ORGANIC CHEMISTRY SAPLING ACCESS + ETEX
6th Edition
ISBN: 9781319306977
Author: LOUDON
Publisher: INTER MAC
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Chapter 7, Problem 7.46AP
Interpretation Introduction
(a)
Interpretation:
The structure and stereochemistry of the expected products for the addition of
Concept introduction:
Stereochemistry is the study of the arrangement of the atoms and molecules in the space and its effects on the reactions.
The addition reactions on the
Interpretation Introduction
(b)
Interpretation:
The structure and stereochemistry of the expected products for the reaction of cyclopentene with
Concept introduction:
Stereochemistry is the study of the arrangement of the atoms and molecules in the space and its effects on the reactions.
The addition reactions on the alkenes are very common as there is electron density available on the alkene due to double bond electron-cloud.
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There are 48 pairs of students in the following table. Each pair has quantitatively determined the mass of taurine in a 250 mL can of the popular energy drink marketed as “Munster” using High Performance Liquid Chromatography (HPLC). The class results are presented below:
QUESTION: Summarise and report these results including an indication of measurement uncertainty.
In both calculation samples calculate if an outlier is present, max value, number of samples, mean, standard deviation, g (suspect), g (critical) and t (critical).
Mass of Taurine (mg)
Mass of Taurine (mg)
(Table continued)
152.01
152.23
151.87
151.45
154.11
152.64
152.98
153.24
152.88
151.45
153.49
152.48
150.68
152.33
151.52
153.63
152.48
151.68
153.17
153.40
153.77
153.67
152.34
153.16
152.57
153.02
152.86
151.50
151.23
152.57
152.72
151.54
146.47
152.38
152.44
152.54
152.53
152.54
151.32…
Indicate the rate expressions for reactions that have order 0, 1, and 2.
PROBLEMS
Q1) Label the following salts as either acidic, basic, or neutral
a) Fe(NOx)
c) AlBr
b) NH.CH COO
d) HCOON
(1/2 mark each)
e) Fes
f) NaBr
Q2) What is the pH of a 0.0750 M solution of sulphuric acid?
Chapter 7 Solutions
ORGANIC CHEMISTRY SAPLING ACCESS + ETEX
Ch. 7 - Prob. 7.1PCh. 7 - Prob. 7.2PCh. 7 - Prob. 7.3PCh. 7 - Prob. 7.4PCh. 7 - Prob. 7.5PCh. 7 - Prob. 7.6PCh. 7 - Prob. 7.7PCh. 7 - Prob. 7.8PCh. 7 - Prob. 7.9PCh. 7 - Prob. 7.10P
Ch. 7 - Prob. 7.11PCh. 7 - Prob. 7.12PCh. 7 - Prob. 7.13PCh. 7 - Prob. 7.14PCh. 7 - Prob. 7.15PCh. 7 - Prob. 7.16PCh. 7 - Prob. 7.17PCh. 7 - Prob. 7.18PCh. 7 - Prob. 7.19PCh. 7 - Prob. 7.20PCh. 7 - Prob. 7.21PCh. 7 - Prob. 7.22PCh. 7 - Prob. 7.23PCh. 7 - Prob. 7.24PCh. 7 - Prob. 7.25PCh. 7 - Prob. 7.26PCh. 7 - Prob. 7.27PCh. 7 - Prob. 7.28PCh. 7 - Prob. 7.29PCh. 7 - Prob. 7.30PCh. 7 - Prob. 7.31PCh. 7 - Prob. 7.32PCh. 7 - Prob. 7.33PCh. 7 - Prob. 7.34APCh. 7 - Prob. 7.35APCh. 7 - Prob. 7.36APCh. 7 - Prob. 7.37APCh. 7 - Prob. 7.38APCh. 7 - Prob. 7.39APCh. 7 - Prob. 7.40APCh. 7 - Prob. 7.41APCh. 7 - Prob. 7.42APCh. 7 - Prob. 7.43APCh. 7 - Prob. 7.44APCh. 7 - Prob. 7.45APCh. 7 - Prob. 7.46APCh. 7 - Prob. 7.47APCh. 7 - Prob. 7.48APCh. 7 - Prob. 7.49APCh. 7 - Prob. 7.50APCh. 7 - Prob. 7.51APCh. 7 - Prob. 7.52APCh. 7 - Prob. 7.53APCh. 7 - Prob. 7.54APCh. 7 - Prob. 7.55APCh. 7 - Prob. 7.56APCh. 7 - Prob. 7.57APCh. 7 - Prob. 7.58APCh. 7 - Prob. 7.59APCh. 7 - Prob. 7.60APCh. 7 - Prob. 7.61APCh. 7 - Prob. 7.62APCh. 7 - Prob. 7.63APCh. 7 - Prob. 7.64APCh. 7 - Prob. 7.65APCh. 7 - Prob. 7.66APCh. 7 - Prob. 7.67APCh. 7 - Prob. 7.68APCh. 7 - Prob. 7.69APCh. 7 - Prob. 7.70APCh. 7 - Prob. 7.71APCh. 7 - Prob. 7.72APCh. 7 - Prob. 7.73APCh. 7 - Prob. 7.74APCh. 7 - Prob. 7.75AP
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- 8. Draw all the resonance forms for each of the fling molecules or ions, and indicate the major contributor in each case, or if they are equivalent (45) (2) -PH2 سمة مدarrow_forwardA J то گای ه +0 Also calculate the amount of starting materials chlorobenzaldehyde and p-chloroacetophenone required to prepare 400 mg of the given chalcone product 1, 3-bis(4-chlorophenyl)prop-2-en-1-one molar mass ok 1,3-bis(4-Chlorophenyl) prop-2-en-1-one = 277.1591m01 number of moles= 0.400/277.15 = 0.00144 moles 2 x 0.00 144=0.00288 moves arams of acetophenone = 0.00144 X 120.16 = 0.1739 0.1739x2=0.3469 grams of benzaldehyde = 0.00144X106.12=0.1539 0.1539x2 = 0.3069 Starting materials: 0.3469 Ox acetophenone, 0.3069 of benzaldehyde 3arrow_forward1. Answer the questions about the following reaction: (a) Draw in the arrows that can be used make this reaction occur and draw in the product of substitution in this reaction. Be sure to include any relevant stereochemistry in the product structure. + SK F Br + (b) In which solvent would this reaction proceed the fastest (Circle one) Methanol Acetone (c) Imagine that you are working for a chemical company and it was your job to perform a similar reaction to the one above, with the exception of the S atom in this reaction being replaced by an O atom. During the reaction, you observe the formation of three separate molecules instead of the single molecule obtained above. What is the likeliest other products that are formed? Draw them in the box provided.arrow_forward
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