Chapter 7, Problem 7.104QP

Interpretation Introduction

Interpretation:

The numbers of photons are emitted by $\text{60W}$ tungsten light bulb which converts $15\%$ energy to visible light has to be calculated.

Concept Introduction:

The energy of each photon is given as

$\text{E}\text{=}\text{hν}$

h is the Planck’s constant ($\text{6}\text{.63}\text{×}{\text{10}}^{\text{-34}}\text{J}\text{.s}$ ) which relates energy and frequency.

$\text{ν}$ is the frequency.

E is the energy of light particle.

The mathematical equation of various characteristics of light wave is given as follows,

$\begin{array}{l}\text{ν}\text{= }\frac{\text{c}}{\text{λ }}\\ \\ \text{c = νλ}\end{array}$

C is the speed of light ($\text{3}{\text{.00 × 10}}^{\text{8}}\text{ m/s}$).

$\text{ν}$ is the frequency

$\text{λ}$ is wavelength.