Introduction to General, Organic and Biochemistry
Introduction to General, Organic and Biochemistry
11th Edition
ISBN: 9781285869759
Author: Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher: Cengage Learning
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Chapter 7, Problem 7.76P
Interpretation Introduction

Interpretation:

The equilibrium constant for the given reaction should be calculated.

Concept Introduction:

The given equilibrium reaction representing the conversion of glucose-1-phosphate to glucose-6-phosphate,

Glucose1phosphate◰  Glucose6phosphate

Equilibrium constant, K for this reaction can be determined using the equilibrium molar concentrations of glucose-1-phosphate and glucose-6-phosphate as below,

K=[Glucose-6-phosphate][Glucose-1-phosphate].

Expert Solution & Answer
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Answer to Problem 7.76P

The equilibrium constant for the given equilibrium is 24.

Explanation of Solution

The given equilibrium reaction representing the conversion of glucose-1-phosphate to glucose-6-phosphate:

Glucose1phosphate◰  Glucose6phosphate

Initial concentration of glucose-1-phosphate is 0.10 M.

Equilibrium concentration of glucose-6-phosphate is 9.6×102M

Setting up an ICE table for the equilibrium,

Glucose1phosphate◰  Glucose6phosphateInitial(M)0.100Change(M)X+XEquilibrium(M)(0.10X)X

K=X(0.10X)

[Glucose-6-phosphate] = X=9.6×102M[Glucose-1-phosphate] = (0.10X)=(0.109.6×102)=0.004M

K=(9.6×102)(0.004)

  = 24.

Conclusion

Therefore, the equilibrium constant for the given equilibrium will be 24.

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Chapter 7 Solutions

Introduction to General, Organic and Biochemistry

Ch. 7 - 7-11 Consider the following reaction: Suppose we...Ch. 7 - 7-12 Two kinds of gas molecules are reacted at a...Ch. 7 - 7-13 Why are reactions between ions in aqueous...Ch. 7 - Prob. 7.14PCh. 7 - 7-15 A certain reaction is exothermic by 9...Ch. 7 - 7-16 A quart of milk quickly spoils if left at...Ch. 7 - 7-17 If a certain reaction takes 16 h to go to...Ch. 7 - Prob. 7.18PCh. 7 - Prob. 7.19PCh. 7 - Prob. 7.20PCh. 7 - Prob. 7.21PCh. 7 - 7-22 If you add a piece of marble, CaCO3 to a 6 M...Ch. 7 - Prob. 7.23PCh. 7 - Prob. 7.24PCh. 7 - Prob. 7.25PCh. 7 - 7-26 Write the chemical equations corresponding to...Ch. 7 - Prob. 7.27PCh. 7 - 7-28 When the following reaction reached...Ch. 7 - 7-29 The following reaction was allowed to reach...Ch. 7 - Prob. 7.30PCh. 7 - 7-31 Here are equilibrium constants for several...Ch. 7 - 7-32 A particular reaction has an equilibrium...Ch. 7 - Prob. 7.33PCh. 7 - Prob. 7.34PCh. 7 - 7-35 A reaction has a high rate constant but a...Ch. 7 - 7-36 Complete the following table showing the...Ch. 7 - Prob. 7.37PCh. 7 - Prob. 7.38PCh. 7 - Prob. 7.39PCh. 7 - 7-40 Is there any change in conditions that change...Ch. 7 - 7-41 The equilibrium constant at 1127°C for the...Ch. 7 - Prob. 7.42PCh. 7 - 7-43 (Chemical Connections 7A and 7B) Why is a...Ch. 7 - Prob. 7.44PCh. 7 - 7-45 (Chemical Connections 7C) A painkiller—for...Ch. 7 - 7-46 (Chemical Connections 7D) What reaction takes...Ch. 7 - Prob. 7.47PCh. 7 - Prob. 7.48PCh. 7 - Prob. 7.49PCh. 7 - 7-50 Draw an energy diagram for an exothermic...Ch. 7 - Prob. 7.51PCh. 7 - Prob. 7.52PCh. 7 - Prob. 7.53PCh. 7 - Prob. 7.54PCh. 7 - Prob. 7.55PCh. 7 - Prob. 7.56PCh. 7 - 7-57 Write the reaction to which the following...Ch. 7 - Prob. 7.58PCh. 7 - Prob. 7.59PCh. 7 - Prob. 7.60PCh. 7 - Prob. 7.61PCh. 7 - Prob. 7.62PCh. 7 - Prob. 7.63PCh. 7 - 7-64 As we shall see in Chapter 20, there are two...Ch. 7 - Prob. 7.65PCh. 7 - Prob. 7.66PCh. 7 - Prob. 7.67PCh. 7 - Prob. 7.68PCh. 7 - 7-69 Pure carbon exists is several forms, two of...Ch. 7 - Prob. 7.70PCh. 7 - 7-71 You have a beaker that contains solid silver...Ch. 7 - Prob. 7.72PCh. 7 - Prob. 7.73PCh. 7 - Prob. 7.74PCh. 7 - Prob. 7.75PCh. 7 - Prob. 7.76PCh. 7 - Prob. 7.77PCh. 7 - Prob. 7.78PCh. 7 - Prob. 7.79PCh. 7 - Prob. 7.80PCh. 7 - Prob. 7.81PCh. 7 - 7-82 An equilibrium mixture of O2, SO2, and SO3...Ch. 7 - Prob. 7.83PCh. 7 - Prob. 7.84P
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