Principles of Geotechnical Engineering (MindTap Course List)
Principles of Geotechnical Engineering (MindTap Course List)
9th Edition
ISBN: 9781305970939
Author: Braja M. Das, Khaled Sobhan
Publisher: Cengage Learning
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Chapter 7, Problem 7.9P

(a)

To determine

Find the absolute permeability of the soil.

(a)

Expert Solution
Check Mark

Answer to Problem 7.9P

The absolute permeability of the soil is 8.4×1013m2_.

Explanation of Solution

Given information:

The length of the soil sample L is 400 mm.

The area of the sample A is 7,854mm2.

The diameter of the standpipe (d) is 11 mm.

The head difference (h1) at t=0 is 450 mm.

The head difference  (h2) at t=8min is 200 mm.

The unit weight of water (γw) is 9.789kN/m3.

The dynamic viscosity of water (η) is 1.005×103Ns/m2.

Calculation:

Determine the area of the standpipe a using the relation.

a=πd24

Substitute 11 mm for d.

a=π(11)24=95.03mm2

Determine the hydraulic conductivity k using the relation.

k=2.303(aLAt)log10(h1h2)

Substitute 95.03mm2 for a, 400 mm for L, 7,854mm2 for A, 8 min for t, 450 mm for h1, and 200 mm for h2.

k=2.303(95.03×4007,854×8min×60sec1min)log10(450200)=8.18×103mm/s×1cm10mm=8.18×104cm/sec

Determine the absolute permeability of the soil using the relation.

k=γwηK¯

Substitute 8.18×104cm/sec for k, 9.789kN/m3 for γw, and 1.005×103Ns/m2 for η.

8.18×104cm/sec×1m100cm=9.789×1031.005×103×K¯8.18×106×1.005×1039.789×103=K¯K¯=8.4×1013m2

Therefore, the absolute permeability of the soil is 8.4×1013m2_.

(b)

To determine

Find the head difference at 4 min time duration.

(b)

Expert Solution
Check Mark

Answer to Problem 7.9P

The head difference at 4 min time duration is 30cm_.

Explanation of Solution

Given information:

The length of the soil sample L is 400 mm.

The area of the sample A is 7,854mm2.

The diameter of the standpipe (d) is 11 mm.

The head difference (h1) at t=0 is 450 mm.

The head difference (h2) at t=8min is 200 mm.

The unit weight of water (γw) is 9.789kN/m3.

The dynamic viscosity of water (η) is 1.005×103Ns/m2.

Calculation:

Determine the head difference at 4 min time duration using the relation.

k=2.303(aLAt)log10(h1h2)

Substitute 8.18×104cm/sec for k, 95.03mm2 for a, 400 mm for L, 7,854mm2 for A, 8 min for t, and 450 mm for h1.

8.18×104cm/sec×10mm1cm=2.303(95.03×4007,854×4min×60sec1min)log10(450h2)8.18×1030.0464=log10(450h2)10(0.176)=(450h2)h2=4501.5

h2=300mm×1cm10mmh2=30cm

Therefore, the head difference at 4 min time duration is 30cm_.

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PROBLEM 1 The following data are for a falling-head permeability test: Length of the soil sample = 500 mm Area of the soil sample = 1600 mm2 Area of the standpipe = 97 mm2 At time t = 0, head difference = 410 mm At time t = 10 min, head difference = 185 mm If the test was conducted at 20°C at which ywater = 9.789 kN/m³ and n = 1.005x10-3 N *s/m2, Determine the absolute permeability of soil (cm/sec) = 7 min ? (cm) a. b. What was the head difference at t
6. The following data are for a falling-head permeability test: • Length of the soil sample = 140mm • Diameter of soil sample = 70 mm • Area of the standpipe = 19.6 mm? At time t= 0, head difference 5 500 mm At time t= 7 min, head difference 5 350 mm %3D a. Determine the hydraulic conductivity of the soil (cm/sec). b. What was the head difference at t= 5 min?
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