EBK PHYSICS FOR SCIENTISTS AND ENGINEER
6th Edition
ISBN: 9781319321710
Author: Mosca
Publisher: VST
expand_more
expand_more
format_list_bulleted
Videos
Question
Chapter 7, Problem 77P
To determine
The energy released during the reaction.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
Determine the amount of energy required for the U-238 to dissociate completely into its
consistent protons and neutrons. Assume that the mass of the U-238 is 238.05 u, the mass
of proton is 1.00727 u, and the mass of neutron is 1.00867 u.
Answer Choices:
а. 1854 MeV
b. 1756 MeV
с. 1645 MeV
d. 1453 MeV
a) Add the missing particles required to satisfy our laws of physics.
p = uud, n = ddu, л¹ = ud, π = ud, лº = uu or dd.
T → e +
n→ p+
T° → e+v
p+n→p+p+p+
b) For reactions (1) and (4) in part a), can the initial particles be at rest? Why/why not?
The carbon isotope 14C is used for carbon dating of objects. A 14C nucleus can change into a different kind of element, a neighbor on the periodic table with lower mass, by emitting a beta particle – an electron or positron – plus a neutrino or an anti-neutrino. Consider the scenario where 14C ( mass of 2.34 x 10 -26) decays by emitting an electron and anti neutrino. The electron has a mass of 9.11x 10-31 kg and a speed of 5.5 x107 m/s. While the anti neutrino has a momentum of 8.5x10-24 kg-m/s. If the electron and anti neutrino are emitted at right angles from each other, calculate the recoil speed of the nucleus.
Chapter 7 Solutions
EBK PHYSICS FOR SCIENTISTS AND ENGINEER
Ch. 7 - Prob. 1PCh. 7 - Prob. 2PCh. 7 - Prob. 3PCh. 7 - Prob. 4PCh. 7 - Prob. 5PCh. 7 - Prob. 6PCh. 7 - Prob. 7PCh. 7 - Prob. 8PCh. 7 - Prob. 9PCh. 7 - Prob. 10P
Ch. 7 - Prob. 11PCh. 7 - Prob. 12PCh. 7 - Prob. 13PCh. 7 - Prob. 14PCh. 7 - Prob. 15PCh. 7 - Prob. 16PCh. 7 - Prob. 17PCh. 7 - Prob. 18PCh. 7 - Prob. 19PCh. 7 - Prob. 20PCh. 7 - Prob. 21PCh. 7 - Prob. 22PCh. 7 - Prob. 23PCh. 7 - Prob. 24PCh. 7 - Prob. 25PCh. 7 - Prob. 26PCh. 7 - Prob. 27PCh. 7 - Prob. 28PCh. 7 - Prob. 29PCh. 7 - Prob. 30PCh. 7 - Prob. 31PCh. 7 - Prob. 32PCh. 7 - Prob. 33PCh. 7 - Prob. 34PCh. 7 - Prob. 35PCh. 7 - Prob. 36PCh. 7 - Prob. 37PCh. 7 - Prob. 38PCh. 7 - Prob. 39PCh. 7 - Prob. 40PCh. 7 - Prob. 41PCh. 7 - Prob. 42PCh. 7 - Prob. 43PCh. 7 - Prob. 44PCh. 7 - Prob. 45PCh. 7 - Prob. 46PCh. 7 - Prob. 47PCh. 7 - Prob. 48PCh. 7 - Prob. 49PCh. 7 - Prob. 50PCh. 7 - Prob. 51PCh. 7 - Prob. 52PCh. 7 - Prob. 53PCh. 7 - Prob. 54PCh. 7 - Prob. 55PCh. 7 - Prob. 56PCh. 7 - Prob. 57PCh. 7 - Prob. 58PCh. 7 - Prob. 59PCh. 7 - Prob. 60PCh. 7 - Prob. 61PCh. 7 - Prob. 62PCh. 7 - Prob. 63PCh. 7 - Prob. 64PCh. 7 - Prob. 65PCh. 7 - Prob. 66PCh. 7 - Prob. 67PCh. 7 - Prob. 68PCh. 7 - Prob. 69PCh. 7 - Prob. 70PCh. 7 - Prob. 71PCh. 7 - Prob. 72PCh. 7 - Prob. 73PCh. 7 - Prob. 74PCh. 7 - Prob. 75PCh. 7 - Prob. 76PCh. 7 - Prob. 77PCh. 7 - Prob. 78PCh. 7 - Prob. 79PCh. 7 - Prob. 80PCh. 7 - Prob. 81PCh. 7 - Prob. 82PCh. 7 - Prob. 83PCh. 7 - Prob. 84PCh. 7 - Prob. 85PCh. 7 - Prob. 86PCh. 7 - Prob. 87PCh. 7 - Prob. 88PCh. 7 - Prob. 89PCh. 7 - Prob. 90PCh. 7 - Prob. 91PCh. 7 - Prob. 92PCh. 7 - Prob. 93PCh. 7 - Prob. 94PCh. 7 - Prob. 95PCh. 7 - Prob. 96PCh. 7 - Prob. 97PCh. 7 - Prob. 98PCh. 7 - Prob. 99PCh. 7 - Prob. 100PCh. 7 - Prob. 101PCh. 7 - Prob. 102PCh. 7 - Prob. 103PCh. 7 - Prob. 104PCh. 7 - Prob. 105PCh. 7 - Prob. 106P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- You have five identical apples and six identical pears. The mass of an apple is 100 g and the mass of a pear is 101 g. You put all the fruit in a bag and place the bag on a scale. The scale reads 1100 g. Calculate the binding energy of the apple - pear system, in joules. Ignore the mass of the bag. Write your answer as E x 1014 J and type in just the value of E.arrow_forwardA 212^Bi (bismuth) nucleus undergoes alpha decay, resulting in a 208^Tl (thallium) nucleus and a 4He (helium) nucleus as per the following reaction: 212^Bi →208^Tl + 4^He The masses of each nucleus is listed in the table below. Given that the bismuth atom was at rest before the reaction, if the resulting thallium nucleus is traveling 3.3 × 105 m/s, how fast is the helium nucleus traveling?arrow_forwardwhere 1 eV = 1.602 × 10-19 J. Express the neutron’s kinetic energy in electron volts. b) In nuclear physics, it is convenient to express the energy of particles in electron volts (eV), 2) A neutron with a mass of 1.7 × 10-27 kg passes between two points in a detector 6 m apart in a time interval of 1.8 x 10-4 s. In the tendon at this pon a) Find the kinetic energy of the neutron in joulesarrow_forward
- Given the masses of various atomic particles mp = 1.0072 u, mn = 1.0087 u, me = 0.000548 u, mv[bar] = 0, md = 2.0141 u, where p ≡ proton, n ≡ neutron, e ≡ electron, v [bar] ≡ antineutrino and d ≡ deuteron. Which of the following processes is allowed by momentum and energy conservation? 1) n + n deuterium atom (electron bound to the nucleus) 2) e+ + e– → γ 3) p → n + e+ + v [bar] 4) n + p → d + γarrow_forwardIn the analysis of a nuclear reaction, scientists identify the rest masses of all reactants and products. By applying the equation E = mc, what property of the reaction can be calculated? O the kinetic energy of each component O the half-life of each component O the reaction energy O the speed of the reaction inish Cancel here to searcharrow_forwardWe have the following nuclear reaction, 73Li + p −→ 74Be + n the neutrons are ejected at an angle of 90° relative to the original direction of the proton beam. The kinetic energy of neutrons is 1.94 MeV. (a) Calculate the Q of the nuclear reactionarrow_forward
- The Sun generates energy by p-p proton-proton chain nuclear fusion. The second step of p-p chain is: 2H + 1H → 3He. The particle masses are 2.0141 u, 1.0078 u, 3.0160 u, for 2H, 1H, 3He, respectively. This step produces _____ MeV of energy.arrow_forwardElectron capture is a variant on beta-radiation. The lightest nucleus to decay by electron capture is 7Be -- beryllium-7. The daughter nucleus is 7Li -- lithium-7. The electron is transformed into a massless particle (a neutrino): e − + 7 B e + ⟶ 7 L i + ν The initial electron is bound in the atom, so the beryllium mass includes the electron. In fact, since the electron starts bound in the atom, a more-accurate statement of the nuclear reaction is probably: 7 B e ⟶ 7 L i + ν The masses are beryllium: 7.016929 u, and lithium: 7.016003 u, and refer to the neutral atom as a whole. (Use uc and uc2 as your momentum and energy units -- but carry them along in your calculation.) The initial beryllium atom is stationary. Calculate the speed of the final lithium nucleus in km/s. (all the energy released goes into the lighter particle. c = 300,000 km/s)arrow_forwardElectron capture is a variant on beta-radiation. The lightest nucleus to decay by electron capture is 7Be -- beryllium-7. The daughter nucleus is 7Li -- lithium-7. The electron is transformed into a massless particle (a neutrino): e − + 7 B e + ⟶ 7 L i + ν The initial electron is bound in the atom, so the beryllium mass includes the electron. In fact, since the electron starts bound in the atom, a more-accurate statement of the nuclear reaction is probably: 7 B e ⟶ 7 L i + ν The masses are beryllium: 7.016929 u, and lithium: 7.016003 u, and refer to the neutral atom as a whole. (Use uc and uc2 as your momentum and energy units -- but carry them along in your calculation.) The initial beryllium atom is stationary. Calculate the speed of the final lithium nucleus in km/s. (You will make life much easier for yourself if you recognize that practically all the energy released goes into the lighter particle. c = 300,000 km/s)arrow_forward
- Plz helparrow_forwardThe nuclear reaction that powers the radioisotope thermoelectric generator is 2382Pu → 23U + He. The atomic masses of plutonium-238 and uranium-234 are 238.049554 amu and 234.040946 amu, respectively. The mass of an alpha particle is 4.001506 amu. How much energy in kJ is released when 1.00 g of plutonium-238 decays to uranium-234?arrow_forwardNuclear Fusion Reaction In a human-scale model of a nuclear fusion reaction, two "deuterons" smash together head-on. Each has a mass of 2.0147kg and is moving at speed vd. The result is a "Helium-3 nucleus" (mass 3.0160kg) and a separate "neutron" (mass 1.0090kg пс ). Amazingly, this reaction produces a positive Wn of 3.96 × 10 14 J -- by converting mass into kinetic energy as predicted by Einstein's E = mc². The "neutron" moves with a speed of un after the reaction. E 4 Vd 1.63×107 m S Type your answer... + D D 3Не N. Proton Neutron http://fusion.srubar.net Un ×107: m S &arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage Learning
Physics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Physics for Scientists and Engineers: Foundations...
Physics
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Cengage Learning
Physics for Scientists and Engineers with Modern ...
Physics
ISBN:9781337553292
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Time Dilation - Einstein's Theory Of Relativity Explained!; Author: Science ABC;https://www.youtube.com/watch?v=yuD34tEpRFw;License: Standard YouTube License, CC-BY