
Interpretation:
The possible values of l and ml for n = 3 quantum level should be identified using the concept of quantum numbers.
Concept Introduction:
Quantum numbers are explained for the distribution of electron density in an atom. They are derived from the mathematical solution of Schrodinger’s equation for the hydrogen atom. The types of quantum numbers are the principal quantum number (n), the
Principal Quantum Number (n)
The principal quantum number (n) assigns the size of the orbital and specifies the energy of an electron. If the value of n is larger, then the average distance of an electron in the orbital from the nucleus will be greater. Therefore the size of the orbital is large. The principal quantum numbers have the integral values of 1, 2, 3 and so forth and it corresponds to the quantum number in
Angular Momentum Quantum Number (l)
The angular momentum quantum number (l) explains the shape of the atomic orbital. The values of l are integers which depend on the value of the principal quantum number, n. For a given value of n, the possible values of l range are from 0 to n − 1. If n = 1, there is only one possible value of l (l=0). If n = 2, there are two values of l: 0 and 1. If n = 3, there are three values of l: 0, 1, and 2. The value of l is selected by the letters s, p, d, and f. If l = 0, we have an s orbital; if l = 1, we have a p orbital; if l = 2, we have a d orbital and finally if l = 3, we have a f orbital. A collection of orbitals with the same value of n is called a shell. One or more orbitals with the same n and l values are referred to a subshell (sublevel). The value of l also has a slight effect on the energy of the subshell; the energy of the subshell increases with l (s < p < d < f).
Magnetic Quantum Number (ml)
The magnetic quantum number (ml) explains the orientation of the orbital in space. The value of ml depends on the value of l in a subshell. This number divides the subshell into individual orbitals which hold the electrons. For a certain value of l, there are (2l + 1) integral values of ml which is explained as follows:
ml = ‒ l, ..., 0, ..., +l
If l = 0, there is only one possible value of ml: 0.
If l = 1, then there are three values of ml: −1, 0, and +1.
If l = 2, there are five values of ml, namely, −2, −1, 0, +1, and +2.
If l = 3, there are seven values of ml, namely, −3, −2, −1, 0, +1, +2, and +3, and so on.
The number of ml values indicates the number of orbitals in a subshell with a particular l value. Therefore, each ml value refers to a different orbital.
To find: Get the possible values of l and ml for n = 3 quantum level
Find the value of ‘l’ for n = 3

Want to see the full answer?
Check out a sample textbook solution
Chapter 7 Solutions
General Chemistry
- > Can the molecule on the right-hand side of this organic reaction be made in good yield from no more than two reactants, in one step, by moderately heating the reactants? esc ? A O O •If your answer is yes, then draw the reactant or reactants in the drawing area below. You can draw the reactants in any arrangement you like. • If your answer is no, check the box under the drawing area instead. olo 18 Ar Explanation Check BB Click and drag to start drawing a structure. 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center Accessibilityarrow_forwardName the structurearrow_forward> For each pair of substrates below, choose the one that will react faster in a substitution reaction, assuming that: 1. the rate of substitution doesn't depend on nucleophile concentration and 2. the products are a roughly 50/50 mixture of enantiomers. Substrate A Substrate B Faster Rate X CI (Choose one) (Choose one) CI Br Explanation Check Br (Choose one) C 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy A F10arrow_forward
- How to draw this mechanism for the foloowing reaction in the foto. thank youarrow_forwardPredict the major products of the following organic reaction: Some important notes: CN A? • Draw the major product, or products, of the reaction in the drawing area below. • If there aren't any products, because no reaction will take place, check the box below the drawing area instead. • Be sure to use wedge and dash bonds when necessary, for example to distinguish between major products that are enantiomers. No reaction. Explanation Check Click and drag to start drawing a structure. 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use Privacy Centerarrow_forwardDraw the major product of the following reaction. Do not draw inorganic byproducts. H3PO4 OHarrow_forward
- Predict the major products of this organic reaction: HBr (1 equiv) Δ ? Some important notes: • Draw the major product, or products, of this reaction in the drawing area below. • You can draw the products in any arrangement you like. • Pay careful attention to the reaction conditions, and only include the major products. • Be sure to use wedge and dash bonds when necessary, for example to distinguish between major products that are enantiomers. • Note that there is only 1 equivalent of HBr reactant, so you need not consider the case of multiple additions. Explanation Check X ©2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacyarrow_forwardFor the structure below, draw the resonance structure that is indicated by the curved arrow(s). Be sure to include formal charges. :ÖH Modify the second structure given to draw the new resonance structure. Include lone pairs and charges in your structure. Use the + and - tools to add/remove charges to an atom, and use the single bond tool to add/remove double bonds.arrow_forwardUsing the table of Reactants and Products provided in the Hints section, provide the major product (with the correct stereochemistry when applicable) for questions below by selecting the letter that corresponds to the exact chemical structures for the possible product. OH conc Hydrochloric acid 40°C Temp A/arrow_forward
- Using arrows to designate the flow of electrons, complete the reaction below and provide a detailed mechanism for the formation of the product OH conc Hydrochloric acid 40°C Temp All chemical structures should be hand drawn on a piece of paper Paragraph BI UAE +varrow_forwarddraw out the following structures plesearrow_forwardDraw everything on a piece of paper outlining the synthesis from acetaldehyde to 2 cyclopentene carboxaldehyde using carbon based reagants with 3 carbons or fewers. Here is the attached image.arrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY





