Principles of General Organic & Biological Chemistry
2nd Edition
ISBN: 9780077633721
Author: Janice Smith
Publisher: Mcgraw-hill Higher Education (us)
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Question
Chapter 7, Problem 7.64AP
(a)
Interpretation Introduction
Interpretation:
The concentration in weight/volume percent of Lithium chloride has to be calculated.
Concept Introduction:
Weight/volume percent: Weight/volume percent is defined as the concentration expressed in terms of grams of solute dissolved in volume of solution. Weight/volume percent is given as,
(b)
Interpretation Introduction
Interpretation:
The concentration in weight/volume percent of sodium nitrate has to be calculated.
Concept Introduction:
Refer to part (a).
(c)
Interpretation Introduction
Interpretation:
The concentration in weight/volume percent of sodium hydroxide has to be calculated.
Concept Introduction:
Refer to part (a).
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Students have asked these similar questions
A 0.10 M solution of acetic acid (CH3COOH, Ka = 1.8 x 10^-5) is titrated with a 0.0250 M solution of magnesium hydroxide (Mg(OH)2). If 10.0 mL of the acid solution is titrated with 20.0 mL of the base solution, what is the pH of the resulting solution?
For the decomposition reaction of N2O5(g): 2 N2O5(g) → 4 NO2(g) + O2(g), the following mechanism has been proposed:
N2O5 NO2 + NO3 (K1) | NO2 + NO3 → N2O5 (k-1) | NO2 + NO3 NO2 + O2 + NO (k2) | NO + N2O51 NO2 + NO2 + NO2 (K3)
→
Give the expression for the acceptable rate.
→
→
(A).
d[N205]
dt
==
2k,k₂[N₂O₂]
k₁+k₁₂
(B).
d[N2O5]
=-k₁[N₂O] + k₁[NO₂] [NO3] - k₂[NO₂]³
dt
(C).
d[N2O5]
=-k₁[N₂O] + k [NO] - k₂[NO] [NO]
d[N2O5]
(D).
=
dt
= -k₁[N2O5] - k¸[NO][N₂05]
dt
Do not apply the calculations, based on the approximation of the stationary state, to make them perform correctly. Basta discard
the 3 responses that you encounter that are obviously erroneous if you apply the formula to determine the speed of a reaction.
For the decomposition reaction of N2O5(g): 2 N2O5(g) → 4 NO2(g) + O2(g), the following mechanism has been proposed:
N2O5 NO2 + NO3 (K1) | NO2 + NO3 → N2O5 (k-1) | NO2 + NO3 NO2 + O2 + NO (k2) | NO + N2O51 NO2 + NO2 + NO2 (K3)
→
Give the expression for the acceptable rate.
→
→
(A).
d[N205]
dt
==
2k,k₂[N₂O₂]
k₁+k₁₂
(B).
d[N2O5]
=-k₁[N₂O] + k₁[NO₂] [NO3] - k₂[NO₂]³
dt
(C).
d[N2O5]
=-k₁[N₂O] + k [NO] - k₂[NO] [NO]
d[N2O5]
(D).
=
dt
= -k₁[N2O5] - k¸[NO][N₂05]
dt
Do not apply the calculations, based on the approximation of the stationary state, to make them perform correctly. Basta discard
the 3 responses that you encounter that are obviously erroneous if you apply the formula to determine the speed of a reaction.
Chapter 7 Solutions
Principles of General Organic & Biological Chemistry
Ch. 7.1 - Classify each substance as a heterogeneous...Ch. 7.1 - Classify each product as a solution, colloid, or...Ch. 7.2 - Consider the following diagrams for an aqueous...Ch. 7.2 - Prob. 7.4PCh. 7.2 - Prob. 7.5PCh. 7.2 - Prob. 7.6PCh. 7.2 - Prob. 7.7PCh. 7.2 - If a solution contains 125 mEq of Na+ per liter,...Ch. 7.3 - Prob. 7.9PCh. 7.3 - Prob. 7.10P
Ch. 7.4 - Why does a soft drink become flat faster when it...Ch. 7.4 - Predict the effect each change has on the...Ch. 7.5 - Prob. 7.13PCh. 7.5 - Prob. 7.14PCh. 7.5 - Prob. 7.15PCh. 7.5 - A drink sold in a health food store contains 0.50%...Ch. 7.5 - Prob. 7.17PCh. 7.5 - Prob. 7.18PCh. 7.5 - Prob. 7.19PCh. 7.6 - Prob. 7.20PCh. 7.6 - Prob. 7.21PCh. 7.6 - Prob. 7.22PCh. 7.6 - Prob. 7.23PCh. 7.6 - Prob. 7.24PCh. 7.7 - Prob. 7.25PCh. 7.7 - Prob. 7.26PCh. 7.7 - Prob. 7.27PCh. 7.8 - Which solution in each pair exerts the greater...Ch. 7.8 - Describe the process that occurs when a 1.0 M NaCl...Ch. 7.8 - Prob. 7.30PCh. 7 - Prob. 7.31UKCCh. 7 - Prob. 7.32UKCCh. 7 - Prob. 7.33UKCCh. 7 - Prob. 7.34UKCCh. 7 - Prob. 7.35UKCCh. 7 - Prob. 7.36UKCCh. 7 - Prob. 7.37UKCCh. 7 - Prob. 7.38UKCCh. 7 - Prob. 7.41UKCCh. 7 - Prob. 7.42UKCCh. 7 - Prob. 7.43APCh. 7 - Prob. 7.44APCh. 7 - Prob. 7.45APCh. 7 - Prob. 7.46APCh. 7 - Prob. 7.47APCh. 7 - Prob. 7.48APCh. 7 - Prob. 7.49APCh. 7 - Prob. 7.50APCh. 7 - Prob. 7.51APCh. 7 - Prob. 7.52APCh. 7 - Prob. 7.53APCh. 7 - Prob. 7.54APCh. 7 - Prob. 7.55APCh. 7 - Prob. 7.56APCh. 7 - Prob. 7.57APCh. 7 - Prob. 7.58APCh. 7 - Prob. 7.59APCh. 7 - Prob. 7.60APCh. 7 - Prob. 7.61APCh. 7 - Prob. 7.62APCh. 7 - Prob. 7.63APCh. 7 - Prob. 7.64APCh. 7 - Prob. 7.65APCh. 7 - Prob. 7.66APCh. 7 - Prob. 7.67APCh. 7 - Prob. 7.68APCh. 7 - Prob. 7.69APCh. 7 - Prob. 7.70APCh. 7 - Prob. 7.71APCh. 7 - Prob. 7.72APCh. 7 - Prob. 7.73APCh. 7 - Prob. 7.74APCh. 7 - Prob. 7.75APCh. 7 - Prob. 7.76APCh. 7 - Prob. 7.77APCh. 7 - Prob. 7.78APCh. 7 - Prob. 7.79APCh. 7 - Prob. 7.80APCh. 7 - Prob. 7.81APCh. 7 - Prob. 7.82APCh. 7 - Prob. 7.83APCh. 7 - Prob. 7.84APCh. 7 - Prob. 7.85APCh. 7 - Prob. 7.86APCh. 7 - Prob. 7.87APCh. 7 - Prob. 7.88APCh. 7 - Prob. 7.89APCh. 7 - Prob. 7.90APCh. 7 - If the concentration of glucose in the blood is 90...Ch. 7 - Prob. 7.92APCh. 7 - Prob. 7.93APCh. 7 - Prob. 7.94APCh. 7 - Prob. 7.95APCh. 7 - Prob. 7.96APCh. 7 - Prob. 7.97APCh. 7 - Prob. 7.98APCh. 7 - Prob. 7.99APCh. 7 - Prob. 7.100APCh. 7 - Prob. 7.101APCh. 7 - Prob. 7.102APCh. 7 - Prob. 7.103CPCh. 7 - Prob. 7.104CP
Knowledge Booster
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