Gen Combo Ll Basic Biomechanics; Connect Ac; Maxtraq Software Ac
8th Edition
ISBN: 9781264013876
Author: Hall
Publisher: McGraw-Hill Education
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Chapter 7, Problem 8AP
8. How much tension (Fm) must be supplied by the triceps to stabilize the arm against an external force (Fe) of 200 N, given dm = 2 cm and de = 25 cm? What is the magnitude of the joint reaction force (R)? (Because the forearm is vertical, its weight does not produce torque at the elbow.) (Answer: Fm = 2500 N, R = 2700 N)
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2. a) Label the system provided below, including the reference frame, moment arms and vector forces
with the information provided.
Internal moment arm = 4cm +0.04m
External moment arm relative
to the segment weight = 25cm 0.25m
External moment arm relative
to the load weight = 45cm 40.45m
Segment weight = 50 N
Load weight = 100 N
Lower leg segment angle relative
to horizontal plane = 45°
Quadriceps tendon angle = 45°
Axis of
rotation
MF
SW
LW
2b) Using the figure in 2a., calculate the external torque of the system relative to the normal
component of segment and load weights listed above.
2c) Calculate the amount of both the tangential component of the muscle force and the muscle force
itself required to keep this system in a state of static equilibrium.
5. Using the hip joint reaction force example we did in class, if the moment arm for the cane is
30 cm and the cane force is applied in the vertical direction, how much would the cane force
have to be to reduce the muscle force to 1.5BW? Under that condition, what would the joint
reaction force be?
Explain the answer biomechanically
Chapter 7 Solutions
Gen Combo Ll Basic Biomechanics; Connect Ac; Maxtraq Software Ac
Ch. 7 - Construct a chart listing all muscles crossing the...Ch. 7 - Prob. 2IPCh. 7 - Prob. 3IPCh. 7 - INTRODUCTORY PROBLEMS 4. List the muscles that...Ch. 7 - INTRODUCTORY PROBLEMS 5. List the muscles used as...Ch. 7 - INTRODUCTORY PROBLEMS 6. Explain how the use of an...Ch. 7 - INTRODUCTORY PROBLEMS 7. Select a familiar...Ch. 7 - 8. Using the diagram in Sample Problem 7.1 as a...Ch. 7 - 10. Solve Sample Problem 7.2 with the addition of...Ch. 7 - Identify the sequence of movements that occur at...
Ch. 7 - Which muscles are most likely to serve as agonists...Ch. 7 - Prob. 3APCh. 7 - ADDITIONAL PROBLEMS 4. Which muscles are most...Ch. 7 - Prob. 5APCh. 7 - Prob. 6APCh. 7 - 8. How much tension (Fm) must be supplied by the...Ch. 7 - 9. What is the length of the moment arm between...Ch. 7 - Prob. 10AP
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- How much force must be produced by the biceps brachii, attaching at 90? to the radius at 3 cm from the center of rotation at the elbow joint, to support a weight of 200 N held in the hand at a distance of 30 cm from the elbow joint? (Neglect the weight of the forearm and hand, and neglect any action of other muscles)arrow_forward< The three main forces that act on the patella are shown on the diagram of the knee joint below. These forces are the quadriceps muscle force (FQ), the patella ligament force (FPL), and the patellofemoral joint reaction force (FPF). The angles a and ẞ are with respect to a line that is perpendicular to FPF. Assuming a = 15°, ẞ = 20°, and FQ = 3725 N, use equations for static equilibrium to calculate (a) FPL, and (b) FPF. (Hint: To solve this problem consider using a coordinate system that is aligned with the principal axes of the patella instead of the usual vertical and horizontal axes). (c) Many people assume FQ and FPL are always equal in magnitude but this is only true under certain circumstances. Under what conditions are FQ and FPL equal in magnitude? Fo FPF FP B GriffithUNIVERSITY Queensland Australiaarrow_forwardWith the shoulder flexed at 30°, the moment arm of the deltoid muscle is 2.0 cm. Solve for the force exerted by the deltoid muscle at the glenohumeral joint give the following assumptions: The deltoid is the only active muscle at the glenohumeral joint The weight of the humerus is 48 N. The center of gravity of the humerus is located 30 cm from the shoulder center of rotation STATIC EQUILIBRIUM EQUATIONS CONSIDERING ONLY THE DELTOID MUSCLE Fo MA = 18 Cn COR B=55". 0-30° RaF 30 cm FG = 24 Narrow_forward
- GIVE 3 EXERCISES THAT CAN BE CONSIDERED AS A LOCOMOTOR MOVEMENT WITH ABDUCTION AND ADDUCTION MOVEMENT. WHY?arrow_forward5 Describe the difference in maximal force capacity in the knee extensors vs the knee flexors. What role does bi-articulation at this joint play? How does this influence potential injury mechanics?arrow_forwardTwo lifter's knees are of interest at a specific moment in their lifts. In both lifts, the knee extensor torque is 100 Nm, requiring quadriceps tendon/patella ligament forces of 1000 N (about 220 Ibs). Despite equivalent knee torques and quadriceps forces, patellofemoral joint forces are higher on the knees of lifter A. Briefly explain why. Edit View Insert Format Tools Table 12pt v Paragraph v BIUAarrow_forward
- GIVE 3 EXERCISES THAT CAN BE CONSIDERED AS A LOCOMOTOR MOVEMENT WITH LATERAL ROTATION AND MEDIAL ROTATION MOVEMENT AND WHY?arrow_forwardGIVE 3 EXERCISE THAT CAN BE CONSIDERED AS A LOCOMOTOR MOVEMENT WITH FLEXION AND EXTENSION MOVEMENT AND WHYarrow_forwardWhich of these increases force production? 1. Increasing the velocity of the concentric contraction 2. Increasing the velocity of the eccentric contraction 3. Increasing strength of neural stimulation 4. Holding your breath during contraction 5. Increasing frequency of neural stimulation 6. Decreasing the velocity of the concentric contraction 7. Starting the contraction with the joint in full extension 8. Decreasing the velocity of the eccentric contractionarrow_forward
- 5 of 10 Which of the following exercises would be an example of a Stabilization-Focused exercise for the shoulders? Standing cable row Bench press Single-leg dumbell overhead press shoulder press machine Next ▶arrow_forwardMany locomotion movements use: O a proximal to distal sequence of lower extremity joint torques O more eccentric than concentric contractions O only concentric contractions O a distal to proximal sequence of lower extremity joint torquesarrow_forward3 E there to search D Calculate the ankle torque during initial gait contact from the following data set to 1 decimal place. NOTE if your answer is negative put the negative sign in the answer! FZ 765 N 4 с Fx-290 N CoP z 0 m Cop x 0.51 m Ankle z 0.074 m Ankle x 0.62 m Answer Check R F 96 5 Bi T G B 6 y H N U J 8 M 1 hp к Ji C 9 9 P O alt gr O P ? ctri 910- C > pri se 1 GBP/AUD-0.41% pause # ← tock Next page 7 11:26 02/12/2023 1 end ☐ po up 5 Carrow_forward
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