
Concept explainers
(a)
Interpretation:
The following table is to be completed by assuming the gas at a constant temperature.
5.0L | 310K | ? | 250K |
Concept Introduction:
According to Charles's law, the volume of gas is directly proportional to the temperature of the gas in K at constant pressure. This relation is represented as
Or,

Answer to Problem 7.55P
5.0L | 310K | 4.0L | 250K |
Explanation of Solution
According to Charles's law, the volume of gas is directly proportional to the Kelvin temperature of the gas at constant pressure. This relation is represented as
Or,
Given that
Initial volume, V1 = 5.0L
Initial temperature, T1 = 310K
Final temperature, T2 = 250K
Put the above values in equ (1)
The final volume of gas that is V2 = 4.0L
Thus,
5.0L | 310K | 4.0L | 250K |
(b)
Interpretation:
The following table is to be completed by assuming the gas at a constant temperature.
150mL | 45K | ? |
Concept Introduction:
According to Charles's law, the volume of gas is directly proportional to the temperature of the gas in K at constant pressure. This relation is represented as
Or,

Answer to Problem 7.55P
150mL | 45K | 1.1L |
Explanation of Solution
According to Charles's law, the volume of gas is directly proportional to the Kelvin temperature of the gas at constant pressure. This relation is represented as
Or,
Given that
Initial volume, V1 = 150mL
Initial temperature, T1 = 45K
Final temperature, T2 =
Or,
Put the above values in equation (1),
Or,
The final volume of gas that is V2 = 1.1 L
150mL | 45K | 1.1L |
(c)
Interpretation:
The following table is to be completed by assuming the gas at a constant temperature.
60.0L | 180L | ? |
Concept Introduction:
According to Charles's law, the volume of gas is directly proportional to the temperature of the gas in K at constant pressure. This relation is represented as
Or,

Answer to Problem 7.55P
60.0L | 180L | 820K |
Explanation of Solution
According to Charles's law, the volume of gas is directly proportional to the Kelvin temperature of the gas at constant pressure. This relation is represented as
Or,
Given that −
Initial volume, V1 = 60L
Final temperature, T2 =
Final volume, V2 = 180L
Or,
Put the above values in equation (2),
The final volume of gas that is T2 = 820K
The final table is −
60.0L | 180L | 820K |
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Chapter 7 Solutions
EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM
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