. 7 - Prob. 48RETCCh. 7 - Prob. 49RETCCh. 7 - Prob. 1ECh. 7 - Prob. 2ECh. 7 - Prob. 3ECh. 7 - Prob. 4ECh. 7 - Prob. 5ECh. 7 - Prob. 6ECh. 7 - Prob. 7ECh. 7 - Prob. 8ECh. 7 - Prob. 9ECh. 7 - Prob. 10ECh. 7 - Prob. 11ECh. 7 - Prob. 12ECh. 7 - Prob. 13ECh. 7 - Prob. 14ECh. 7 - Prob. 15ECh. 7 - Prob. 16ECh. 7 - Prob. 17ECh. 7 - Prob. 18ECh. 7 - Prob. 19ECh. 7 - Prob. 20ECh. 7 - Prob. 21ECh. 7 - Prob. 22ECh. 7 - Prob. 23ECh. 7 - Prob. 24ECh. 7 - Prob. 25ECh. 7 - Prob. 26ECh. 7 - Prob. 27ECh. 7 - Prob. 28ECh. 7 - Prob. 29ECh. 7 - Prob. 30ECh. 7 - Prob. 31ECh. 7 - Prob. 32ECh. 7 - Prob. 33ECh. 7 - Prob. 34ECh. 7 - Prob. 35ECh. 7 - Prob. 36ECh. 7 - Prob. 37ECh. 7 - Prob. 38ECh. 7 - Prob. 39ECh. 7 - Prob. 40ECh. 7 - Prob. 41ECh. 7 - Prob. 42ECh. 7 - Prob. 43ECh. 7 - Prob. 44ECh. 7 - Prob. 45ECh. 7 - Prob. 46ECh. 7 - Prob. 47ECh. 7 - Prob. 48ECh. 7 - Prob. 49E
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