A deck of n cards numbered 1 through n is thoroughly shuffled so that all possible n! orderings can be assumed to be equally likely. Suppose you are to make n guesses sequentially, where the i th one is a guess of the card in position i. Let n denote the number of correct guesses. a. If you are not given any information about your earlier guesses, show that for any strategy, E [ N ] = 1 . b. Suppose that after each guess you are shown the card that was in the position in question. What do you think is the best strategy? Show that under this strategy, E [ N ] = 1 n + 1 n − 1 + ... + 1 ≈ ∫ 1 n 1 x d x = log n c. Suppose that you are told after each guess whether you are right or wrong. In this case, it can be shown that the strategy that maximizes E[N] is one that keeps on guessing the same card until you are told you are correct and then changes to a new card. For this strategy, show that E [ N ] = 1 + 1 2 ! + 1 3 ! + ... + 1 n ! ≈ e − 1 Hint: For all parts, express N as the sum of indicator (that is, Bernoulli) random variables.
A deck of n cards numbered 1 through n is thoroughly shuffled so that all possible n! orderings can be assumed to be equally likely. Suppose you are to make n guesses sequentially, where the i th one is a guess of the card in position i. Let n denote the number of correct guesses. a. If you are not given any information about your earlier guesses, show that for any strategy, E [ N ] = 1 . b. Suppose that after each guess you are shown the card that was in the position in question. What do you think is the best strategy? Show that under this strategy, E [ N ] = 1 n + 1 n − 1 + ... + 1 ≈ ∫ 1 n 1 x d x = log n c. Suppose that you are told after each guess whether you are right or wrong. In this case, it can be shown that the strategy that maximizes E[N] is one that keeps on guessing the same card until you are told you are correct and then changes to a new card. For this strategy, show that E [ N ] = 1 + 1 2 ! + 1 3 ! + ... + 1 n ! ≈ e − 1 Hint: For all parts, express N as the sum of indicator (that is, Bernoulli) random variables.
Solution Summary: The author shows the expected value of N for any strategy.
A deck of n cards numbered 1 through n is thoroughly shuffled so that all possible n! orderings can be assumed to be equally likely. Suppose you are to make n guesses sequentially, where the ith one is a guess of the card in position i. Let n denote the number of correct guesses.
a. If you are not given any information about your earlier guesses, show that for any strategy,
E
[
N
]
=
1
.
b. Suppose that after each guess you are shown the card that was in the position in question. What do you think is the best strategy? Show that under this strategy,
E
[
N
]
=
1
n
+
1
n
−
1
+
...
+
1
≈
∫
1
n
1
x
d
x
=
log
n
c. Suppose that you are told after each guess whether you are right or wrong. In this case, it can be shown that the strategy that maximizes E[N] is one that keeps on guessing the same card until you are told you are correct and then changes to a new card. For this strategy, show that
E
[
N
]
=
1
+
1
2
!
+
1
3
!
+
...
+
1
n
!
≈
e
−
1
Hint: For all parts, express
N as the sum of indicator (that is, Bernoulli) random variables.
3. A different 7-Eleven has a bank of slurpee fountain heads. Their available flavors are as follows: Mountain
Dew, Mountain Dew Code Red, Grape, Pepsi and Mountain Dew Livewire. You fill five different cups full
with each type of flavor. How many different ways can you arrange the cups in a line if exactly two Mountain
Dew flavors are next to each other?
3.2.1
Answer questions 8.3.3 and 8.3.4 respectively
8.3.4 .WP An article in Medicine and Science in Sports and
Exercise [“Electrostimulation Training Effects on the Physical Performance of Ice Hockey Players” (2005, Vol. 37, pp.
455–460)] considered the use of electromyostimulation (EMS) as
a method to train healthy skeletal muscle. EMS sessions consisted of 30 contractions (4-second duration, 85 Hz) and were carried
out three times per week for 3 weeks on 17 ice hockey players.
The 10-meter skating performance test showed a standard deviation of 0.09 seconds. Construct a 95% confidence interval of the
standard deviation of the skating performance test.
8.6.7 Consider the tire-testing data in Exercise 8.2.3. Compute a 95% tolerance interval on the life of the tires that has confidence level 95%. Compare the length of the tolerance interval with the length of the 95% CI on the population mean. Which interval is shorter? Discuss the difference in interpretation of these two intervals.
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, probability and related others by exploring similar questions and additional content below.
Discrete Distributions: Binomial, Poisson and Hypergeometric | Statistics for Data Science; Author: Dr. Bharatendra Rai;https://www.youtube.com/watch?v=lHhyy4JMigg;License: Standard Youtube License