(a) Interpretation: The molarity of a sample of solid KBr weighing 11.9 g on dissolving in enough distilled water to give 200. mL of solution is to be calculated. Concept introduction: A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume ( % w / v ) , percent volume by volume ( % v / v ) and molarity ( M ) . When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight ( % w / w ) .

Question

5. A solution of sucrose is fermented in a vessel until the evolution of CO2 ceases. Then, the product solution is analyzed and found to contain, 45% ethanol; 5% acetic acid; and 15% glycerin by weight. If the original charge is 500 kg, evaluate; e. The ratio of sucrose to water in the original charge (wt/wt). f. Moles of CO2 evolved. g. Maximum possible amount of ethanol that could be formed. h. Conversion efficiency. i. Per cent excess of excess reactant. Reactions: Inversion reaction: C12H22O11 + H2O →2C6H12O6 Fermentation reaction: C6H12O6 →→2C2H5OH + 2CO2 Formation of acetic acid and glycerin: C6H12O6 + C2H5OH + H₂O→ CH3COOH + 2C3H8O3

Answer 1

Question

Chapter 7, Problem 7.22E

Interpretation Introduction

(a)

Interpretation:

The molarity of a sample of solid KBr weighing 11.9 g on dissolving in enough distilled water to give 200. mL of solution is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Interpretation Introduction

(b)

Interpretation:

The molarity of 14.2-g sample of solid Na2SO4 dissolved in enough water to give 500. mL of solution is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Interpretation Introduction

(c)

Interpretation:

The molarity of a 10.0-mL sample of solution that was evaporated to dryness and 0.29 g of Li2SO4 was left is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

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5. A solution of sucrose is fermented in a vessel until the evolution of CO2 ceases. Then, the product solution is analyzed and found to contain, 45% ethanol; 5% acetic acid; and 15% glycerin by weight. If the original charge is 500 kg, evaluate; e. The ratio of sucrose to water in the original charge (wt/wt). f. Moles of CO2 evolved. g. Maximum possible amount of ethanol that could be formed. h. Conversion efficiency. i. Per cent excess of excess reactant. Reactions: Inversion reaction: C12H22O11 + H2O →2C6H12O6 Fermentation reaction: C6H12O6 →→2C2H5OH + 2CO2 Formation of acetic acid and glycerin: C6H12O6 + C2H5OH + H₂O→ CH3COOH + 2C3H8O3

Show work. don't give Ai generated solution. How many carbons and hydrogens are in the structure?

13. (11pts total) Consider the arrows pointing at three different carbon-carbon bonds in the molecule depicted below. Bond B 2°C. +2°C. cleavage Bond A •CH3 + 26.← Cleavage 2°C. + Bond C +3°C• CH3 2C Cleavage E 2°C. 26. weakest bond Intact molecule Strongest 3°C 20. Gund Largest argest a. (2pts) Which bond between A-C is weakest? Which is strongest? Place answers in appropriate boxes. C Weakest bond A Produces Most Bond Strongest Bond Strongest Gund produces least stable radicals Weakest Stable radical b. (4pts) Consider the relative stability of all cleavage products that form when bonds A, B, AND C are homolytically cleaved/broken. Hint: cleavage products of bonds A, B, and C are all carbon radicals. i. Which ONE cleavage product is the most stable? A condensed or bond line representation is fine. 13°C. formed in bound C cleavage ii. Which ONE cleavage product is the least stable? A condensed or bond line representation is fine. • CH3 methyl radical Formed in Gund A Cleavage c.…

Answer 2

Question

Chapter 7, Problem 7.22E

Interpretation Introduction

(a)

Interpretation:

The molarity of a sample of solid KBr weighing 11.9 g on dissolving in enough distilled water to give 200. mL of solution is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Interpretation Introduction

(b)

Interpretation:

The molarity of 14.2-g sample of solid Na2SO4 dissolved in enough water to give 500. mL of solution is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Interpretation Introduction

(c)

Interpretation:

The molarity of a 10.0-mL sample of solution that was evaporated to dryness and 0.29 g of Li2SO4 was left is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

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Answer 3

Question

Chapter 7, Problem 7.22E

Interpretation Introduction

(a)

Interpretation:

The molarity of a sample of solid KBr weighing 11.9 g on dissolving in enough distilled water to give 200. mL of solution is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Interpretation Introduction

(b)

Interpretation:

The molarity of 14.2-g sample of solid Na2SO4 dissolved in enough water to give 500. mL of solution is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Interpretation Introduction

(c)

Interpretation:

The molarity of a 10.0-mL sample of solution that was evaporated to dryness and 0.29 g of Li2SO4 was left is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

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Answer 4

Question

Chapter 7, Problem 7.22E

Interpretation Introduction

(a)

Interpretation:

The molarity of a sample of solid KBr weighing 11.9 g on dissolving in enough distilled water to give 200. mL of solution is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Interpretation Introduction

(b)

Interpretation:

The molarity of 14.2-g sample of solid Na2SO4 dissolved in enough water to give 500. mL of solution is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Interpretation Introduction

(c)

Interpretation:

The molarity of a 10.0-mL sample of solution that was evaporated to dryness and 0.29 g of Li2SO4 was left is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

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Answer 5

Chapter 7, Problem 7.22E

Interpretation Introduction

(a)

Interpretation:

The molarity of a sample of solid KBr weighing 11.9 g on dissolving in enough distilled water to give 200. mL of solution is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Interpretation Introduction

(b)

Interpretation:

The molarity of 14.2-g sample of solid Na2SO4 dissolved in enough water to give 500. mL of solution is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Interpretation Introduction

(c)

Interpretation:

The molarity of a 10.0-mL sample of solution that was evaporated to dryness and 0.29 g of Li2SO4 was left is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Answer 6

Chapter 7, Problem 7.22E

Interpretation Introduction

(a)

Interpretation:

The molarity of a sample of solid KBr weighing 11.9 g on dissolving in enough distilled water to give 200. mL of solution is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Answer 7

Chapter 7, Problem 7.22E

Interpretation Introduction

(a)

Interpretation:

The molarity of a sample of solid KBr weighing 11.9 g on dissolving in enough distilled water to give 200. mL of solution is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Answer 8

Interpretation Introduction

(b)

Interpretation:

The molarity of 14.2-g sample of solid Na2SO4 dissolved in enough water to give 500. mL of solution is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Answer 9

Interpretation Introduction

(b)

Interpretation:

The molarity of 14.2-g sample of solid Na2SO4 dissolved in enough water to give 500. mL of solution is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Answer 10

Interpretation Introduction

(c)

Interpretation:

The molarity of a 10.0-mL sample of solution that was evaporated to dryness and 0.29 g of Li2SO4 was left is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Answer 11

Interpretation Introduction

(c)

Interpretation:

The molarity of a 10.0-mL sample of solution that was evaporated to dryness and 0.29 g of Li2SO4 was left is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Answer 12

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Answer 23

Ch. 7 - Many solutions are found in the home. Some are...Ch. 7 - Prob. 7.2E Ch. 7 - Classify the following as being a solution or not...Ch. 7 - Classify the following as being a solution or not...Ch. 7 - Use the term soluble, insoluble, or immiscible to...Ch. 7 - Use the term soluble, insoluble, or immiscible to...Ch. 7 - Define the term miscible. It is not defined in the...Ch. 7 - Classify the following solutions as unsaturated,...Ch. 7 - Prob. 7.9E Ch. 7 - Prob. 7.10E

Solution Summary: The author explains that the formula to calculate number of moles of solutes is given below.

Chapter 7 Solutions