Industrial Plastics: Theory and Applications
6th Edition
ISBN: 9781285061238
Author: Lokensgard, Erik
Publisher: Delmar Cengage Learning
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Question
Chapter 7, Problem 7.1Q
Interpretation Introduction
Interpretation:
The given statement should be completed.
Concept Introduction:
Plastics are organic polymers of high molecular mass substances. Plastics are durable, lightweight, resistant to corrosion, chemical stress and have many more advantageous properties. But industrially special ingredients are added to plastic to enhance and alter to get desired properties to plastics.
Expert Solution & Answer
Answer to Problem 7.1Q
Additives, Reinforcements and Fillers.
Explanation of Solution
Given information:
______ are used for improvement or extension of the properties of plastics.
The special ingredients added to plastics in order to enhance or alter properties of plastics fall into three categories as additives, reinforcements and fillers. These ingredients improveprocess ability, surface finish, thermal and electrical conductivity, reduces material cost and many other properties.
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LATIHAN
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The power generation unit in a plant uses a hot exhaust gas from another process to produce work. The gas enters at 10 bar and 350°C and exits at 1 bar and 40°C. The process produces a net amount of work equal to 4500 J/mol and it exchanges an unknown amount of heat with the surroundings. 1.1 Determine the amount of heat exchanged with the surroundings. Is this heat absorbed or rejected by the system? 1.2 Calculate the entropy change of the exhaust gas. 1.3 As a young and ambitious chemical engineer, you seek ways to improve the process. What is the maximum amount of work that you could extract from this system? Assume that the inlet and outlet conditions of the exhaust gas remain the same.
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Latihan mandiri
Reaktor fluidisasi menggunakan katalis padat dengan diameter
partikel 0,25 mm, rapat massa 1,50 g/ml, sperisitas 0,90. Pada
kondisi unggun diam, porositas 0,35, tinggi unggun 2 m. Gas
masuk dari bagian bawah reaktor pada suhu 600°C pada
viskositas 0,025 CP serta rapat massa 0,22 lb/cuft. Pada fluidisasi
minimum, porositas tercapai pada 0,45. Hitung
Hitung
a. Laju alir semu minimum (VM) gas masuk kolom fluidisasi !
b. Tinggi unggun jika Vo = 2 VM
c. Pressure drop pada kondisi Vo = 2,5 VM
<
1 m
= 3,28084 ft
1 g/ml
= 62,43 lbm/ft³
1 cp
gc
= 6,7197 × 10-4 lbm/ft.s
= 32,174 ft/s²
=
Chapter 7 Solutions
Industrial Plastics: Theory and Applications
Ch. 7 - Prob. 7.1QCh. 7 - Prob. 7.2QCh. 7 - Prob. 7.3QCh. 7 - Prob. 7.4QCh. 7 - Prob. 7.5QCh. 7 - Prob. 7.6QCh. 7 - Prob. 7.7QCh. 7 - Prob. 7.8QCh. 7 - Prob. 7.9QCh. 7 - Prob. 7.10Q
Ch. 7 - Prob. 7.11QCh. 7 - Prob. 7.12QCh. 7 - Prob. 7.13QCh. 7 - Prob. 7.14QCh. 7 - Prob. 7.15QCh. 7 - Prob. 7.16QCh. 7 - Prob. 7.17QCh. 7 - Prob. 7.18QCh. 7 - Prob. 7.19QCh. 7 - Prob. 7.20QCh. 7 - Prob. 7.21QCh. 7 - Prob. 7.22QCh. 7 - Prob. 7.23QCh. 7 - Prob. 7.24QCh. 7 - Prob. 7.25QCh. 7 - Prob. 7.26QCh. 7 - Prob. 7.27QCh. 7 - Prob. 7.28QCh. 7 - Prob. 7.29QCh. 7 - Prob. 7.30QCh. 7 - Prob. 7.31Q
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