
Interpretation:
The number of large stress amplitude cycles that can be sustained before failure need sto be determined, if the material has a crack of the initial length of 0.010 mm and then subjected to calculating tensile structures of 25 and 125 MPa for 350,000 cycles.
Concept introduction:
Equation of strain fracture toughness of the material.
Material subjected to cycle string is given by,

Answer to Problem 7.38P
The cycles that sustained before failure are given by 13,560 cycles.
Explanation of Solution
Given Information:
Calculation:
Stress fracture toughness
Here,
Rearranging equation (1),
Therefore, critical crack length when 250 MPa stress is applied is given by 3.18mm
Let, a1 is the initial flaw size when material subjected to stress in cyclic testing.
Now, the number of cycles (N) is given to find out crack (a1)
Here,
Equation (2) becomes.
Hence the length of the crack
Now a number of cycles (N) for the crack length of
Here,
Under compression
Therefore equation (2) becomes
Required number of cycles
Hence by using strain fracture toughness of material equation and also a number of cycles equation, the number of cycles (N) before failure is
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Chapter 7 Solutions
Essentials of Materials Science and Engineering, SI Edition
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