EP INTRODUCTORY CHEM.-MOD.MASTERINGCHEM
EP INTRODUCTORY CHEM.-MOD.MASTERINGCHEM
8th Edition
ISBN: 9780134554433
Author: CORWIN
Publisher: PEARSON CO
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Chapter 7, Problem 85E
Interpretation Introduction

(a)

Interpretation:

The reaction CH4(g)+O2(g)CO2(g)+H2O(g) is to be balanced.

Concept introduction:

A balanced chemical equation represents an equation in which all the reactants and products are written with their stoichiometric coefficient and physical states. The number of atoms of an element on the both sides of the equation is equal.

Interpretation Introduction

(b)

Interpretation:

The reaction C3H8(g)+O2(g)CO2(g)+H2O(g) is to be balanced.

Concept introduction:

A balanced chemical equation represents an equation in which all the reactants and products are written with their stoichiometric coefficient and physical states. The number of atoms of an element on the both sides of the equation is equal.

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Decane, C10H22(l), undergoes complete combustion if there is sufficient oxygen available: 2 C10H22(l) + 31 O2(g) → 20 CO2(g) + 22 H2O(g) (a) What mass of oxygen is required for the complete combustion of 800g of decane? (b) A sample of decane is burned, producing 12 mol of carbon dioxide. What amount (moles) of water is also produced? Include a therefore statement for EACH a) and b)
(1) One of the steps in the commercial process for converting ammonia to nitric acid involves the conversion of ammonia, NH3(g) to nitrous oxide, NO(g). 4 NH3(g )  +  5 O2(g)  → 4  NO(g)  +  6 H2O(l) Atomic weights (g/mol): N=14, H=1, O=16 a. Balance the above chemical equation that represents the conversion. b. How many moles of oxygen are needed to convert 2.5 moles of ammonia? c. How many grams of water will be produced from 2.5 moles of ammonia? d. If 150 grams of oxygen reacted 2.5 moles of ammonia, identify the limiting and excess reagents. e. How much of the excess reagent remains unreacted? f. If the reaction in (d) produces 10.0 grams of nitrous oxide, calculate the percent yield.
A mixture of O2 (g) and H2 (g) explosively react to form steam H2O (g) in the presence of an electric spark.  4.15 mol of H2 (g) and 7.13 mol of O2 (g) are mixed and allowed to react in the presence of a electric spark.  The yield of the reaction is 100%. (a) Write a balanced equation for the reaction. (b) What is the limiting reactant? (answer: 4.15 mol H2 can produce 4.15 mol H2O and 7.13 mol O2 can produce 14.3 mol of H2O, so, H2 is the limiting reactant.) (c) What is the theoretical yield of H2O in moles? (answer: 4.15 mol) (d) How many moles of O2 are left after the reaction? (answer: 5.05 mol) (e) How many moles of H2 and O2 would be left if the reaction yield is only 74.5%? (answer: H2: 1.06 mol left; O2: 5.59 mol)

Chapter 7 Solutions

EP INTRODUCTORY CHEM.-MOD.MASTERINGCHEM

Ch. 7 - Prob. 11CECh. 7 - Prob. 12CECh. 7 - Prob. 13CECh. 7 - Prob. 14CECh. 7 - Prob. 15CECh. 7 - Prob. 16CECh. 7 - Prob. 1KTCh. 7 - Prob. 2KTCh. 7 - Prob. 3KTCh. 7 - Prob. 4KTCh. 7 - Prob. 5KTCh. 7 - Prob. 6KTCh. 7 - Prob. 7KTCh. 7 - Prob. 8KTCh. 7 - Prob. 9KTCh. 7 - Prob. 10KTCh. 7 - Prob. 11KTCh. 7 - Prob. 12KTCh. 7 - Prob. 13KTCh. 7 - Prob. 14KTCh. 7 - Prob. 15KTCh. 7 - Prob. 16KTCh. 7 - Prob. 17KTCh. 7 - Prob. 18KTCh. 7 - Prob. 19KTCh. 7 - Prob. 20KTCh. 7 - Prob. 21KTCh. 7 - Prob. 22KTCh. 7 - Prob. 1ECh. 7 - Prob. 2ECh. 7 - Prob. 3ECh. 7 - Prob. 4ECh. 7 - Prob. 5ECh. 7 - Prob. 6ECh. 7 - Prob. 7ECh. 7 - Prob. 8ECh. 7 - Prob. 9ECh. 7 - Prob. 10ECh. 7 - Prob. 11ECh. 7 - Prob. 12ECh. 7 - Prob. 13ECh. 7 - Prob. 14ECh. 7 - Prob. 15ECh. 7 - Prob. 16ECh. 7 - Prob. 17ECh. 7 - Prob. 18ECh. 7 - Prob. 19ECh. 7 - Prob. 20ECh. 7 - Prob. 21ECh. 7 - Prob. 22ECh. 7 - Prob. 23ECh. 7 - Prob. 24ECh. 7 - Prob. 25ECh. 7 - Prob. 26ECh. 7 - Prob. 27ECh. 7 - Prob. 28ECh. 7 - Prob. 29ECh. 7 - Prob. 30ECh. 7 - Prob. 31ECh. 7 - Prob. 32ECh. 7 - Prob. 33ECh. 7 - Prob. 34ECh. 7 - Prob. 35ECh. 7 - Prob. 36ECh. 7 - Prob. 37ECh. 7 - Prob. 38ECh. 7 - Prob. 39ECh. 7 - Prob. 40ECh. 7 - Prob. 41ECh. 7 - Prob. 42ECh. 7 - Prob. 43ECh. 7 - Prob. 44ECh. 7 - Prob. 45ECh. 7 - Prob. 46ECh. 7 - Prob. 47ECh. 7 - Prob. 48ECh. 7 - Prob. 49ECh. 7 - Prob. 50ECh. 7 - Prob. 51ECh. 7 - Prob. 52ECh. 7 - Prob. 53ECh. 7 - Prob. 54ECh. 7 - Prob. 55ECh. 7 - Prob. 56ECh. 7 - Prob. 57ECh. 7 - Prob. 58ECh. 7 - Prob. 59ECh. 7 - Prob. 60ECh. 7 - Prob. 61ECh. 7 - Prob. 62ECh. 7 - Prob. 63ECh. 7 - Prob. 64ECh. 7 - Prob. 65ECh. 7 - Prob. 66ECh. 7 - Prob. 67ECh. 7 - Prob. 68ECh. 7 - Prob. 69ECh. 7 - Prob. 70ECh. 7 - Prob. 71ECh. 7 - Prob. 72ECh. 7 - Prob. 73ECh. 7 - Prob. 74ECh. 7 - Prob. 75ECh. 7 - Prob. 76ECh. 7 - Prob. 77ECh. 7 - Prob. 78ECh. 7 - Prob. 79ECh. 7 - Prob. 80ECh. 7 - Prob. 81ECh. 7 - Prob. 82ECh. 7 - Prob. 83ECh. 7 - Prob. 84ECh. 7 - Prob. 85ECh. 7 - Prob. 86ECh. 7 - Prob. 87ECh. 7 - Prob. 88ECh. 7 - Prob. 1STCh. 7 - Prob. 2STCh. 7 - Prob. 3STCh. 7 - Prob. 4STCh. 7 - Prob. 5STCh. 7 - Prob. 6STCh. 7 - Prob. 7STCh. 7 - Prob. 8STCh. 7 - Prob. 9STCh. 7 - Prob. 10STCh. 7 - Prob. 11STCh. 7 - Prob. 12STCh. 7 - Prob. 13STCh. 7 - Prob. 14STCh. 7 - Prob. 15STCh. 7 - Prob. 16STCh. 7 - Prob. 17STCh. 7 - Prob. 18ST
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