Concept explainers
(a)
Interpretation: The term monosaccharide, disaccharide, reducing sugar, anomers, enantiomer and aldohexoses whether applies to both the members of the given pair or not has to be stated.
Concept introduction: Monosaccharides are those type of sugars which cannot be hydrolysed further.
Disaccharides are those type of sugars which have two units of monosaccharides.
The enantiomers are the molecules that form non-superimposable mirror images of each other.
Carbon atom which behaves as a stereocenter in the cyclic form of the hemiacetal compound is known as anomeric carbon. The molecule containing the anomeric carbon is called anomer.
The monosaccharides that have
The sugars that have a free carbonyl group are called reducing sugars.
(b)
Interpretation: The term monosaccharide, disaccharide, reducing sugar, anomers, enantiomer and aldohexoses whether applies to both the members of the given pair or not has to be stated.
Concept introduction: Monosaccharides are those type of sugars which cannot be hydrolysed further.
Disaccharides are those type of sugars which have two units of monosaccharides.
The enantiomers are the molecules that form non-superimposable mirror images of each other.
Carbon atom which behaves as a stereocenter in the cyclic form of the hemiacetal compound is known as anomeric carbon. The molecule containing the anomeric carbon is called anomer.
The monosaccharides that have aldehyde as a functional group and a long chain of six carbon atoms are called aldohexoses.
The sugars that have a free carbonyl group are called reducing sugars.
(c)
Interpretation: The term monosaccharide, disaccharide, reducing sugar, anomers, enantiomer and aldohexoses whether applies to both the members of the given pair or not has to be stated.
Concept introduction: Monosaccharides are those type of sugars which cannot be hydrolysed further.
Disaccharides are those type of sugars which have two units of monosaccharides.
The enantiomers are the molecules that form non-superimposable mirror images of each other.
Carbon atom which behaves as a stereocenter in the cyclic form of the hemiacetal compound is known as anomeric carbon. The molecule containing the anomeric carbon is called anomer.
The monosaccharides that have aldehyde as a functional group and a long chain of six carbon atoms are called aldohexoses.
The sugars that have a free carbonyl group are called reducing sugars.
(d)
Interpretation: The term monosaccharide, disaccharide, reducing sugar, anomers, enantiomer and aldohexoses whether applies to both the members of the given pair or not has to be stated.
Concept introduction: Monosaccharides are those type of sugars which cannot be hydrolysed further.
Disaccharides are those type of sugars which have two units of monosaccharides.
The enantiomers are the molecules that form non-superimposable mirror images of each other.
Carbon atom which behaves as a stereocenter in the cyclic form of the hemiacetal compound is known as anomeric carbon. The molecule containing the anomeric carbon is called anomer.
The monosaccharides that have aldehyde as a functional group and a long chain of six carbon atoms are called aldohexoses.
The sugars that have a free carbonyl group are called reducing sugars.

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Chapter 7 Solutions
EBK ORGANIC AND BIOLOGICAL CHEMISTRY
- drawing, no aiarrow_forwardDraw the major organic product when each of the bellow reagents is added to 3,3-dimethylbutere. ✓ 3rd attempt Part 1 (0.3 point) H.C CH CH + 1. BHG THF 210 NaOH NJ 10000 Part 2 (0.3 point) HC- CH HC 2741 OH a Search 1. He|DA HO 2. NIBH さ 士 Ju See Periodic Table See Hint j = uz C H F F boxarrow_forwardSynthesis of 2-metilbenzimidazol from 1,2-diaminobenceno y propanona.arrow_forward
- Predict the product of the following reaction. 1st attempt HI 1 product 50300 Jul See Periodic Table See Hint P Br 石尚 Iarrow_forwardIndicate the substitutes in one place, if they are a diazonio room.arrow_forwardIndicate the product formed in each reaction. If the product exhibits tautomerism, draw the tautomeric structure. a) о + CH3-NH-NH2 CO2C2H5 b) + CoH5-NH-NH2 OC2H5arrow_forward
- Indicate the formula of the compound, that is the result of the N- alquilación (nucleofílic substitution), in which an additional lateral chain was formed (NH-CH2-COOMe). F3C. CF3 NH NH2 Br о OMe K2CO3, DABCO, DMFarrow_forwardSynthesis of 1-metilbenzotriazole from 1,2-diaminobenceno.arrow_forwardSynthesis of 1-metilbenzotriazole.arrow_forward
- Indicate the formula of the compound, that is the result of the N- alquilación (nucleofílic substitution), in which an additional lateral chain was formed (NH-CH2-COOMe). F3C. CF3 NH NH2 Br о OMe K2CO3, DABCO, DMFarrow_forwardIdentify the mechanism through which the following reaction will proceed and draw the major product. Part 1 of 2 Br KOH EtOH Through which mechanism will the reaction proceed? Select the single best answer. E1 E2 neither Part: 1/2 Part 2 of 2 Draw the major product formed as a result of the reaction. Click and drag to start drawing a structure. Xarrow_forwardWhat is single-point calibration? Provide an example.arrow_forward
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