(a) Interpretation: The molarity of a sample of solid KBr weighing 11.9 g on dissolving in enough distilled water to give 200. mL of solution is to be calculated. Concept introduction: A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume ( % w / v ) , percent volume by volume ( % v / v ) and molarity ( M ) . When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight ( % w / w ) .

Question

Lab Data The distance entered is out of the expected range. Check your calculations and conversion factors. Verify your distance. Will the gas cloud be closer to the cotton ball with HCI or NH3? Did you report your data to the correct number of significant figures? - X Experimental Set-up HCI-NH3 NH3-HCI Longer Tube Time elapsed (min) 5 (exact) 5 (exact) Distance between cotton balls (cm) 24.30 24.40 Distance to cloud (cm) 9.70 14.16 Distance traveled by HCI (cm) 9.70 9.80 Distance traveled by NH3 (cm) 14.60 14.50 Diffusion rate of HCI (cm/hr) 116 118 Diffusion rate of NH3 (cm/hr) 175.2 175.2 How to measure distance and calculate rate

Answer 1

Question

Chapter 7, Problem 7.22E

Interpretation Introduction

(a)

Interpretation:

The molarity of a sample of solid KBr weighing 11.9 g on dissolving in enough distilled water to give 200. mL of solution is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Interpretation Introduction

(b)

Interpretation:

The molarity of 14.2-g sample of solid Na2SO4 dissolved in enough water to give 500. mL of solution is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Interpretation Introduction

(c)

Interpretation:

The molarity of a 10.0-mL sample of solution that was evaporated to dryness and 0.29 g of Li2SO4 was left is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

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Lab Data The distance entered is out of the expected range. Check your calculations and conversion factors. Verify your distance. Will the gas cloud be closer to the cotton ball with HCI or NH3? Did you report your data to the correct number of significant figures? - X Experimental Set-up HCI-NH3 NH3-HCI Longer Tube Time elapsed (min) 5 (exact) 5 (exact) Distance between cotton balls (cm) 24.30 24.40 Distance to cloud (cm) 9.70 14.16 Distance traveled by HCI (cm) 9.70 9.80 Distance traveled by NH3 (cm) 14.60 14.50 Diffusion rate of HCI (cm/hr) 116 118 Diffusion rate of NH3 (cm/hr) 175.2 175.2 How to measure distance and calculate rate

For the titration of a divalent metal ion (M2+) with EDTA, the stoichiometry of the reaction is typically: 1:1 (one mole of EDTA per mole of metal ion) 2:1 (two moles of EDTA per mole of metal ion) 1:2 (one mole of EDTA per two moles of metal ion) None of the above

Please help me solve this reaction.

Answer 2

Question

Chapter 7, Problem 7.22E

Interpretation Introduction

(a)

Interpretation:

The molarity of a sample of solid KBr weighing 11.9 g on dissolving in enough distilled water to give 200. mL of solution is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Interpretation Introduction

(b)

Interpretation:

The molarity of 14.2-g sample of solid Na2SO4 dissolved in enough water to give 500. mL of solution is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Interpretation Introduction

(c)

Interpretation:

The molarity of a 10.0-mL sample of solution that was evaporated to dryness and 0.29 g of Li2SO4 was left is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

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Answer 3

Question

Chapter 7, Problem 7.22E

Interpretation Introduction

(a)

Interpretation:

The molarity of a sample of solid KBr weighing 11.9 g on dissolving in enough distilled water to give 200. mL of solution is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Interpretation Introduction

(b)

Interpretation:

The molarity of 14.2-g sample of solid Na2SO4 dissolved in enough water to give 500. mL of solution is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Interpretation Introduction

(c)

Interpretation:

The molarity of a 10.0-mL sample of solution that was evaporated to dryness and 0.29 g of Li2SO4 was left is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

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Answer 4

Question

Chapter 7, Problem 7.22E

Interpretation Introduction

(a)

Interpretation:

The molarity of a sample of solid KBr weighing 11.9 g on dissolving in enough distilled water to give 200. mL of solution is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Interpretation Introduction

(b)

Interpretation:

The molarity of 14.2-g sample of solid Na2SO4 dissolved in enough water to give 500. mL of solution is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Interpretation Introduction

(c)

Interpretation:

The molarity of a 10.0-mL sample of solution that was evaporated to dryness and 0.29 g of Li2SO4 was left is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

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Answer 5

Chapter 7, Problem 7.22E

Interpretation Introduction

(a)

Interpretation:

The molarity of a sample of solid KBr weighing 11.9 g on dissolving in enough distilled water to give 200. mL of solution is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Interpretation Introduction

(b)

Interpretation:

The molarity of 14.2-g sample of solid Na2SO4 dissolved in enough water to give 500. mL of solution is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Interpretation Introduction

(c)

Interpretation:

The molarity of a 10.0-mL sample of solution that was evaporated to dryness and 0.29 g of Li2SO4 was left is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Answer 6

Chapter 7, Problem 7.22E

Interpretation Introduction

(a)

Interpretation:

The molarity of a sample of solid KBr weighing 11.9 g on dissolving in enough distilled water to give 200. mL of solution is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Answer 7

Chapter 7, Problem 7.22E

Interpretation Introduction

(a)

Interpretation:

The molarity of a sample of solid KBr weighing 11.9 g on dissolving in enough distilled water to give 200. mL of solution is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Answer 8

Interpretation Introduction

(b)

Interpretation:

The molarity of 14.2-g sample of solid Na2SO4 dissolved in enough water to give 500. mL of solution is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Answer 9

Interpretation Introduction

(b)

Interpretation:

The molarity of 14.2-g sample of solid Na2SO4 dissolved in enough water to give 500. mL of solution is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Answer 10

Interpretation Introduction

(c)

Interpretation:

The molarity of a 10.0-mL sample of solution that was evaporated to dryness and 0.29 g of Li2SO4 was left is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Answer 11

Interpretation Introduction

(c)

Interpretation:

The molarity of a 10.0-mL sample of solution that was evaporated to dryness and 0.29 g of Li2SO4 was left is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Answer 12

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Answer 23

Ch. 7 - Many solutions are found in the home. Some are...Ch. 7 - Prob. 7.2E Ch. 7 - Classify the following as being a solution or not...Ch. 7 - Classify the following as being a solution or not...Ch. 7 - Use the term soluble, insoluble, or immiscible to...Ch. 7 - Use the term soluble, insoluble, or immiscible to...Ch. 7 - Define the term miscible. It is not defined in the...Ch. 7 - Classify the following solutions as unsaturated,...Ch. 7 - Prob. 7.9E Ch. 7 - Prob. 7.10E

Solution Summary: The author explains that the formula to calculate number of moles of solutes is given below.

Chapter 7 Solutions