Co a S b O c ⋅ X H 2 O is the general formula of a certain hydrate. When 43.0 g of the compound is heated to drive off the water, 26.1 g of anhydrous compound is left. Further analysis shows that the percentage composition by mass of the anhydrate is 42.4 % Co , 23.0 % S , and 34.6 % O . Find the empirical formula of (a) the anhydrous compound and (b) the hydrate. ( Hint: treat the anhydrous compound and water just as you treated elements in calculating X in the formula of the hydrate.)
Co a S b O c ⋅ X H 2 O is the general formula of a certain hydrate. When 43.0 g of the compound is heated to drive off the water, 26.1 g of anhydrous compound is left. Further analysis shows that the percentage composition by mass of the anhydrate is 42.4 % Co , 23.0 % S , and 34.6 % O . Find the empirical formula of (a) the anhydrous compound and (b) the hydrate. ( Hint: treat the anhydrous compound and water just as you treated elements in calculating X in the formula of the hydrate.)
Solution Summary: The author explains how the empirical formula of anhydrous compounds is to be predicted.
Co
a
S
b
O
c
⋅
X
H
2
O
is the general formula of a certain hydrate. When
43.0
g
of the compound is heated to drive off the water,
26.1
g
of anhydrous compound is left. Further analysis shows that the percentage composition by mass of the anhydrate is
42.4
%
Co
,
23.0
%
S
, and
34.6
%
O
. Find the empirical formula of (a) the anhydrous compound and (b) the hydrate. (Hint: treat the anhydrous compound and water just as you treated elements in calculating
X
in the formula of the hydrate.)
Calculate the differences between energy levels in J, Einstein's coefficients of estimated absorption and spontaneous emission and life time media for typical electronic transmissions (vnm = 1015 s-1) and vibrations (vnm = 1013 s-1) . Assume that the dipolar transition moments for these transactions are in the order of 1 D.Data: 1D = 3.33564x10-30 C m; epsilon0 = 8.85419x10-12 C2m-1J-1
Don't used Ai solution
Please correct answer and don't used hand raiting
Chapter 7 Solutions
Introductory Chemistry: An Active Learning Approach
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