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Concept explainers
(a)
Interpretation:
The following table is to be completed by assuming the gas at a constant temperature.
5.0L | 310K | ? | 250K |
Concept Introduction:
According to Charles's law, the volume of gas is directly proportional to the temperature of the gas in K at constant pressure. This relation is represented as
Or,
![Check Mark](/static/check-mark.png)
Answer to Problem 7.55P
5.0L | 310K | 4.0L | 250K |
Explanation of Solution
According to Charles's law, the volume of gas is directly proportional to the Kelvin temperature of the gas at constant pressure. This relation is represented as
Or,
Given that
Initial volume, V1 = 5.0L
Initial temperature, T1 = 310K
Final temperature, T2 = 250K
Put the above values in equ (1)
The final volume of gas that is V2 = 4.0L
Thus,
5.0L | 310K | 4.0L | 250K |
(b)
Interpretation:
The following table is to be completed by assuming the gas at a constant temperature.
150mL | 45K | ? |
Concept Introduction:
According to Charles's law, the volume of gas is directly proportional to the temperature of the gas in K at constant pressure. This relation is represented as
Or,
![Check Mark](/static/check-mark.png)
Answer to Problem 7.55P
150mL | 45K | 1.1L |
Explanation of Solution
According to Charles's law, the volume of gas is directly proportional to the Kelvin temperature of the gas at constant pressure. This relation is represented as
Or,
Given that
Initial volume, V1 = 150mL
Initial temperature, T1 = 45K
Final temperature, T2 =
Or,
Put the above values in equation (1),
Or,
The final volume of gas that is V2 = 1.1 L
150mL | 45K | 1.1L |
(c)
Interpretation:
The following table is to be completed by assuming the gas at a constant temperature.
60.0L | 180L | ? |
Concept Introduction:
According to Charles's law, the volume of gas is directly proportional to the temperature of the gas in K at constant pressure. This relation is represented as
Or,
![Check Mark](/static/check-mark.png)
Answer to Problem 7.55P
60.0L | 180L | 820K |
Explanation of Solution
According to Charles's law, the volume of gas is directly proportional to the Kelvin temperature of the gas at constant pressure. This relation is represented as
Or,
Given that −
Initial volume, V1 = 60L
Final temperature, T2 =
Final volume, V2 = 180L
Or,
Put the above values in equation (2),
The final volume of gas that is T2 = 820K
The final table is −
60.0L | 180L | 820K |
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Chapter 7 Solutions
EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM
- Q1: For each molecule, assign each stereocenter as R or S. Circle the meso compounds. Label each compound as chiral or achiral. OH HO CI Br H CI CI Br CI CI Xf x f g Br D OH Br Br H₂N R. IN Ill I -N S OMe D II H CO₂H 1/111 DuckDuckGarrow_forwardThese are synthesis questions. You need to show how the starting material can be converted into the product(s) shown. You may use any reactions we have learned. Show all the reagents you need. Show each molecule synthesized along the way and be sure to pay attention to the regiochemistry and stereochemistry preferences for each reaction. If a racemic molecule is made along the way, you need to draw both enantiomers and label the mixture as "racemic". All of the carbon atoms of the products must come from the starting material! ? H Harrow_forwardQ5: Draw every stereoisomer for 1-bromo-2-chloro-1,2-difluorocyclopentane. Clearly show stereochemistry by drawing the wedge-and-dashed bonds. Describe the relationship between each pair of the stereoisomers you have drawn.arrow_forward
- Classify each pair of molecules according to whether or not they can participate in hydrogen bonding with one another. Participate in hydrogen bonding CH3COCH3 and CH3COCH2CH3 H2O and (CH3CH2)2CO CH3COCH3 and CH₂ CHO Answer Bank Do not participate in hydrogen bonding CH3CH2OH and HCHO CH3COCH2CH3 and CH3OHarrow_forwardNonearrow_forwardQ4: Comparing (3S,4S)-3,4-dimethylhexane and (3R,4S)-3,4-dimethylhexane, which one is optically active? Briefly explain.arrow_forward
- Nonearrow_forwardNonearrow_forwardGiven the standard enthalpies of formation for the following substances, determine the reaction enthalpy for the following reaction. 4A (g) + 2B (g) → 2C (g) + 7D (g) AHrxn =?kJ Substance AH in kJ/mol A (g) - 20.42 B (g) + 32.18 C (g) - 72.51 D (g) - 17.87arrow_forward
- Determine ASran for Zn(s) + 2HCl(aq) = ZnCl2(aq) + H2(aq) given the following information: Standard Entropy Values of Various Substance Substance So (J/mol • K) 60.9 Zn(s) HCl(aq) 56.5 130.58 H2(g) Zn2+(aq) -106.5 55.10 CI (aq)arrow_forward3) Catalytic hydrogenation of the compound below produced the expected product. However, a byproduct with molecular formula C10H12O is also formed in small quantities. What is the by product?arrow_forwardWhat is the ΔHorxn of the reaction? NaOH(aq) + HCl(aq) → H2O(l) + NaCl(aq) ΔHorxn 1= ________ kJ/molarrow_forward
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