A deck of n cards numbered 1 through n is thoroughly shuffled so that all possible n! orderings can be assumed to be equally likely. Suppose you are to make n guesses sequentially, where the i th one is a guess of the card in position i. Let n denote the number of correct guesses. a. If you are not given any information about your earlier guesses, show that for any strategy, E [ N ] = 1 . b. Suppose that after each guess you are shown the card that was in the position in question. What do you think is the best strategy? Show that under this strategy, E [ N ] = 1 n + 1 n − 1 + ... + 1 ≈ ∫ 1 n 1 x d x = log n c. Suppose that you are told after each guess whether you are right or wrong. In this case, it can be shown that the strategy that maximizes E[N] is one that keeps on guessing the same card until you are told you are correct and then changes to a new card. For this strategy, show that E [ N ] = 1 + 1 2 ! + 1 3 ! + ... + 1 n ! ≈ e − 1 Hint: For all parts, express N as the sum of indicator (that is, Bernoulli) random variables.
A deck of n cards numbered 1 through n is thoroughly shuffled so that all possible n! orderings can be assumed to be equally likely. Suppose you are to make n guesses sequentially, where the i th one is a guess of the card in position i. Let n denote the number of correct guesses. a. If you are not given any information about your earlier guesses, show that for any strategy, E [ N ] = 1 . b. Suppose that after each guess you are shown the card that was in the position in question. What do you think is the best strategy? Show that under this strategy, E [ N ] = 1 n + 1 n − 1 + ... + 1 ≈ ∫ 1 n 1 x d x = log n c. Suppose that you are told after each guess whether you are right or wrong. In this case, it can be shown that the strategy that maximizes E[N] is one that keeps on guessing the same card until you are told you are correct and then changes to a new card. For this strategy, show that E [ N ] = 1 + 1 2 ! + 1 3 ! + ... + 1 n ! ≈ e − 1 Hint: For all parts, express N as the sum of indicator (that is, Bernoulli) random variables.
Solution Summary: The author shows the expected value of N for any strategy.
A deck of n cards numbered 1 through n is thoroughly shuffled so that all possible n! orderings can be assumed to be equally likely. Suppose you are to make n guesses sequentially, where the ith one is a guess of the card in position i. Let n denote the number of correct guesses.
a. If you are not given any information about your earlier guesses, show that for any strategy,
E
[
N
]
=
1
.
b. Suppose that after each guess you are shown the card that was in the position in question. What do you think is the best strategy? Show that under this strategy,
E
[
N
]
=
1
n
+
1
n
−
1
+
...
+
1
≈
∫
1
n
1
x
d
x
=
log
n
c. Suppose that you are told after each guess whether you are right or wrong. In this case, it can be shown that the strategy that maximizes E[N] is one that keeps on guessing the same card until you are told you are correct and then changes to a new card. For this strategy, show that
E
[
N
]
=
1
+
1
2
!
+
1
3
!
+
...
+
1
n
!
≈
e
−
1
Hint: For all parts, express
N as the sum of indicator (that is, Bernoulli) random variables.
Q1. A group of five applicants for a pair of identical jobs consists of three men and two
women. The employer is to select two of the five applicants for the jobs. Let S
denote the set of all possible outcomes for the employer's selection. Let A denote
the subset of outcomes corresponding to the selection of two men and B the subset
corresponding to the selection of at least one woman. List the outcomes in A, B,
AUB, AN B, and An B. (Denote the different men and women by M₁, M2, M3
and W₁, W2, respectively.)
Q3 (8 points)
Q3. A survey classified a large number of adults according to whether they were diag-
nosed as needing eyeglasses to correct their reading vision and whether they use
eyeglasses when reading. The proportions falling into the four resulting categories
are given in the following table:
Use Eyeglasses for Reading
Needs glasses Yes
No
Yes
0.44
0.14
No
0.02
0.40
If a single adult is selected from the large group, find the probabilities of the events
defined below. The adult
(a) needs glasses.
(b) needs glasses but does not use them.
(c) uses glasses whether the glasses are needed or not.
4. (i) Let a discrete sample space be given by
N = {W1, W2, W3, W4},
and let a probability measure P on be given by
P(w1) = 0.2, P(w2) = 0.2, P(w3) = 0.5, P(wa) = 0.1.
Consider the random variables X1, X2 → R defined by
X₁(w1) = 1, X₁(w2) = 2,
X2(w1) = 2, X2 (w2) = 2,
Find the joint distribution of X1, X2.
(ii)
X1(W3) = 1, X₁(w4) = 1,
X2(W3) = 1, X2(w4) = 2.
[4 Marks]
Let Y, Z be random variables on a probability space (, F, P).
Let the random vector (Y, Z) take on values in the set [0, 1] x [0,2] and let the
joint distribution of Y, Z on [0, 1] x [0,2] be given by
1
dPy,z (y, z) ==(y²z+yz2) dy dz.
harks 12 Find the distribution Py of the random variable Y.
[8 Marks]
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, probability and related others by exploring similar questions and additional content below.
Discrete Distributions: Binomial, Poisson and Hypergeometric | Statistics for Data Science; Author: Dr. Bharatendra Rai;https://www.youtube.com/watch?v=lHhyy4JMigg;License: Standard Youtube License