Chapter 7, Problem 7.15QP

Interpretation Introduction

Interpretation:

The energy of photon having wavelength of $\text{624nm}$ has to be calculated.

Concept introduction:

The mathematical equation of various characteristics of light wave is

$\text{c = νλ}$

C is speed of light ($\text{3}{\text{.00 × 10}}^{\text{8}}\text{ m/s}$).

$\text{ν}$ is the frequency

$\text{λ}$ is wavelength.

The energy of each photon is given as

$\text{E}\text{=}\text{hν}$

h is Planck’s constant ($\text{6}\text{.63}\text{×}{\text{10}}^{\text{-34}}\text{J}\text{.s}$ ) which relates energy and frequency.

$\text{ν}$ is the frequency.

E is energy of light particle