EBK BIOLOGY
5th Edition
ISBN: 9780133954425
Author: Maier
Publisher: YUZU
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Chapter 7, Problem 8LTB
Summary Introduction
Introduction:
Any inherited disease is a genetic disorder. It is caused due to abnormalities in the genomes which are passed on from the parents to the offsprings. These disorders are sex-linked disorders, which are due to the inherited defective X and Y chromosomes.
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Students have asked these similar questions
Recessives Allele, an allele that is fully expressed in the phenotype of a heterozygote.
Select one:
True
False
Which of the following statements about X-linked recessive patterns is true?
The X-linked trait appears more often in females than in males.
An affected father can never pass an X-linked recessive allele to an XY son.
An affected father can never pass an X-linked recessive allele to a daughter.
Heterozygous females always express the X-linked recessive trait.
Having two different harmful disease alleles at the same locus is called a
double heterozygote
compound heterozygote
double homozygote
compound homozygote
Chapter 7 Solutions
EBK BIOLOGY
Ch. 7 - What is the relationship between genotype and...Ch. 7 - Prob. 2LTBCh. 7 - Prob. 3LTBCh. 7 - Prob. 4LTBCh. 7 - Prob. 5LTBCh. 7 - Scientists have recently developed a process by...Ch. 7 - What is the physical basis for the independent...Ch. 7 - Prob. 8LTBCh. 7 - Prob. 9LTBCh. 7 - Prob. 10LTB
Ch. 7 - Prob. 1GPCh. 7 - Prob. 2GPCh. 7 - Prob. 3GPCh. 7 - Prob. 4GPCh. 7 - Pfeiffer syndrome is a dominant genetic disease...Ch. 7 - Prob. 6GPCh. 7 - A cross between a pea plant that produces round...Ch. 7 - Prob. 8GPCh. 7 - The allele BRCA2 was identified in families with...Ch. 7 - Two parents both have brown eyes, but they have...Ch. 7 - Prob. 2AAATBCh. 7 - Prob. 3AAATBCh. 7 - Prob. 1CTSCh. 7 - Prob. 2CTSCh. 7 - Prob. 3CTS
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- The young woman shown at right has albinismvery pale skin, white hair, and pale blue eyes. This phenotype is due to the absence of melanin, which imparts color to the skin, hair, and eyes. It typically is caused by a recessive allele. In the following situations, what are the probable genotypes of the father, the mother, and their children? a. Both parents have normal phenotypes; some of their children are albino and others are not. b. Both parents and all their children are albino. c. The mother is not albino, the father is albino, and one of their four children is albino.arrow_forwardConsidering a common autosomal recessive trait: (Read each statement carefully. Select all of the statements below that are true (that you agree with). Leave any statements that are false (that you do not agree with) un- selected.) the unaffected biological siblings of an affected person should be heterozygotes. an unaffected woman and an affected man have at most a 100% probability of having a affected child. an affected person should have an affected parent. The unaffected offspring of an affected parent must be carriers.arrow_forwardPKU disease is recessive. A man and a woman are both carriers for PKU disease. Determine the following: Genotype of the man: Genotype of the woman: Possible genotypes of children: Possible phenotypes of children: Probability of PKU disease in their children:arrow_forward
- Which of the following genetic disorders is described by the following: Recessive sex-linked disorder. More common in males. Results in the inability to distinguish some colors. Male-pattern baldness Cystic fibrosis albinism colorblindnessarrow_forwardA recessive disease is represented in 8% of the US population. What is the frequency of homozygous dominant, heterozygous and homozygous recessive individuals in the US population for that disease Homozygous dominant: 0.36 Heterozygous: 2 x 0.36 x 0.64 Homozygous recessive: 0.64 Homozygous dominant: 0.362 Heterozygous: 2 x 0.36 x 0.64 Homozygous recessive: 0.642 Homozygous dominant: 0.72 Heterozygous: 2 x 0.72 x 0.28 Homozygous recessive: 0.28 Homozygous dominant: 0.722 Heterozygous: 2 x 0.72 x 0.28 Homozygous recessive: 0.282arrow_forwardF1 and F2 offspring with given genders and disease phenotypes. The data are generated from an initial parental cross. One parent displays the disease phenotype and one displays the wild-type (WT) phenotype. The WT parent always has a homozygous genotype. There are three possible modes of inheritance that underlie the generation of the data. All are monogenic. They are: (i) Autosomal Recessive. (ii) Homozygous Lethal Dominant. (iii) Autosomal Dominant. One's phenotype is determined by their genotype at the disease locus and the mode of inheritance, as we have seen with Punnett Square. on the F2 data and make a decision, based on your statistical analysis, as to whether you reject or do not reject the computer-generated model of inheritance as being consistent with the observed data. The mode of inheritance you are to test on the observed data is autosomal recessive. PARENTAL CROSS Parental cross: Father with disease phenotype, Mother with wild-type phenotype. F1 DATA Phenotype…arrow_forward
- If a trait is X-linked, which of the following statements is true? Two recessive alleles are needed to express that trait. A female with one recessive allele will express that trait. A female can be a carrier, affected or unaffected. The trait is inherited from father to son. The gene is carried on the Y chromosome.arrow_forwardHemophilia is a sex-linked trait. A person with hemophilia is lacking certain proteins that are necessary for normal blood clotting. Hemophilia is caused by a recessive allele so use "N" for normal and "n" for hemophilia. Since hemophilia is sex-linked, remember a woman will have two alleles (NN or Nn or nn) but a man will have only one allele (N or n). A woman who is heterozygous (a carrier) for hemophilia marries a normal man: a.What are the genotypes of the parents? b.What is the probability that a male offspring will have hemophilia? c. What is the probability of having a hemophiliac female offspring?arrow_forwardAssume for a moment that a child has a autosomal recessive disorder, but both parents appear normal. What is the genotype of both parents? : one parent must be homozygous dominant : both parents must be homozygous recessive : both parents are heterozygous : both parents nust be homozygous dominantarrow_forward
- People with recessive disorders are usually born to normal parents who are both heterozygotes which means that both parents are carriers of the dominant allele for the disorder but appear normal themselves. Select one: True Falsearrow_forwardAlbinism is an autosomal (not sex-linked) recessive trait. A man and woman are both of normal pigmentation and have one child out of three who is albino (without melanin pigmentation). What are the genotypes of the albino's parents? One parent must be homozygous for the recessive allele; the other parent can be homozygous dominant, homozygous recessive, or heterozygous. Both parents must be homozygous dominant. One parent must be heterozygous; the other parent can be homozygous dominant, homozygous recessive, or heterozygous. Both parents must be heterozygous. One parent must be homozygous dominant; the other parent must be heterozygous. O000arrow_forwardIn humans, having facial dimples is dominant to not having facial dimples. Mary has dimples, yet only 3 of her 10 children have dimples. What must Mary's genotype be? homozygous dominant heterozygous homozygous recessive has dimples does not have dimplesarrow_forward
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