Principles of Geotechnical Engineering (MindTap Course List)
9th Edition
ISBN: 9781305970939
Author: Braja M. Das, Khaled Sobhan
Publisher: Cengage Learning
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Chapter 7, Problem 7.21P
To determine
Find the ratio of equivalent permeability
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A layered soil is shown in the figure below. Given that
H1 = 1 m, k1 = 10-4 cm/sec
H2 = 1 m, k2 = 2.8 x 10-2 cm/sec
H3 = 2 m, k3 = 3.5 x 10-5 cm/sec
Estimate the ratio of equivalent permeability, kH(eq)/kV(eq).
Problem 7.21
How to solve 9.4
Chapter 7 Solutions
Principles of Geotechnical Engineering (MindTap Course List)
Ch. 7 - Prob. 7.1PCh. 7 - Prob. 7.2PCh. 7 - Prob. 7.3PCh. 7 - Prob. 7.4PCh. 7 - Prob. 7.5PCh. 7 - Prob. 7.6PCh. 7 - Prob. 7.7PCh. 7 - Prob. 7.8PCh. 7 - Prob. 7.9PCh. 7 - Prob. 7.10P
Ch. 7 - Prob. 7.11PCh. 7 - Prob. 7.12PCh. 7 - Prob. 7.13PCh. 7 - Prob. 7.14PCh. 7 - Prob. 7.15PCh. 7 - Prob. 7.16PCh. 7 - Prob. 7.17PCh. 7 - Prob. 7.18PCh. 7 - Prob. 7.19PCh. 7 - Prob. 7.20PCh. 7 - Prob. 7.21PCh. 7 - Refer to Figure 7.24. The following data were...Ch. 7 - Prob. 7.23PCh. 7 - Prob. 7.1CTP
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- Solutions plsarrow_forwardA canal is cut into a soil with a stratigraphy as shown. Assume that flow takes place horizontally and vertically through the sides of the canal and vertically below the canal. The values of k in each layer is given. a. What is the equivalent permeability in the horizontal direction through the sides of the canal in cm/day? b. What is the equivalent permeability in the horizontal direction through the sides of the canal in cm/day? c. Determine the equivalent permeability in the vertical directions below the bottom of the canal, in cm/day. 1.0 m k = 2.3 x 10* cm/s 1.5 m T. k = 5.2 x 10 cm/s 3.0 m 2.0 m k = 2 x 10 cm/s 1.2 m k- 0.3 x 10 cm/s 3.0 m k = 0.8 x 10° cmn/sarrow_forwardWater flows through a sand filter as shown on the figure. The soil has a cross sectional area of 0.39 m². d1=d2=d3=0.52 m. Head difference is 0.93 m. Inflow Outflow Soil A Soil B Soil C d2 d3 Coefficient of Permeability for Each Soil: Soil A Kax 2.92 x 10-2 cm/s Soil A Kaz 1.36 x 10-3 cm/s Soil B Kbx 1.67 x 10.2 cm/s Soil B Kbz 2.92 x 10-3 cm/s Soil CKcx 3.28 x 102 cm/s Soil C Kcz 3.49 x 10-3 cm/s Compute the coefficient of permeability of the sand filler in cm/s. Use 4 decimal placesarrow_forward
- A natural deposit of soil was found to have a water content of 27% and to be 88% saturated. Gs=2.7.Calculate (a) the void ratio, e; (b) the porosity, n; and (c) the dry density, ρd. (use kg/m^3 for density units). Include phase diagrams.arrow_forwardThe figure shows the layers of soll in a tube that is 100mm by 150mm in cross-section. Water is supplied to maintain a constant head difference of 450mm across the sample. The hydraulic conductivity of the soils in the direction of flow through them are tabulated as shown. Compute the flow rate in cm:/hr. k = 2 x 10* cm/s Kç = 1.75 x 10- cm/s k = 3.7 x 10 cm/s K= 2.1 x 10 cm/s Water upply outfiow 50 mm A D. 50 mm 200 200 200 mmarrow_forwardProblem 3: A layered soil is shown below. Given: H1 = 1.5 m kj = 9 x 104 cm/sec H2 = 2.5 m k2 = 7.8 x 10³ cm/sec H3 = 3.5 m k3 = 4.5 x 10$ cm/sec %3D Estimate the ratio of equivalent permeability, kH(eqykv(cq). H1 H2 k2 H3arrow_forward
- Three layers of soil are shown with the corresponding values of coefficient of permeability. K = 4 x 103 cm/sec 3 m К 3 5 х 103 сm/sec 4 m 5 m K3 = 6 x 103 cm/sec What is the equivalent vertical coefficient of permeability (in cm/s) ? O 5.035 x 103 cm/s O 4.113 x 10 3 cm/s 3.085 x 103 cm/s O 2.839 x 103 cm/sarrow_forwardConsider point P. If the groundwater drops 1m to the top of the clay layer, what would the change in Total Stress and Pore Water Pressure change? 1 m 1m 2m 2m P Sand Clay Sand Pd = 1.35 Mg/m³ Psat 1.85 Mg/m³ H Psat = 2.0 Mg/m³ Psat = 1.9 Mg/m³arrow_forwardQuestion: A Blasius Exact Solution Equation For A Laminar Flat-Plate Boundary Layer Problem Which... A Blasius exact solution equation for a laminar flat-plate boundary layer problem which derived from Navier-Stoke equations, could be written as, ff"-2f"'=0 where f = f(n), =d'fm), dn? d'f(n). df (N) =- ,and f'=- dn' dn U is mainstream fluid velocity and u is fluid velocity in boundary layer. With suitable boundary conditions, the above equation had been solved by 4th-order Runge-Kutta numerical integration and the result is tabulated in Table Qla. TABLE Qla f'=w/U f" 7 = y, VX 0.000 0.000 0.332 0.323 0.267 1 0.166 0.330 0.630 0.846 0.956 0.992 0.998 0.650 1.397 2.310 3.283 0.161 0.064 3 4 0.016 0.002 6 7 4.280 0.001 5.279 6.280 0.999 1.000 0.000 Show that : CoRe , = 1.27 %3Darrow_forward
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