Calculate the concentration in % ( w / w ) of the following solutions. Assume water has a density of 1.00 g / mL . a. 20.0 g of salt is dissolved in 250. mL of water. b. 0.100 mol of solid glucose ( C 6 H 12 O 6 ) is dissolved in 100. mL of water. c. 120 g of solid is dissolved in 100. mL of water. d. 10.0 mL of ethyl alcohol (density = 0.789 g / mL ) is mixed with 10.0 mL of water.

Question

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Answer 1

Textbook Question

Chapter 7, Problem 7.30E

Calculate the concentration in % ( w / w ) of the following solutions. Assume water has a density of 1.00 g / mL .

a. 20.0 g of salt is dissolved in 250. mL of water.

b. 0.100 mol of solid glucose ( C 6 H 12 O 6 ) is dissolved in 100. mL of water.

c. 120 g of solid is dissolved in 100. mL of water.

d. 10.0 mL of ethyl alcohol (density = 0.789 g / mL ) is mixed with 10.0 mL of water.

Expert Solution

Interpretation Introduction

(a)

Interpretation:

The concentration in %(w/w) of 20.0 g of salt dissolved in 250. mL of water is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Answer to Problem 7.30E

The concentration in %(w/w) of 20.0 g of salt dissolved in 250. mL of water is 7.41 %w/w.

Explanation of Solution

The formula to calculate concentration in %(w/w) is given below as,

%(w/w)=Solute MassSolution Mass×100

The density of water is 1.00 g/mL. Thus, the mass of water is equal to its volume. Hence in this case the mass of solution is taken as 250. g. Substitute the value of mass of salt and mass of solution in the above equation as follows.

%(w/w)=Mass of saltSolution Mass×100=20.0 g(250+20) g×100=20 g270 g×100=7.41 %w/w

Conclusion

The concentration in %(w/w) of 20.0 g of salt dissolved in 250. mL of water is 7.41 %w/w.

Expert Solution

Interpretation Introduction

(b)

Interpretation:

The concentration in %(w/w) of 0.100 mol of solid glucose (C6H12O6) dissolved in 100. mL of water is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Answer to Problem 7.30E

The concentration in %(w/w) of 0.100 mol of solid glucose (C6H12O6) dissolved in 100. mL of water is 15.27 %w/w.

Explanation of Solution

The formula to calculate number of moles of solutes is given below as,

Moles of solute=Mass of soluteMolar mass of solute

Rearrange the above equation for mass of solute as follows.

Moles of solute=Mass of soluteMolar mass of soluteMass of solute=Moles of solute×Molar mass of solute …(1)

The molar mass of glucose can be calculated as follows.

C6H12O6=(6×C)+(12×H)+(6×O)=(6×12)+(12×1)+(6×16)=180 g/mol

Substitute the values in the equation (1) as follows.

Mass of C6H12O6=Moles of C6H12O6×Molar mass of C6H12O6=0.100 mol×180 g/mol g/mol=18.0 g

The formula to calculate concentration in %(w/w) is given below as,

%(w/w)=Solute MassSolution Mass×100

The density of water is 1.00 g/mL. Thus, the mass of water is equal to its volume. Hence in this case the mass of solution is taken as 100. g. Substitute the value of mass of solute and mass of solution in the above equation as follows.

%(w/w)=Mass of C6H12O6Solution Mass×100=18.02 g(100+18.0)g×100=18.02 g118.0 g×100=15.27 %w/w

Conclusion

The concentration in %(w/w) of 0.100 mol of solid glucose (C6H12O6) dissolved in 100. mL of water is 15.27 %w/w.

Expert Solution

Interpretation Introduction

(c)

Interpretation:

The concentration in %(w/w) of 120 g of solid dissolved in 100. mL of water is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Answer to Problem 7.30E

The concentration in %(w/w) of 120 g of solid dissolved in 100. mL of water is 54.55 %w/w.

Explanation of Solution

The formula to calculate concentration in %(w/w) is given below as,

%(w/w)=Solute MassSolution Mass×100

The density of water is 1.00 g/mL. Thus, the mass of water is equal to its volume. Hence in this case the mass of solution is taken as 100. g. Substitute the value of mass of solute and mass of solution in the above equation as follows.

%(w/w)=Solute MassSolution Mass×100=120 g(100+120) g×100=120 g220 g×100=54.55 %w/w

Conclusion

The concentration in %(w/w) of 120 g of solid dissolved in 100. mL of water is 54.55 %w/w.

Expert Solution

Interpretation Introduction

(d)

Interpretation:

The concentration in %(w/w) of 10.0 mL of ethyl alcohol (density =0.789 g/mL) mixed with 10.0 mL of water is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Answer to Problem 7.30E

The concentration in %(w/w) of 10.0 mL of ethyl alcohol (density =0.789 g/mL) mixed with 10.0 mL of water is 44.10 %w/w.

Explanation of Solution

The formula to calculate concentration in %(w/w) is given below as,

%(w/w)=Solute MassSolution Mass×100 …(1)

The formula to calculate density is given below as,

d=mV

Where,

• m is the mass of the substance.

• V is the volume of the substance.

• d is the density of the substance.

The density of water is 1.00 g/mL. Thus, the mass of water is equal to its volume. Hence in this case the mass of solution is taken as 10. g. But the density of ethyl alcohol is 0.789 g/mL. Thus, the mass of 10.0 mL of ethyl alcohol can be calculated as follows.

d=mVm=d×V=0.789 g/mL×10.0 mL=7.89 g

Substitute the value of mass of ethyl alcohol and mass of solution in the equation (1) as follows.

%(w/w)= Mass of ethyl alcoholSolution Mass×100=7.89 g(10+7.89) g×100=7.89 g17.89 g×100=44.10 %w/w

Conclusion

The concentration in %(w/w) of 10.0 mL of ethyl alcohol (density =0.789 g/mL) mixed with 10.0 mL of water is 44.10 %w/w.

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Answer 2

Textbook Question

Chapter 7, Problem 7.30E

Calculate the concentration in % ( w / w ) of the following solutions. Assume water has a density of 1.00 g / mL .

a. 20.0 g of salt is dissolved in 250. mL of water.

b. 0.100 mol of solid glucose ( C 6 H 12 O 6 ) is dissolved in 100. mL of water.

c. 120 g of solid is dissolved in 100. mL of water.

d. 10.0 mL of ethyl alcohol (density = 0.789 g / mL ) is mixed with 10.0 mL of water.

Expert Solution

Interpretation Introduction

(a)

Interpretation:

The concentration in %(w/w) of 20.0 g of salt dissolved in 250. mL of water is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Answer to Problem 7.30E

The concentration in %(w/w) of 20.0 g of salt dissolved in 250. mL of water is 7.41 %w/w.

Explanation of Solution

The formula to calculate concentration in %(w/w) is given below as,

%(w/w)=Solute MassSolution Mass×100

The density of water is 1.00 g/mL. Thus, the mass of water is equal to its volume. Hence in this case the mass of solution is taken as 250. g. Substitute the value of mass of salt and mass of solution in the above equation as follows.

%(w/w)=Mass of saltSolution Mass×100=20.0 g(250+20) g×100=20 g270 g×100=7.41 %w/w

Conclusion

The concentration in %(w/w) of 20.0 g of salt dissolved in 250. mL of water is 7.41 %w/w.

Expert Solution

Interpretation Introduction

(b)

Interpretation:

The concentration in %(w/w) of 0.100 mol of solid glucose (C6H12O6) dissolved in 100. mL of water is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Answer to Problem 7.30E

The concentration in %(w/w) of 0.100 mol of solid glucose (C6H12O6) dissolved in 100. mL of water is 15.27 %w/w.

Explanation of Solution

The formula to calculate number of moles of solutes is given below as,

Moles of solute=Mass of soluteMolar mass of solute

Rearrange the above equation for mass of solute as follows.

Moles of solute=Mass of soluteMolar mass of soluteMass of solute=Moles of solute×Molar mass of solute …(1)

The molar mass of glucose can be calculated as follows.

C6H12O6=(6×C)+(12×H)+(6×O)=(6×12)+(12×1)+(6×16)=180 g/mol

Substitute the values in the equation (1) as follows.

Mass of C6H12O6=Moles of C6H12O6×Molar mass of C6H12O6=0.100 mol×180 g/mol g/mol=18.0 g

The formula to calculate concentration in %(w/w) is given below as,

%(w/w)=Solute MassSolution Mass×100

The density of water is 1.00 g/mL. Thus, the mass of water is equal to its volume. Hence in this case the mass of solution is taken as 100. g. Substitute the value of mass of solute and mass of solution in the above equation as follows.

%(w/w)=Mass of C6H12O6Solution Mass×100=18.02 g(100+18.0)g×100=18.02 g118.0 g×100=15.27 %w/w

Conclusion

The concentration in %(w/w) of 0.100 mol of solid glucose (C6H12O6) dissolved in 100. mL of water is 15.27 %w/w.

Expert Solution

Interpretation Introduction

(c)

Interpretation:

The concentration in %(w/w) of 120 g of solid dissolved in 100. mL of water is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Answer to Problem 7.30E

The concentration in %(w/w) of 120 g of solid dissolved in 100. mL of water is 54.55 %w/w.

Explanation of Solution

The formula to calculate concentration in %(w/w) is given below as,

%(w/w)=Solute MassSolution Mass×100

The density of water is 1.00 g/mL. Thus, the mass of water is equal to its volume. Hence in this case the mass of solution is taken as 100. g. Substitute the value of mass of solute and mass of solution in the above equation as follows.

%(w/w)=Solute MassSolution Mass×100=120 g(100+120) g×100=120 g220 g×100=54.55 %w/w

Conclusion

The concentration in %(w/w) of 120 g of solid dissolved in 100. mL of water is 54.55 %w/w.

Expert Solution

Interpretation Introduction

(d)

Interpretation:

The concentration in %(w/w) of 10.0 mL of ethyl alcohol (density =0.789 g/mL) mixed with 10.0 mL of water is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Answer to Problem 7.30E

The concentration in %(w/w) of 10.0 mL of ethyl alcohol (density =0.789 g/mL) mixed with 10.0 mL of water is 44.10 %w/w.

Explanation of Solution

The formula to calculate concentration in %(w/w) is given below as,

%(w/w)=Solute MassSolution Mass×100 …(1)

The formula to calculate density is given below as,

d=mV

Where,

• m is the mass of the substance.

• V is the volume of the substance.

• d is the density of the substance.

The density of water is 1.00 g/mL. Thus, the mass of water is equal to its volume. Hence in this case the mass of solution is taken as 10. g. But the density of ethyl alcohol is 0.789 g/mL. Thus, the mass of 10.0 mL of ethyl alcohol can be calculated as follows.

d=mVm=d×V=0.789 g/mL×10.0 mL=7.89 g

Substitute the value of mass of ethyl alcohol and mass of solution in the equation (1) as follows.

%(w/w)= Mass of ethyl alcoholSolution Mass×100=7.89 g(10+7.89) g×100=7.89 g17.89 g×100=44.10 %w/w

Conclusion

The concentration in %(w/w) of 10.0 mL of ethyl alcohol (density =0.789 g/mL) mixed with 10.0 mL of water is 44.10 %w/w.

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Answer 3

Textbook Question

Chapter 7, Problem 7.30E

Calculate the concentration in % ( w / w ) of the following solutions. Assume water has a density of 1.00 g / mL .

a. 20.0 g of salt is dissolved in 250. mL of water.

b. 0.100 mol of solid glucose ( C 6 H 12 O 6 ) is dissolved in 100. mL of water.

c. 120 g of solid is dissolved in 100. mL of water.

d. 10.0 mL of ethyl alcohol (density = 0.789 g / mL ) is mixed with 10.0 mL of water.

Expert Solution

Interpretation Introduction

(a)

Interpretation:

The concentration in %(w/w) of 20.0 g of salt dissolved in 250. mL of water is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Answer to Problem 7.30E

The concentration in %(w/w) of 20.0 g of salt dissolved in 250. mL of water is 7.41 %w/w.

Explanation of Solution

The formula to calculate concentration in %(w/w) is given below as,

%(w/w)=Solute MassSolution Mass×100

The density of water is 1.00 g/mL. Thus, the mass of water is equal to its volume. Hence in this case the mass of solution is taken as 250. g. Substitute the value of mass of salt and mass of solution in the above equation as follows.

%(w/w)=Mass of saltSolution Mass×100=20.0 g(250+20) g×100=20 g270 g×100=7.41 %w/w

Conclusion

The concentration in %(w/w) of 20.0 g of salt dissolved in 250. mL of water is 7.41 %w/w.

Expert Solution

Interpretation Introduction

(b)

Interpretation:

The concentration in %(w/w) of 0.100 mol of solid glucose (C6H12O6) dissolved in 100. mL of water is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Answer to Problem 7.30E

The concentration in %(w/w) of 0.100 mol of solid glucose (C6H12O6) dissolved in 100. mL of water is 15.27 %w/w.

Explanation of Solution

The formula to calculate number of moles of solutes is given below as,

Moles of solute=Mass of soluteMolar mass of solute

Rearrange the above equation for mass of solute as follows.

Moles of solute=Mass of soluteMolar mass of soluteMass of solute=Moles of solute×Molar mass of solute …(1)

The molar mass of glucose can be calculated as follows.

C6H12O6=(6×C)+(12×H)+(6×O)=(6×12)+(12×1)+(6×16)=180 g/mol

Substitute the values in the equation (1) as follows.

Mass of C6H12O6=Moles of C6H12O6×Molar mass of C6H12O6=0.100 mol×180 g/mol g/mol=18.0 g

The formula to calculate concentration in %(w/w) is given below as,

%(w/w)=Solute MassSolution Mass×100

The density of water is 1.00 g/mL. Thus, the mass of water is equal to its volume. Hence in this case the mass of solution is taken as 100. g. Substitute the value of mass of solute and mass of solution in the above equation as follows.

%(w/w)=Mass of C6H12O6Solution Mass×100=18.02 g(100+18.0)g×100=18.02 g118.0 g×100=15.27 %w/w

Conclusion

The concentration in %(w/w) of 0.100 mol of solid glucose (C6H12O6) dissolved in 100. mL of water is 15.27 %w/w.

Expert Solution

Interpretation Introduction

(c)

Interpretation:

The concentration in %(w/w) of 120 g of solid dissolved in 100. mL of water is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Answer to Problem 7.30E

The concentration in %(w/w) of 120 g of solid dissolved in 100. mL of water is 54.55 %w/w.

Explanation of Solution

The formula to calculate concentration in %(w/w) is given below as,

%(w/w)=Solute MassSolution Mass×100

The density of water is 1.00 g/mL. Thus, the mass of water is equal to its volume. Hence in this case the mass of solution is taken as 100. g. Substitute the value of mass of solute and mass of solution in the above equation as follows.

%(w/w)=Solute MassSolution Mass×100=120 g(100+120) g×100=120 g220 g×100=54.55 %w/w

Conclusion

The concentration in %(w/w) of 120 g of solid dissolved in 100. mL of water is 54.55 %w/w.

Expert Solution

Interpretation Introduction

(d)

Interpretation:

The concentration in %(w/w) of 10.0 mL of ethyl alcohol (density =0.789 g/mL) mixed with 10.0 mL of water is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Answer to Problem 7.30E

The concentration in %(w/w) of 10.0 mL of ethyl alcohol (density =0.789 g/mL) mixed with 10.0 mL of water is 44.10 %w/w.

Explanation of Solution

The formula to calculate concentration in %(w/w) is given below as,

%(w/w)=Solute MassSolution Mass×100 …(1)

The formula to calculate density is given below as,

d=mV

Where,

• m is the mass of the substance.

• V is the volume of the substance.

• d is the density of the substance.

The density of water is 1.00 g/mL. Thus, the mass of water is equal to its volume. Hence in this case the mass of solution is taken as 10. g. But the density of ethyl alcohol is 0.789 g/mL. Thus, the mass of 10.0 mL of ethyl alcohol can be calculated as follows.

d=mVm=d×V=0.789 g/mL×10.0 mL=7.89 g

Substitute the value of mass of ethyl alcohol and mass of solution in the equation (1) as follows.

%(w/w)= Mass of ethyl alcoholSolution Mass×100=7.89 g(10+7.89) g×100=7.89 g17.89 g×100=44.10 %w/w

Conclusion

The concentration in %(w/w) of 10.0 mL of ethyl alcohol (density =0.789 g/mL) mixed with 10.0 mL of water is 44.10 %w/w.

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Answer 4

Textbook Question

Chapter 7, Problem 7.30E

Calculate the concentration in % ( w / w ) of the following solutions. Assume water has a density of 1.00 g / mL .

a. 20.0 g of salt is dissolved in 250. mL of water.

b. 0.100 mol of solid glucose ( C 6 H 12 O 6 ) is dissolved in 100. mL of water.

c. 120 g of solid is dissolved in 100. mL of water.

d. 10.0 mL of ethyl alcohol (density = 0.789 g / mL ) is mixed with 10.0 mL of water.

Expert Solution

Interpretation Introduction

(a)

Interpretation:

The concentration in %(w/w) of 20.0 g of salt dissolved in 250. mL of water is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Answer to Problem 7.30E

The concentration in %(w/w) of 20.0 g of salt dissolved in 250. mL of water is 7.41 %w/w.

Explanation of Solution

The formula to calculate concentration in %(w/w) is given below as,

%(w/w)=Solute MassSolution Mass×100

The density of water is 1.00 g/mL. Thus, the mass of water is equal to its volume. Hence in this case the mass of solution is taken as 250. g. Substitute the value of mass of salt and mass of solution in the above equation as follows.

%(w/w)=Mass of saltSolution Mass×100=20.0 g(250+20) g×100=20 g270 g×100=7.41 %w/w

Conclusion

The concentration in %(w/w) of 20.0 g of salt dissolved in 250. mL of water is 7.41 %w/w.

Expert Solution

Interpretation Introduction

(b)

Interpretation:

The concentration in %(w/w) of 0.100 mol of solid glucose (C6H12O6) dissolved in 100. mL of water is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Answer to Problem 7.30E

The concentration in %(w/w) of 0.100 mol of solid glucose (C6H12O6) dissolved in 100. mL of water is 15.27 %w/w.

Explanation of Solution

The formula to calculate number of moles of solutes is given below as,

Moles of solute=Mass of soluteMolar mass of solute

Rearrange the above equation for mass of solute as follows.

Moles of solute=Mass of soluteMolar mass of soluteMass of solute=Moles of solute×Molar mass of solute …(1)

The molar mass of glucose can be calculated as follows.

C6H12O6=(6×C)+(12×H)+(6×O)=(6×12)+(12×1)+(6×16)=180 g/mol

Substitute the values in the equation (1) as follows.

Mass of C6H12O6=Moles of C6H12O6×Molar mass of C6H12O6=0.100 mol×180 g/mol g/mol=18.0 g

The formula to calculate concentration in %(w/w) is given below as,

%(w/w)=Solute MassSolution Mass×100

The density of water is 1.00 g/mL. Thus, the mass of water is equal to its volume. Hence in this case the mass of solution is taken as 100. g. Substitute the value of mass of solute and mass of solution in the above equation as follows.

%(w/w)=Mass of C6H12O6Solution Mass×100=18.02 g(100+18.0)g×100=18.02 g118.0 g×100=15.27 %w/w

Conclusion

The concentration in %(w/w) of 0.100 mol of solid glucose (C6H12O6) dissolved in 100. mL of water is 15.27 %w/w.

Expert Solution

Interpretation Introduction

(c)

Interpretation:

The concentration in %(w/w) of 120 g of solid dissolved in 100. mL of water is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Answer to Problem 7.30E

The concentration in %(w/w) of 120 g of solid dissolved in 100. mL of water is 54.55 %w/w.

Explanation of Solution

The formula to calculate concentration in %(w/w) is given below as,

%(w/w)=Solute MassSolution Mass×100

The density of water is 1.00 g/mL. Thus, the mass of water is equal to its volume. Hence in this case the mass of solution is taken as 100. g. Substitute the value of mass of solute and mass of solution in the above equation as follows.

%(w/w)=Solute MassSolution Mass×100=120 g(100+120) g×100=120 g220 g×100=54.55 %w/w

Conclusion

The concentration in %(w/w) of 120 g of solid dissolved in 100. mL of water is 54.55 %w/w.

Expert Solution

Interpretation Introduction

(d)

Interpretation:

The concentration in %(w/w) of 10.0 mL of ethyl alcohol (density =0.789 g/mL) mixed with 10.0 mL of water is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Answer to Problem 7.30E

The concentration in %(w/w) of 10.0 mL of ethyl alcohol (density =0.789 g/mL) mixed with 10.0 mL of water is 44.10 %w/w.

Explanation of Solution

The formula to calculate concentration in %(w/w) is given below as,

%(w/w)=Solute MassSolution Mass×100 …(1)

The formula to calculate density is given below as,

d=mV

Where,

• m is the mass of the substance.

• V is the volume of the substance.

• d is the density of the substance.

The density of water is 1.00 g/mL. Thus, the mass of water is equal to its volume. Hence in this case the mass of solution is taken as 10. g. But the density of ethyl alcohol is 0.789 g/mL. Thus, the mass of 10.0 mL of ethyl alcohol can be calculated as follows.

d=mVm=d×V=0.789 g/mL×10.0 mL=7.89 g

Substitute the value of mass of ethyl alcohol and mass of solution in the equation (1) as follows.

%(w/w)= Mass of ethyl alcoholSolution Mass×100=7.89 g(10+7.89) g×100=7.89 g17.89 g×100=44.10 %w/w

Conclusion

The concentration in %(w/w) of 10.0 mL of ethyl alcohol (density =0.789 g/mL) mixed with 10.0 mL of water is 44.10 %w/w.

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Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

Expert Solution

Interpretation Introduction

(a)

Interpretation:

The concentration in %(w/w) of 20.0 g of salt dissolved in 250. mL of water is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Answer to Problem 7.30E

The concentration in %(w/w) of 20.0 g of salt dissolved in 250. mL of water is 7.41 %w/w.

Explanation of Solution

The formula to calculate concentration in %(w/w) is given below as,

%(w/w)=Solute MassSolution Mass×100

The density of water is 1.00 g/mL. Thus, the mass of water is equal to its volume. Hence in this case the mass of solution is taken as 250. g. Substitute the value of mass of salt and mass of solution in the above equation as follows.

%(w/w)=Mass of saltSolution Mass×100=20.0 g(250+20) g×100=20 g270 g×100=7.41 %w/w

Conclusion

The concentration in %(w/w) of 20.0 g of salt dissolved in 250. mL of water is 7.41 %w/w.

Expert Solution

Interpretation Introduction

(b)

Interpretation:

The concentration in %(w/w) of 0.100 mol of solid glucose (C6H12O6) dissolved in 100. mL of water is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Answer to Problem 7.30E

The concentration in %(w/w) of 0.100 mol of solid glucose (C6H12O6) dissolved in 100. mL of water is 15.27 %w/w.

Explanation of Solution

The formula to calculate number of moles of solutes is given below as,

Moles of solute=Mass of soluteMolar mass of solute

Rearrange the above equation for mass of solute as follows.

Moles of solute=Mass of soluteMolar mass of soluteMass of solute=Moles of solute×Molar mass of solute …(1)

The molar mass of glucose can be calculated as follows.

C6H12O6=(6×C)+(12×H)+(6×O)=(6×12)+(12×1)+(6×16)=180 g/mol

Substitute the values in the equation (1) as follows.

Mass of C6H12O6=Moles of C6H12O6×Molar mass of C6H12O6=0.100 mol×180 g/mol g/mol=18.0 g

The formula to calculate concentration in %(w/w) is given below as,

%(w/w)=Solute MassSolution Mass×100

The density of water is 1.00 g/mL. Thus, the mass of water is equal to its volume. Hence in this case the mass of solution is taken as 100. g. Substitute the value of mass of solute and mass of solution in the above equation as follows.

%(w/w)=Mass of C6H12O6Solution Mass×100=18.02 g(100+18.0)g×100=18.02 g118.0 g×100=15.27 %w/w

Conclusion

The concentration in %(w/w) of 0.100 mol of solid glucose (C6H12O6) dissolved in 100. mL of water is 15.27 %w/w.

Expert Solution

Interpretation Introduction

(c)

Interpretation:

The concentration in %(w/w) of 120 g of solid dissolved in 100. mL of water is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Answer to Problem 7.30E

The concentration in %(w/w) of 120 g of solid dissolved in 100. mL of water is 54.55 %w/w.

Explanation of Solution

The formula to calculate concentration in %(w/w) is given below as,

%(w/w)=Solute MassSolution Mass×100

The density of water is 1.00 g/mL. Thus, the mass of water is equal to its volume. Hence in this case the mass of solution is taken as 100. g. Substitute the value of mass of solute and mass of solution in the above equation as follows.

%(w/w)=Solute MassSolution Mass×100=120 g(100+120) g×100=120 g220 g×100=54.55 %w/w

Conclusion

The concentration in %(w/w) of 120 g of solid dissolved in 100. mL of water is 54.55 %w/w.

Expert Solution

Interpretation Introduction

(d)

Interpretation:

The concentration in %(w/w) of 10.0 mL of ethyl alcohol (density =0.789 g/mL) mixed with 10.0 mL of water is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Answer to Problem 7.30E

The concentration in %(w/w) of 10.0 mL of ethyl alcohol (density =0.789 g/mL) mixed with 10.0 mL of water is 44.10 %w/w.

Explanation of Solution

The formula to calculate concentration in %(w/w) is given below as,

%(w/w)=Solute MassSolution Mass×100 …(1)

The formula to calculate density is given below as,

d=mV

Where,

• m is the mass of the substance.

• V is the volume of the substance.

• d is the density of the substance.

The density of water is 1.00 g/mL. Thus, the mass of water is equal to its volume. Hence in this case the mass of solution is taken as 10. g. But the density of ethyl alcohol is 0.789 g/mL. Thus, the mass of 10.0 mL of ethyl alcohol can be calculated as follows.

d=mVm=d×V=0.789 g/mL×10.0 mL=7.89 g

Substitute the value of mass of ethyl alcohol and mass of solution in the equation (1) as follows.

%(w/w)= Mass of ethyl alcoholSolution Mass×100=7.89 g(10+7.89) g×100=7.89 g17.89 g×100=44.10 %w/w

Conclusion

The concentration in %(w/w) of 10.0 mL of ethyl alcohol (density =0.789 g/mL) mixed with 10.0 mL of water is 44.10 %w/w.

Answer 8

Expert Solution

Interpretation Introduction

(a)

Interpretation:

The concentration in %(w/w) of 20.0 g of salt dissolved in 250. mL of water is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Answer to Problem 7.30E

The concentration in %(w/w) of 20.0 g of salt dissolved in 250. mL of water is 7.41 %w/w.

Explanation of Solution

The formula to calculate concentration in %(w/w) is given below as,

%(w/w)=Solute MassSolution Mass×100

The density of water is 1.00 g/mL. Thus, the mass of water is equal to its volume. Hence in this case the mass of solution is taken as 250. g. Substitute the value of mass of salt and mass of solution in the above equation as follows.

%(w/w)=Mass of saltSolution Mass×100=20.0 g(250+20) g×100=20 g270 g×100=7.41 %w/w

Conclusion

The concentration in %(w/w) of 20.0 g of salt dissolved in 250. mL of water is 7.41 %w/w.

Answer 9

Expert Solution

Answer 10

Expert Solution

Answer 11

Expert Solution

Answer 12

Interpretation Introduction

(a)

Interpretation:

The concentration in %(w/w) of 20.0 g of salt dissolved in 250. mL of water is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Answer 13

Answer to Problem 7.30E

The concentration in %(w/w) of 20.0 g of salt dissolved in 250. mL of water is 7.41 %w/w.

Answer 14

Explanation of Solution

The formula to calculate concentration in %(w/w) is given below as,

%(w/w)=Solute MassSolution Mass×100

The density of water is 1.00 g/mL. Thus, the mass of water is equal to its volume. Hence in this case the mass of solution is taken as 250. g. Substitute the value of mass of salt and mass of solution in the above equation as follows.

%(w/w)=Mass of saltSolution Mass×100=20.0 g(250+20) g×100=20 g270 g×100=7.41 %w/w

Answer 15

Conclusion

The concentration in %(w/w) of 20.0 g of salt dissolved in 250. mL of water is 7.41 %w/w.

Answer 16

Expert Solution

Interpretation Introduction

(b)

Interpretation:

The concentration in %(w/w) of 0.100 mol of solid glucose (C6H12O6) dissolved in 100. mL of water is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Answer to Problem 7.30E

The concentration in %(w/w) of 0.100 mol of solid glucose (C6H12O6) dissolved in 100. mL of water is 15.27 %w/w.

Explanation of Solution

The formula to calculate number of moles of solutes is given below as,

Moles of solute=Mass of soluteMolar mass of solute

Rearrange the above equation for mass of solute as follows.

Moles of solute=Mass of soluteMolar mass of soluteMass of solute=Moles of solute×Molar mass of solute …(1)

The molar mass of glucose can be calculated as follows.

C6H12O6=(6×C)+(12×H)+(6×O)=(6×12)+(12×1)+(6×16)=180 g/mol

Substitute the values in the equation (1) as follows.

Mass of C6H12O6=Moles of C6H12O6×Molar mass of C6H12O6=0.100 mol×180 g/mol g/mol=18.0 g

The formula to calculate concentration in %(w/w) is given below as,

%(w/w)=Solute MassSolution Mass×100

The density of water is 1.00 g/mL. Thus, the mass of water is equal to its volume. Hence in this case the mass of solution is taken as 100. g. Substitute the value of mass of solute and mass of solution in the above equation as follows.

%(w/w)=Mass of C6H12O6Solution Mass×100=18.02 g(100+18.0)g×100=18.02 g118.0 g×100=15.27 %w/w

Conclusion

The concentration in %(w/w) of 0.100 mol of solid glucose (C6H12O6) dissolved in 100. mL of water is 15.27 %w/w.

Answer 17

Expert Solution

Answer 18

Expert Solution

Answer 19

Expert Solution

Answer 20

Interpretation Introduction

(b)

Interpretation:

The concentration in %(w/w) of 0.100 mol of solid glucose (C6H12O6) dissolved in 100. mL of water is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Answer 21

Answer to Problem 7.30E

The concentration in %(w/w) of 0.100 mol of solid glucose (C6H12O6) dissolved in 100. mL of water is 15.27 %w/w.

Answer 22

Explanation of Solution

The formula to calculate number of moles of solutes is given below as,

Moles of solute=Mass of soluteMolar mass of solute

Rearrange the above equation for mass of solute as follows.

Moles of solute=Mass of soluteMolar mass of soluteMass of solute=Moles of solute×Molar mass of solute …(1)

The molar mass of glucose can be calculated as follows.

C6H12O6=(6×C)+(12×H)+(6×O)=(6×12)+(12×1)+(6×16)=180 g/mol

Substitute the values in the equation (1) as follows.

Mass of C6H12O6=Moles of C6H12O6×Molar mass of C6H12O6=0.100 mol×180 g/mol g/mol=18.0 g

The formula to calculate concentration in %(w/w) is given below as,

%(w/w)=Solute MassSolution Mass×100

The density of water is 1.00 g/mL. Thus, the mass of water is equal to its volume. Hence in this case the mass of solution is taken as 100. g. Substitute the value of mass of solute and mass of solution in the above equation as follows.

%(w/w)=Mass of C6H12O6Solution Mass×100=18.02 g(100+18.0)g×100=18.02 g118.0 g×100=15.27 %w/w

Answer 23

Conclusion

The concentration in %(w/w) of 0.100 mol of solid glucose (C6H12O6) dissolved in 100. mL of water is 15.27 %w/w.

Answer 24

Expert Solution

Interpretation Introduction

(c)

Interpretation:

The concentration in %(w/w) of 120 g of solid dissolved in 100. mL of water is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Answer to Problem 7.30E

The concentration in %(w/w) of 120 g of solid dissolved in 100. mL of water is 54.55 %w/w.

Explanation of Solution

The formula to calculate concentration in %(w/w) is given below as,

%(w/w)=Solute MassSolution Mass×100

The density of water is 1.00 g/mL. Thus, the mass of water is equal to its volume. Hence in this case the mass of solution is taken as 100. g. Substitute the value of mass of solute and mass of solution in the above equation as follows.

%(w/w)=Solute MassSolution Mass×100=120 g(100+120) g×100=120 g220 g×100=54.55 %w/w

Conclusion

The concentration in %(w/w) of 120 g of solid dissolved in 100. mL of water is 54.55 %w/w.

Answer 25

Expert Solution

Answer 26

Expert Solution

Answer 27

Expert Solution

Answer 28

Interpretation Introduction

(c)

Interpretation:

The concentration in %(w/w) of 120 g of solid dissolved in 100. mL of water is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Answer 29

Answer to Problem 7.30E

The concentration in %(w/w) of 120 g of solid dissolved in 100. mL of water is 54.55 %w/w.

Answer 30

Explanation of Solution

The formula to calculate concentration in %(w/w) is given below as,

%(w/w)=Solute MassSolution Mass×100

The density of water is 1.00 g/mL. Thus, the mass of water is equal to its volume. Hence in this case the mass of solution is taken as 100. g. Substitute the value of mass of solute and mass of solution in the above equation as follows.

%(w/w)=Solute MassSolution Mass×100=120 g(100+120) g×100=120 g220 g×100=54.55 %w/w

Answer 31

Conclusion

The concentration in %(w/w) of 120 g of solid dissolved in 100. mL of water is 54.55 %w/w.

Answer 32

Expert Solution

Interpretation Introduction

(d)

Interpretation:

The concentration in %(w/w) of 10.0 mL of ethyl alcohol (density =0.789 g/mL) mixed with 10.0 mL of water is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Answer to Problem 7.30E

The concentration in %(w/w) of 10.0 mL of ethyl alcohol (density =0.789 g/mL) mixed with 10.0 mL of water is 44.10 %w/w.

Explanation of Solution

The formula to calculate concentration in %(w/w) is given below as,

%(w/w)=Solute MassSolution Mass×100 …(1)

The formula to calculate density is given below as,

d=mV

Where,

• m is the mass of the substance.

• V is the volume of the substance.

• d is the density of the substance.

The density of water is 1.00 g/mL. Thus, the mass of water is equal to its volume. Hence in this case the mass of solution is taken as 10. g. But the density of ethyl alcohol is 0.789 g/mL. Thus, the mass of 10.0 mL of ethyl alcohol can be calculated as follows.

d=mVm=d×V=0.789 g/mL×10.0 mL=7.89 g

Substitute the value of mass of ethyl alcohol and mass of solution in the equation (1) as follows.

%(w/w)= Mass of ethyl alcoholSolution Mass×100=7.89 g(10+7.89) g×100=7.89 g17.89 g×100=44.10 %w/w

Conclusion

The concentration in %(w/w) of 10.0 mL of ethyl alcohol (density =0.789 g/mL) mixed with 10.0 mL of water is 44.10 %w/w.

Answer 33

Expert Solution

Answer 34

Expert Solution

Answer 35

Expert Solution

Answer 36

Interpretation Introduction

(d)

Interpretation:

The concentration in %(w/w) of 10.0 mL of ethyl alcohol (density =0.789 g/mL) mixed with 10.0 mL of water is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Answer 37

Answer to Problem 7.30E

The concentration in %(w/w) of 10.0 mL of ethyl alcohol (density =0.789 g/mL) mixed with 10.0 mL of water is 44.10 %w/w.

Answer 38

Explanation of Solution

The formula to calculate concentration in %(w/w) is given below as,

%(w/w)=Solute MassSolution Mass×100 …(1)

The formula to calculate density is given below as,

d=mV

Where,

• m is the mass of the substance.

• V is the volume of the substance.

• d is the density of the substance.

The density of water is 1.00 g/mL. Thus, the mass of water is equal to its volume. Hence in this case the mass of solution is taken as 10. g. But the density of ethyl alcohol is 0.789 g/mL. Thus, the mass of 10.0 mL of ethyl alcohol can be calculated as follows.