(a) Interpretation: The difficulty of that would come on models of the cis and trans isomers of bicyclo [ 3 .1 .0 ] hexane made are to be stated. The model which will form easier is to be identified. The explanation for the corresponding answer is to be stated. Concept introduction: The organic compounds which consist of two cyclic rings fused together are known as bicyclic compounds. Fused rings, bridged rings, and spiro rings are the examples of bicyclic compounds. The stability of bicyclic compounds depends on the ring strain.

Question

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Answer 1

Question

Chapter 7, Problem 7.21P

Interpretation Introduction

(a)

Interpretation:

The difficulty of that would come on models of the cis and trans isomers of $bicyclo[3.1.0]hexane$ made are to be stated. The model which will form easier is to be identified. The explanation for the corresponding answer is to be stated.

Concept introduction:

The organic compounds which consist of two cyclic rings fused together are known as bicyclic compounds. Fused rings, bridged rings, and spiro rings are the examples of bicyclic compounds. The stability of bicyclic compounds depends on the ring strain.

Expert Solution

Answer to Problem 7.21P

The cis isomers of $bicyclo[3.1.0]hexane$ will be formed with less difficulty than the trans isomers of $bicyclo[3.1.0]hexane$ as the formation of three-membered cycles in a case where methyl group are at cis position to each other are easier than the trans position.

Explanation of Solution

The structure of cis and trans isomers of $bicyclo[3.1.0]hexane$ are shown below.

EBK ORGANIC CHEMISTRY, Chapter 7, Problem 7.21P , additional homework tip 1

Figure 1

The formation of trans isomers of $bicyclo[3.1.0]hexane$ is shown below.

EBK ORGANIC CHEMISTRY, Chapter 7, Problem 7.21P , additional homework tip 2

Figure 2

In the formation of trans isomers of $bicyclo[3.1.0]hexane$ , the methyl groups are in two different planes. The angle between them is large. Therefore, it is difficult to form trans isomers of $bicyclo[3.1.0]hexane$ .

The formation of cis isomers of $bicyclo[3.1.0]hexane$ is shown below.

EBK ORGANIC CHEMISTRY, Chapter 7, Problem 7.21P , additional homework tip 3

Figure 3

In the formation of cis isomers of $bicyclo[3.1.0]hexane$ , the methyl groups are in two same planes. The angle between them is not as large as in case of trans. Therefore, cis isomers of $bicyclo[3.1.0]hexane$ will be form easier than the trans isomers of $bicyclo[3.1.0]hexane$ .

Conclusion

It is easier to form a three-membered ring by the methyl at the cis position and the methyl groups at trans position. Therefore, cis isomers of $bicyclo[3.1.0]hexane$ will form easier than the trans isomers of $bicyclo[3.1.0]hexane$ .

Interpretation Introduction

(b)

Interpretation:

The difficulty of that would come on models of $trans-bicyclo[3.1.0]hexane$ and $trans-bicyclo[5.3.0]decane$ make is to be stated. The model which will form easier is to be identified. The explanation for the corresponding answer is to be stated.

Concept introduction:

The organic compounds which consist of two cyclic rings fused together are known as bicyclic compounds. Fused rings, bridged rings and spiro rings are the examples of bicyclic compounds. The stability of bicyclic compounds depends on the ring strain.

Expert Solution

Answer to Problem 7.21P

The compound $trans-bicyclo[3.1.0]hexane$ will form with more difficulties than the compound $trans-bicyclo[5.3.0]decane$ as the methyl groups in case of $trans-bicyclo[3.1.0]hexane$ is movable than in case of formation $trans-bicyclo[5.3.0]decane$ but rigid in case of $trans-bicyclo[3.1.0]hexane$ .

Explanation of Solution

The structure of $trans-bicyclo[3.1.0]hexane$ and $trans-bicyclo[5.3.0]decane$ are shown below.

EBK ORGANIC CHEMISTRY, Chapter 7, Problem 7.21P , additional homework tip 4

Figure 4

The formation of $trans-bicyclo[3.1.0]hexane$ is shown below.

EBK ORGANIC CHEMISTRY, Chapter 7, Problem 7.21P , additional homework tip 5

Figure 2

In the formation of $trans-bicyclo[3.1.0]hexane$ , the methyl groups are in two different planes. The angle between them is large. Therefore, it is difficult to form trans isomers of $bicyclo[3.1.0]hexane$ .

The formation of $trans-bicyclo[5.3.0]decane$ is shown below.

EBK ORGANIC CHEMISTRY, Chapter 7, Problem 7.21P , additional homework tip 6

Figure 5

In the formation of $trans-bicyclo[5.3.0]decane$ , the distance between methyl groups is not large. The angle between them can be change by sigma bond rotation. Therefore, it is easier to form $trans-bicyclo[5.3.0]decane$ than $trans-bicyclo[3.1.0]hexane$ .

Conclusion

The methyl groups in case of $trans-bicyclo[3.1.0]hexane$ is movable than in case of formation $trans-bicyclo[5.3.0]decane$ but rigid in case of $trans-bicyclo[3.1.0]hexane$ . Therefore, compound $trans-bicyclo[3.1.0]hexane$ will form with more difficulties than the compound $trans-bicyclo[5.3.0]decane$ .

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Name the molecules & Identify any chiral center CH3CH2CH2CHCH₂CH₂CH₂CH₂ OH CH₂CHCH2CH3 Br CH3 CH3CHCH2CHCH2CH3 CH3

Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electrons-pushing arrows for the following reaction or mechanistic step(s).

Answer 2

Question

Chapter 7, Problem 7.21P

Interpretation Introduction

(a)

Interpretation:

The difficulty of that would come on models of the cis and trans isomers of $bicyclo[3.1.0]hexane$ made are to be stated. The model which will form easier is to be identified. The explanation for the corresponding answer is to be stated.

Concept introduction:

The organic compounds which consist of two cyclic rings fused together are known as bicyclic compounds. Fused rings, bridged rings, and spiro rings are the examples of bicyclic compounds. The stability of bicyclic compounds depends on the ring strain.

Expert Solution

Answer to Problem 7.21P

The cis isomers of $bicyclo[3.1.0]hexane$ will be formed with less difficulty than the trans isomers of $bicyclo[3.1.0]hexane$ as the formation of three-membered cycles in a case where methyl group are at cis position to each other are easier than the trans position.

Explanation of Solution

The structure of cis and trans isomers of $bicyclo[3.1.0]hexane$ are shown below.

EBK ORGANIC CHEMISTRY, Chapter 7, Problem 7.21P , additional homework tip 1

Figure 1

The formation of trans isomers of $bicyclo[3.1.0]hexane$ is shown below.

EBK ORGANIC CHEMISTRY, Chapter 7, Problem 7.21P , additional homework tip 2

Figure 2

In the formation of trans isomers of $bicyclo[3.1.0]hexane$ , the methyl groups are in two different planes. The angle between them is large. Therefore, it is difficult to form trans isomers of $bicyclo[3.1.0]hexane$ .

The formation of cis isomers of $bicyclo[3.1.0]hexane$ is shown below.

EBK ORGANIC CHEMISTRY, Chapter 7, Problem 7.21P , additional homework tip 3

Figure 3

In the formation of cis isomers of $bicyclo[3.1.0]hexane$ , the methyl groups are in two same planes. The angle between them is not as large as in case of trans. Therefore, cis isomers of $bicyclo[3.1.0]hexane$ will be form easier than the trans isomers of $bicyclo[3.1.0]hexane$ .

Conclusion

It is easier to form a three-membered ring by the methyl at the cis position and the methyl groups at trans position. Therefore, cis isomers of $bicyclo[3.1.0]hexane$ will form easier than the trans isomers of $bicyclo[3.1.0]hexane$ .

Interpretation Introduction

(b)

Interpretation:

The difficulty of that would come on models of $trans-bicyclo[3.1.0]hexane$ and $trans-bicyclo[5.3.0]decane$ make is to be stated. The model which will form easier is to be identified. The explanation for the corresponding answer is to be stated.

Concept introduction:

The organic compounds which consist of two cyclic rings fused together are known as bicyclic compounds. Fused rings, bridged rings and spiro rings are the examples of bicyclic compounds. The stability of bicyclic compounds depends on the ring strain.

Expert Solution

Answer to Problem 7.21P

The compound $trans-bicyclo[3.1.0]hexane$ will form with more difficulties than the compound $trans-bicyclo[5.3.0]decane$ as the methyl groups in case of $trans-bicyclo[3.1.0]hexane$ is movable than in case of formation $trans-bicyclo[5.3.0]decane$ but rigid in case of $trans-bicyclo[3.1.0]hexane$ .

Explanation of Solution

The structure of $trans-bicyclo[3.1.0]hexane$ and $trans-bicyclo[5.3.0]decane$ are shown below.

EBK ORGANIC CHEMISTRY, Chapter 7, Problem 7.21P , additional homework tip 4

Figure 4

The formation of $trans-bicyclo[3.1.0]hexane$ is shown below.

EBK ORGANIC CHEMISTRY, Chapter 7, Problem 7.21P , additional homework tip 5

Figure 2

In the formation of $trans-bicyclo[3.1.0]hexane$ , the methyl groups are in two different planes. The angle between them is large. Therefore, it is difficult to form trans isomers of $bicyclo[3.1.0]hexane$ .

The formation of $trans-bicyclo[5.3.0]decane$ is shown below.

EBK ORGANIC CHEMISTRY, Chapter 7, Problem 7.21P , additional homework tip 6

Figure 5

In the formation of $trans-bicyclo[5.3.0]decane$ , the distance between methyl groups is not large. The angle between them can be change by sigma bond rotation. Therefore, it is easier to form $trans-bicyclo[5.3.0]decane$ than $trans-bicyclo[3.1.0]hexane$ .

Conclusion

The methyl groups in case of $trans-bicyclo[3.1.0]hexane$ is movable than in case of formation $trans-bicyclo[5.3.0]decane$ but rigid in case of $trans-bicyclo[3.1.0]hexane$ . Therefore, compound $trans-bicyclo[3.1.0]hexane$ will form with more difficulties than the compound $trans-bicyclo[5.3.0]decane$ .

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Answer 3

Question

Chapter 7, Problem 7.21P

Interpretation Introduction

(a)

Interpretation:

The difficulty of that would come on models of the cis and trans isomers of $bicyclo[3.1.0]hexane$ made are to be stated. The model which will form easier is to be identified. The explanation for the corresponding answer is to be stated.

Concept introduction:

The organic compounds which consist of two cyclic rings fused together are known as bicyclic compounds. Fused rings, bridged rings, and spiro rings are the examples of bicyclic compounds. The stability of bicyclic compounds depends on the ring strain.

Expert Solution

Answer to Problem 7.21P

The cis isomers of $bicyclo[3.1.0]hexane$ will be formed with less difficulty than the trans isomers of $bicyclo[3.1.0]hexane$ as the formation of three-membered cycles in a case where methyl group are at cis position to each other are easier than the trans position.

Explanation of Solution

The structure of cis and trans isomers of $bicyclo[3.1.0]hexane$ are shown below.

EBK ORGANIC CHEMISTRY, Chapter 7, Problem 7.21P , additional homework tip 1

Figure 1

The formation of trans isomers of $bicyclo[3.1.0]hexane$ is shown below.

EBK ORGANIC CHEMISTRY, Chapter 7, Problem 7.21P , additional homework tip 2

Figure 2

In the formation of trans isomers of $bicyclo[3.1.0]hexane$ , the methyl groups are in two different planes. The angle between them is large. Therefore, it is difficult to form trans isomers of $bicyclo[3.1.0]hexane$ .

The formation of cis isomers of $bicyclo[3.1.0]hexane$ is shown below.

EBK ORGANIC CHEMISTRY, Chapter 7, Problem 7.21P , additional homework tip 3

Figure 3

In the formation of cis isomers of $bicyclo[3.1.0]hexane$ , the methyl groups are in two same planes. The angle between them is not as large as in case of trans. Therefore, cis isomers of $bicyclo[3.1.0]hexane$ will be form easier than the trans isomers of $bicyclo[3.1.0]hexane$ .

Conclusion

It is easier to form a three-membered ring by the methyl at the cis position and the methyl groups at trans position. Therefore, cis isomers of $bicyclo[3.1.0]hexane$ will form easier than the trans isomers of $bicyclo[3.1.0]hexane$ .

Interpretation Introduction

(b)

Interpretation:

The difficulty of that would come on models of $trans-bicyclo[3.1.0]hexane$ and $trans-bicyclo[5.3.0]decane$ make is to be stated. The model which will form easier is to be identified. The explanation for the corresponding answer is to be stated.

Concept introduction:

The organic compounds which consist of two cyclic rings fused together are known as bicyclic compounds. Fused rings, bridged rings and spiro rings are the examples of bicyclic compounds. The stability of bicyclic compounds depends on the ring strain.

Expert Solution

Answer to Problem 7.21P

The compound $trans-bicyclo[3.1.0]hexane$ will form with more difficulties than the compound $trans-bicyclo[5.3.0]decane$ as the methyl groups in case of $trans-bicyclo[3.1.0]hexane$ is movable than in case of formation $trans-bicyclo[5.3.0]decane$ but rigid in case of $trans-bicyclo[3.1.0]hexane$ .

Explanation of Solution

The structure of $trans-bicyclo[3.1.0]hexane$ and $trans-bicyclo[5.3.0]decane$ are shown below.

EBK ORGANIC CHEMISTRY, Chapter 7, Problem 7.21P , additional homework tip 4

Figure 4

The formation of $trans-bicyclo[3.1.0]hexane$ is shown below.

EBK ORGANIC CHEMISTRY, Chapter 7, Problem 7.21P , additional homework tip 5

Figure 2

In the formation of $trans-bicyclo[3.1.0]hexane$ , the methyl groups are in two different planes. The angle between them is large. Therefore, it is difficult to form trans isomers of $bicyclo[3.1.0]hexane$ .

The formation of $trans-bicyclo[5.3.0]decane$ is shown below.

EBK ORGANIC CHEMISTRY, Chapter 7, Problem 7.21P , additional homework tip 6

Figure 5

In the formation of $trans-bicyclo[5.3.0]decane$ , the distance between methyl groups is not large. The angle between them can be change by sigma bond rotation. Therefore, it is easier to form $trans-bicyclo[5.3.0]decane$ than $trans-bicyclo[3.1.0]hexane$ .

Conclusion

The methyl groups in case of $trans-bicyclo[3.1.0]hexane$ is movable than in case of formation $trans-bicyclo[5.3.0]decane$ but rigid in case of $trans-bicyclo[3.1.0]hexane$ . Therefore, compound $trans-bicyclo[3.1.0]hexane$ will form with more difficulties than the compound $trans-bicyclo[5.3.0]decane$ .

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Answer 4

Question

Chapter 7, Problem 7.21P

Interpretation Introduction

(a)

Interpretation:

The difficulty of that would come on models of the cis and trans isomers of $bicyclo[3.1.0]hexane$ made are to be stated. The model which will form easier is to be identified. The explanation for the corresponding answer is to be stated.

Concept introduction:

The organic compounds which consist of two cyclic rings fused together are known as bicyclic compounds. Fused rings, bridged rings, and spiro rings are the examples of bicyclic compounds. The stability of bicyclic compounds depends on the ring strain.

Expert Solution

Answer to Problem 7.21P

The cis isomers of $bicyclo[3.1.0]hexane$ will be formed with less difficulty than the trans isomers of $bicyclo[3.1.0]hexane$ as the formation of three-membered cycles in a case where methyl group are at cis position to each other are easier than the trans position.

Explanation of Solution

The structure of cis and trans isomers of $bicyclo[3.1.0]hexane$ are shown below.

EBK ORGANIC CHEMISTRY, Chapter 7, Problem 7.21P , additional homework tip 1

Figure 1

The formation of trans isomers of $bicyclo[3.1.0]hexane$ is shown below.

EBK ORGANIC CHEMISTRY, Chapter 7, Problem 7.21P , additional homework tip 2

Figure 2

In the formation of trans isomers of $bicyclo[3.1.0]hexane$ , the methyl groups are in two different planes. The angle between them is large. Therefore, it is difficult to form trans isomers of $bicyclo[3.1.0]hexane$ .

The formation of cis isomers of $bicyclo[3.1.0]hexane$ is shown below.

EBK ORGANIC CHEMISTRY, Chapter 7, Problem 7.21P , additional homework tip 3

Figure 3

In the formation of cis isomers of $bicyclo[3.1.0]hexane$ , the methyl groups are in two same planes. The angle between them is not as large as in case of trans. Therefore, cis isomers of $bicyclo[3.1.0]hexane$ will be form easier than the trans isomers of $bicyclo[3.1.0]hexane$ .

Conclusion

It is easier to form a three-membered ring by the methyl at the cis position and the methyl groups at trans position. Therefore, cis isomers of $bicyclo[3.1.0]hexane$ will form easier than the trans isomers of $bicyclo[3.1.0]hexane$ .

Interpretation Introduction

(b)

Interpretation:

The difficulty of that would come on models of $trans-bicyclo[3.1.0]hexane$ and $trans-bicyclo[5.3.0]decane$ make is to be stated. The model which will form easier is to be identified. The explanation for the corresponding answer is to be stated.

Concept introduction:

The organic compounds which consist of two cyclic rings fused together are known as bicyclic compounds. Fused rings, bridged rings and spiro rings are the examples of bicyclic compounds. The stability of bicyclic compounds depends on the ring strain.

Expert Solution

Answer to Problem 7.21P

The compound $trans-bicyclo[3.1.0]hexane$ will form with more difficulties than the compound $trans-bicyclo[5.3.0]decane$ as the methyl groups in case of $trans-bicyclo[3.1.0]hexane$ is movable than in case of formation $trans-bicyclo[5.3.0]decane$ but rigid in case of $trans-bicyclo[3.1.0]hexane$ .

Explanation of Solution

The structure of $trans-bicyclo[3.1.0]hexane$ and $trans-bicyclo[5.3.0]decane$ are shown below.

EBK ORGANIC CHEMISTRY, Chapter 7, Problem 7.21P , additional homework tip 4

Figure 4

The formation of $trans-bicyclo[3.1.0]hexane$ is shown below.

EBK ORGANIC CHEMISTRY, Chapter 7, Problem 7.21P , additional homework tip 5

Figure 2

In the formation of $trans-bicyclo[3.1.0]hexane$ , the methyl groups are in two different planes. The angle between them is large. Therefore, it is difficult to form trans isomers of $bicyclo[3.1.0]hexane$ .

The formation of $trans-bicyclo[5.3.0]decane$ is shown below.

EBK ORGANIC CHEMISTRY, Chapter 7, Problem 7.21P , additional homework tip 6

Figure 5

In the formation of $trans-bicyclo[5.3.0]decane$ , the distance between methyl groups is not large. The angle between them can be change by sigma bond rotation. Therefore, it is easier to form $trans-bicyclo[5.3.0]decane$ than $trans-bicyclo[3.1.0]hexane$ .

Conclusion

The methyl groups in case of $trans-bicyclo[3.1.0]hexane$ is movable than in case of formation $trans-bicyclo[5.3.0]decane$ but rigid in case of $trans-bicyclo[3.1.0]hexane$ . Therefore, compound $trans-bicyclo[3.1.0]hexane$ will form with more difficulties than the compound $trans-bicyclo[5.3.0]decane$ .

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Answer 5

Chapter 7, Problem 7.21P

Interpretation Introduction

(a)

Interpretation:

The difficulty of that would come on models of the cis and trans isomers of $bicyclo[3.1.0]hexane$ made are to be stated. The model which will form easier is to be identified. The explanation for the corresponding answer is to be stated.

Concept introduction:

The organic compounds which consist of two cyclic rings fused together are known as bicyclic compounds. Fused rings, bridged rings, and spiro rings are the examples of bicyclic compounds. The stability of bicyclic compounds depends on the ring strain.

Expert Solution

Answer to Problem 7.21P

The cis isomers of $bicyclo[3.1.0]hexane$ will be formed with less difficulty than the trans isomers of $bicyclo[3.1.0]hexane$ as the formation of three-membered cycles in a case where methyl group are at cis position to each other are easier than the trans position.

Explanation of Solution

The structure of cis and trans isomers of $bicyclo[3.1.0]hexane$ are shown below.

EBK ORGANIC CHEMISTRY, Chapter 7, Problem 7.21P , additional homework tip 1

Figure 1

The formation of trans isomers of $bicyclo[3.1.0]hexane$ is shown below.

EBK ORGANIC CHEMISTRY, Chapter 7, Problem 7.21P , additional homework tip 2

Figure 2

In the formation of trans isomers of $bicyclo[3.1.0]hexane$ , the methyl groups are in two different planes. The angle between them is large. Therefore, it is difficult to form trans isomers of $bicyclo[3.1.0]hexane$ .

The formation of cis isomers of $bicyclo[3.1.0]hexane$ is shown below.

EBK ORGANIC CHEMISTRY, Chapter 7, Problem 7.21P , additional homework tip 3

Figure 3

In the formation of cis isomers of $bicyclo[3.1.0]hexane$ , the methyl groups are in two same planes. The angle between them is not as large as in case of trans. Therefore, cis isomers of $bicyclo[3.1.0]hexane$ will be form easier than the trans isomers of $bicyclo[3.1.0]hexane$ .

Conclusion

It is easier to form a three-membered ring by the methyl at the cis position and the methyl groups at trans position. Therefore, cis isomers of $bicyclo[3.1.0]hexane$ will form easier than the trans isomers of $bicyclo[3.1.0]hexane$ .

Interpretation Introduction

(b)

Interpretation:

The difficulty of that would come on models of $trans-bicyclo[3.1.0]hexane$ and $trans-bicyclo[5.3.0]decane$ make is to be stated. The model which will form easier is to be identified. The explanation for the corresponding answer is to be stated.

Concept introduction:

The organic compounds which consist of two cyclic rings fused together are known as bicyclic compounds. Fused rings, bridged rings and spiro rings are the examples of bicyclic compounds. The stability of bicyclic compounds depends on the ring strain.

Expert Solution

Answer to Problem 7.21P

The compound $trans-bicyclo[3.1.0]hexane$ will form with more difficulties than the compound $trans-bicyclo[5.3.0]decane$ as the methyl groups in case of $trans-bicyclo[3.1.0]hexane$ is movable than in case of formation $trans-bicyclo[5.3.0]decane$ but rigid in case of $trans-bicyclo[3.1.0]hexane$ .

Explanation of Solution

The structure of $trans-bicyclo[3.1.0]hexane$ and $trans-bicyclo[5.3.0]decane$ are shown below.

EBK ORGANIC CHEMISTRY, Chapter 7, Problem 7.21P , additional homework tip 4

Figure 4

The formation of $trans-bicyclo[3.1.0]hexane$ is shown below.

EBK ORGANIC CHEMISTRY, Chapter 7, Problem 7.21P , additional homework tip 5

Figure 2

In the formation of $trans-bicyclo[3.1.0]hexane$ , the methyl groups are in two different planes. The angle between them is large. Therefore, it is difficult to form trans isomers of $bicyclo[3.1.0]hexane$ .

The formation of $trans-bicyclo[5.3.0]decane$ is shown below.

EBK ORGANIC CHEMISTRY, Chapter 7, Problem 7.21P , additional homework tip 6

Figure 5

In the formation of $trans-bicyclo[5.3.0]decane$ , the distance between methyl groups is not large. The angle between them can be change by sigma bond rotation. Therefore, it is easier to form $trans-bicyclo[5.3.0]decane$ than $trans-bicyclo[3.1.0]hexane$ .

Conclusion

The methyl groups in case of $trans-bicyclo[3.1.0]hexane$ is movable than in case of formation $trans-bicyclo[5.3.0]decane$ but rigid in case of $trans-bicyclo[3.1.0]hexane$ . Therefore, compound $trans-bicyclo[3.1.0]hexane$ will form with more difficulties than the compound $trans-bicyclo[5.3.0]decane$ .

Answer 6

Chapter 7, Problem 7.21P

Interpretation Introduction

(a)

Interpretation:

The difficulty of that would come on models of the cis and trans isomers of $bicyclo[3.1.0]hexane$ made are to be stated. The model which will form easier is to be identified. The explanation for the corresponding answer is to be stated.

Concept introduction:

The organic compounds which consist of two cyclic rings fused together are known as bicyclic compounds. Fused rings, bridged rings, and spiro rings are the examples of bicyclic compounds. The stability of bicyclic compounds depends on the ring strain.

Expert Solution

Answer to Problem 7.21P

The cis isomers of $bicyclo[3.1.0]hexane$ will be formed with less difficulty than the trans isomers of $bicyclo[3.1.0]hexane$ as the formation of three-membered cycles in a case where methyl group are at cis position to each other are easier than the trans position.

Explanation of Solution

The structure of cis and trans isomers of $bicyclo[3.1.0]hexane$ are shown below.

EBK ORGANIC CHEMISTRY, Chapter 7, Problem 7.21P , additional homework tip 1

Figure 1

The formation of trans isomers of $bicyclo[3.1.0]hexane$ is shown below.

EBK ORGANIC CHEMISTRY, Chapter 7, Problem 7.21P , additional homework tip 2

Figure 2

In the formation of trans isomers of $bicyclo[3.1.0]hexane$ , the methyl groups are in two different planes. The angle between them is large. Therefore, it is difficult to form trans isomers of $bicyclo[3.1.0]hexane$ .

The formation of cis isomers of $bicyclo[3.1.0]hexane$ is shown below.

EBK ORGANIC CHEMISTRY, Chapter 7, Problem 7.21P , additional homework tip 3

Figure 3

In the formation of cis isomers of $bicyclo[3.1.0]hexane$ , the methyl groups are in two same planes. The angle between them is not as large as in case of trans. Therefore, cis isomers of $bicyclo[3.1.0]hexane$ will be form easier than the trans isomers of $bicyclo[3.1.0]hexane$ .

Conclusion

It is easier to form a three-membered ring by the methyl at the cis position and the methyl groups at trans position. Therefore, cis isomers of $bicyclo[3.1.0]hexane$ will form easier than the trans isomers of $bicyclo[3.1.0]hexane$ .

Answer 7

Chapter 7, Problem 7.21P

Interpretation Introduction

(a)

Interpretation:

The difficulty of that would come on models of the cis and trans isomers of $bicyclo[3.1.0]hexane$ made are to be stated. The model which will form easier is to be identified. The explanation for the corresponding answer is to be stated.

Concept introduction:

The organic compounds which consist of two cyclic rings fused together are known as bicyclic compounds. Fused rings, bridged rings, and spiro rings are the examples of bicyclic compounds. The stability of bicyclic compounds depends on the ring strain.

Answer 8

Expert Solution

Answer to Problem 7.21P

The cis isomers of $bicyclo[3.1.0]hexane$ will be formed with less difficulty than the trans isomers of $bicyclo[3.1.0]hexane$ as the formation of three-membered cycles in a case where methyl group are at cis position to each other are easier than the trans position.

Answer 9

Expert Solution

Answer 10

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

The structure of cis and trans isomers of $bicyclo[3.1.0]hexane$ are shown below.

EBK ORGANIC CHEMISTRY, Chapter 7, Problem 7.21P , additional homework tip 1

Figure 1

The formation of trans isomers of $bicyclo[3.1.0]hexane$ is shown below.

EBK ORGANIC CHEMISTRY, Chapter 7, Problem 7.21P , additional homework tip 2

Figure 2

In the formation of trans isomers of $bicyclo[3.1.0]hexane$ , the methyl groups are in two different planes. The angle between them is large. Therefore, it is difficult to form trans isomers of $bicyclo[3.1.0]hexane$ .

The formation of cis isomers of $bicyclo[3.1.0]hexane$ is shown below.

EBK ORGANIC CHEMISTRY, Chapter 7, Problem 7.21P , additional homework tip 3

Figure 3

In the formation of cis isomers of $bicyclo[3.1.0]hexane$ , the methyl groups are in two same planes. The angle between them is not as large as in case of trans. Therefore, cis isomers of $bicyclo[3.1.0]hexane$ will be form easier than the trans isomers of $bicyclo[3.1.0]hexane$ .

Answer 13

Conclusion

It is easier to form a three-membered ring by the methyl at the cis position and the methyl groups at trans position. Therefore, cis isomers of $bicyclo[3.1.0]hexane$ will form easier than the trans isomers of $bicyclo[3.1.0]hexane$ .

Answer 14

Interpretation Introduction

(b)

Interpretation:

The difficulty of that would come on models of $trans-bicyclo[3.1.0]hexane$ and $trans-bicyclo[5.3.0]decane$ make is to be stated. The model which will form easier is to be identified. The explanation for the corresponding answer is to be stated.

Concept introduction:

The organic compounds which consist of two cyclic rings fused together are known as bicyclic compounds. Fused rings, bridged rings and spiro rings are the examples of bicyclic compounds. The stability of bicyclic compounds depends on the ring strain.

Expert Solution

Answer to Problem 7.21P

The compound $trans-bicyclo[3.1.0]hexane$ will form with more difficulties than the compound $trans-bicyclo[5.3.0]decane$ as the methyl groups in case of $trans-bicyclo[3.1.0]hexane$ is movable than in case of formation $trans-bicyclo[5.3.0]decane$ but rigid in case of $trans-bicyclo[3.1.0]hexane$ .

Explanation of Solution

The structure of $trans-bicyclo[3.1.0]hexane$ and $trans-bicyclo[5.3.0]decane$ are shown below.

EBK ORGANIC CHEMISTRY, Chapter 7, Problem 7.21P , additional homework tip 4

Figure 4

The formation of $trans-bicyclo[3.1.0]hexane$ is shown below.

EBK ORGANIC CHEMISTRY, Chapter 7, Problem 7.21P , additional homework tip 5

Figure 2

In the formation of $trans-bicyclo[3.1.0]hexane$ , the methyl groups are in two different planes. The angle between them is large. Therefore, it is difficult to form trans isomers of $bicyclo[3.1.0]hexane$ .

The formation of $trans-bicyclo[5.3.0]decane$ is shown below.

EBK ORGANIC CHEMISTRY, Chapter 7, Problem 7.21P , additional homework tip 6

Figure 5

In the formation of $trans-bicyclo[5.3.0]decane$ , the distance between methyl groups is not large. The angle between them can be change by sigma bond rotation. Therefore, it is easier to form $trans-bicyclo[5.3.0]decane$ than $trans-bicyclo[3.1.0]hexane$ .

Conclusion

The methyl groups in case of $trans-bicyclo[3.1.0]hexane$ is movable than in case of formation $trans-bicyclo[5.3.0]decane$ but rigid in case of $trans-bicyclo[3.1.0]hexane$ . Therefore, compound $trans-bicyclo[3.1.0]hexane$ will form with more difficulties than the compound $trans-bicyclo[5.3.0]decane$ .

Answer 15

Interpretation Introduction

(b)

Interpretation:

The difficulty of that would come on models of $trans-bicyclo[3.1.0]hexane$ and $trans-bicyclo[5.3.0]decane$ make is to be stated. The model which will form easier is to be identified. The explanation for the corresponding answer is to be stated.

Concept introduction:

The organic compounds which consist of two cyclic rings fused together are known as bicyclic compounds. Fused rings, bridged rings and spiro rings are the examples of bicyclic compounds. The stability of bicyclic compounds depends on the ring strain.

Answer 16

Expert Solution

Answer to Problem 7.21P

The compound $trans-bicyclo[3.1.0]hexane$ will form with more difficulties than the compound $trans-bicyclo[5.3.0]decane$ as the methyl groups in case of $trans-bicyclo[3.1.0]hexane$ is movable than in case of formation $trans-bicyclo[5.3.0]decane$ but rigid in case of $trans-bicyclo[3.1.0]hexane$ .

Answer 17

Expert Solution

Answer 18

Expert Solution

Answer 19

Expert Solution

Answer 20

Explanation of Solution

The structure of $trans-bicyclo[3.1.0]hexane$ and $trans-bicyclo[5.3.0]decane$ are shown below.

EBK ORGANIC CHEMISTRY, Chapter 7, Problem 7.21P , additional homework tip 4

Figure 4

The formation of $trans-bicyclo[3.1.0]hexane$ is shown below.

EBK ORGANIC CHEMISTRY, Chapter 7, Problem 7.21P , additional homework tip 5

Figure 2

In the formation of $trans-bicyclo[3.1.0]hexane$ , the methyl groups are in two different planes. The angle between them is large. Therefore, it is difficult to form trans isomers of $bicyclo[3.1.0]hexane$ .

The formation of $trans-bicyclo[5.3.0]decane$ is shown below.

EBK ORGANIC CHEMISTRY, Chapter 7, Problem 7.21P , additional homework tip 6

Figure 5

In the formation of $trans-bicyclo[5.3.0]decane$ , the distance between methyl groups is not large. The angle between them can be change by sigma bond rotation. Therefore, it is easier to form $trans-bicyclo[5.3.0]decane$ than $trans-bicyclo[3.1.0]hexane$ .

Answer 21

Conclusion

The methyl groups in case of $trans-bicyclo[3.1.0]hexane$ is movable than in case of formation $trans-bicyclo[5.3.0]decane$ but rigid in case of $trans-bicyclo[3.1.0]hexane$ . Therefore, compound $trans-bicyclo[3.1.0]hexane$ will form with more difficulties than the compound $trans-bicyclo[5.3.0]decane$ .

Answer 22

Ch. 7 - Prob. 7.1P Ch. 7 - Prob. 7.2P Ch. 7 - Prob. 7.3P Ch. 7 - Prob. 7.4P Ch. 7 - Prob. 7.5P Ch. 7 - Prob. 7.6P Ch. 7 - Prob. 7.7P Ch. 7 - Prob. 7.8P Ch. 7 - Prob. 7.9P Ch. 7 - Prob. 7.10P

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