Interpretation:
The molecular art that represents a solution of potassium iodide in water has to be identified. The reason has to be explained and conduction of electricity by the solution has to be predicted.
Concept Introduction:
A substance that conducts electricity in water is called as electrolyte and substance that does not conduct electricity in water is called as nonelectrolyte.
Strong electrolyte: An electrolyte that completely dissociates to form ions, when it dissolves in water is called as strong electrolyte.
Weak electrolyte: An electrolyte in which molecules (a small fraction) forms ions, when dissolves in water to give largely uncharged molecules is called as weak electrolyte.

Explanation of Solution
Potassium iodide is an ionic compound, hence separation of ions will takes place when they are dissolved in water.
Figure A represents the solution of potassium iodide in water because the ions of potassium and iodine are separated when potassium iodide is dissolved in water. Yes, the solution of potassium iodide in water conducts electricity due to the presence of ions. Hence, it is best molecular art representation of potassium iodide solution in water.
Figure B represents the molecule of potassium iodide (without being separated into ions). Hence, it cannot be correct representation.
Want to see more full solutions like this?
Chapter 7 Solutions
Connect 1-Semester Online Access for Principles of General, Organic & Biochemistry
- What is/are the product(s) of the following reaction? Select all that apply. * HI A B C OD OH A B OH D Carrow_forwardIn the image, the light blue sphere represents a mole of hydrogen atoms, the purple or teal spheres represent a mole of a conjugate base. A light blue sphere by itself is H+. Assuming there is 2.00 L of solution, answer the following: The Ka of the left & right solution is? The pH of the left & right solution is? The acid on the left & right is what kind of acid?arrow_forwardNonearrow_forward
- Nonearrow_forwardNonearrow_forwardWhat spectral features allow you to differentiate the product from the starting material? Use four separate paragraphs for each set of comparisons. You should have one paragraph each devoted to MS, HNMR, CNMR and IR. 2) For MS, the differing masses of molecular ions are a popular starting point. Including a unique fragmentation is important, too. 3) For HNMR, CNMR and IR state the peaks that are different and what makes them different (usually the presence or absence of certain groups). See if you can find two differences (in each set of IR, HNMR and CNMR spectra) due to the presence or absence of a functional group. Include peak locations. Alternatively, you can state a shift of a peak due to a change near a given functional group. Including peak locations for shifted peaks, as well as what these peaks are due to. Ideally, your focus should be on not just identifying the differences but explaining them in terms of functional group changes.arrow_forward
- Nonearrow_forwardNonearrow_forwardIn the solid state, oxalic acid occurs as a dihydrate with the formula H2C2O4 C+2H2O. Use this formula to calculate the formula weight of oxalic acid. Use the calculated formula weight and the number of moles (0.00504mol) of oxalic acid in each titrated unknown sample recorded in Table 6.4 to calculate the number of grams of pure oxalic acid dihydrate contained in each titrated unknown sample.arrow_forward
- Chemistry by OpenStax (2015-05-04)ChemistryISBN:9781938168390Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark BlaserPublisher:OpenStaxIntroductory Chemistry: A FoundationChemistryISBN:9781337399425Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage LearningIntroductory Chemistry: An Active Learning Approa...ChemistryISBN:9781305079250Author:Mark S. Cracolice, Ed PetersPublisher:Cengage Learning
- Chemistry for Engineering StudentsChemistryISBN:9781337398909Author:Lawrence S. Brown, Tom HolmePublisher:Cengage LearningWorld of Chemistry, 3rd editionChemistryISBN:9781133109655Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCostePublisher:Brooks / Cole / Cengage LearningChemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage Learning





