The plausible mechanism for the given transformations should be drawn and identified. Concept Introduction: Dehydration reaction: Removal of water molecule from the reaction when the alcohol is treated with strong acid like sulfuric acid. Alcohol is reaction with concentrated sulfuric acid, first alcohol gets protonated forms carbocation (more stable carbocation) followed by elimination of proton ( H + ) yields alkene as a product. The stability of carbocation is given below, Tertiary carbocation is more stable than the secondary, secondary carbocation is more stable than primary. In dehydration reaction, sulfuric acid is act as a proton donor, and which is used to protonate the alcohol and makes carbocation therefore sulfuric acid is the driving force of the reaction. Dehydration reaction will not go without acid (sulfuric acid).

Question

Draw one product of an elimination reaction between the molecules below. Note: There may be several correct answers. You only need to draw one of them. You do not need to draw any of the side products of the reaction 'O 10 + x 也 HO + 义 Click and drag to start drawing a structure.

Answer 1

Question

Chapter 7, Problem 70PP

(a)

Interpretation Introduction

Interpretation:

The plausible mechanism for the given transformations should be drawn and identified.

Concept Introduction:

Dehydration reaction:

Removal of water molecule from the reaction when the alcohol is treated with strong acid like sulfuric acid.

Alcohol is reaction with concentrated sulfuric acid, first alcohol gets protonated forms carbocation (more stable carbocation) followed by elimination of proton (H+) yields alkene as a product. The stability of carbocation is given below,

Tertiary carbocation is more stable than the secondary, secondary carbocation is more stable than primary.

In dehydration reaction, sulfuric acid is act as a proton donor, and which is used to protonate the alcohol and makes carbocation therefore sulfuric acid is the driving force of the reaction. Dehydration reaction will not go without acid (sulfuric acid).

(b)

Interpretation Introduction

Interpretation:

The plausible mechanism for the given transformations should be drawn and identified.

Concept Introduction:

Dehydration reaction:

Removal of water molecule from the reaction when the alcohol is treated with strong acid like sulfuric acid.

Alcohol is reaction with concentrated sulfuric acid, first alcohol gets protonated forms carbocation (more stable carbocation) followed by elimination of proton (H+) yields alkene as a product. The stability of carbocation is given below,

Tertiary carbocation is more stable than the secondary, secondary carbocation is more stable than primary.

In dehydration reaction, sulfuric acid is act as a proton donor, and which is used to protonate the alcohol and makes carbocation therefore sulfuric acid is the driving force of the reaction. Dehydration reaction will not go without acid (sulfuric acid).

(c)

Interpretation Introduction

Interpretation:

The plausible mechanism for the given transformations should be drawn and identified.

Concept Introduction:

Elimination Reaction: It is just reverse reaction of addition where substituent from the given molecule is removed via E1 (the reaction depends only on the substrate involved in the reaction) or E2 (the reaction depends on both of the substituents in the reaction) mechanism.

E1 reaction is a unimolecular elimination reaction to produce alkene compounds in which carbocation is formed as an intermediate and it has stepwise mechanism.

E2 reaction is a bimolecular elimination reaction in which alkene compounds formed in a single step.

Example,

Alkenes are formed when alcohols are treated with strong acid via eliminating one β-proton and the −OH group of the alcohol.

Alkenes are formed when alkyl halides are treated with bases via eliminating one β-proton and one α-halo group of the alkyl halide.

Curved arrows are used for drawing the mechanism of reaction.

The tertiary carbocation is more stable than secondary carbocation.

(d)

Interpretation Introduction

Interpretation:

The plausible mechanism for the given transformations should be drawn and identified.

Concept Introduction:

Elimination Reaction: It is just reverse reaction of addition where substituent from the given molecule is removed via E1 (the reaction depends only on the substrate involved in the reaction) or E2 (the reaction depends on both of the substituents in the reaction) mechanism.

E1 reaction is a unimolecular elimination reaction to produce alkene compounds in which carbocation is formed as an intermediate and it has stepwise mechanism.

E2 reaction is a bimolecular elimination reaction in which alkene compounds formed in a single step.

Example,

Alkenes are formed when alcohols are treated with strong acid via eliminating one β-proton and the −OH group of the alcohol.

Alkenes are formed when alkyl halides are treated with bases via eliminating one β-proton and one α-halo group of the alkyl halide.

Curved arrows are used for drawing the mechanism of reaction.

The tertiary carbocation is more stable than secondary carbocation.

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Draw one product of an elimination reaction between the molecules below. Note: There may be several correct answers. You only need to draw one of them. You do not need to draw any of the side products of the reaction 'O 10 + x 也 HO + 义 Click and drag to start drawing a structure.

What are the angles a and b in the actual molecule of which this is a Lewis structure? H- :0: C=N: b Note for advanced students: give the ideal angles, and don't worry about small differences from the ideal that might be caused by the fact that different electron groups may have slightly different sizes. a = 0° b=0 X

A student proposes the transformation below in one step of an organic synthesis. There may be one or more products missing from the right-hand side, but there are no reagents missing from the left-hand side. There may also be catalysts, small inorganic reagents, and other important reaction conditions missing from the arrow. • Is the student's transformation possible? If not, check the box under the drawing area. • If the student's transformation is possible, then complete the reaction by adding any missing products to the right-hand side, and adding required catalysts, inorganic reagents, or other important reaction conditions above and below the arrow. • You do not need to balance the reaction, but be sure every important organic reactant or product is shown. + This transformation can't be done in one step. T i

Answer 2

Question

Chapter 7, Problem 70PP

(a)

Interpretation Introduction

Interpretation:

The plausible mechanism for the given transformations should be drawn and identified.

Concept Introduction:

Dehydration reaction:

Removal of water molecule from the reaction when the alcohol is treated with strong acid like sulfuric acid.

Alcohol is reaction with concentrated sulfuric acid, first alcohol gets protonated forms carbocation (more stable carbocation) followed by elimination of proton (H+) yields alkene as a product. The stability of carbocation is given below,

Tertiary carbocation is more stable than the secondary, secondary carbocation is more stable than primary.

In dehydration reaction, sulfuric acid is act as a proton donor, and which is used to protonate the alcohol and makes carbocation therefore sulfuric acid is the driving force of the reaction. Dehydration reaction will not go without acid (sulfuric acid).

(b)

Interpretation Introduction

Interpretation:

The plausible mechanism for the given transformations should be drawn and identified.

Concept Introduction:

Dehydration reaction:

Removal of water molecule from the reaction when the alcohol is treated with strong acid like sulfuric acid.

Alcohol is reaction with concentrated sulfuric acid, first alcohol gets protonated forms carbocation (more stable carbocation) followed by elimination of proton (H+) yields alkene as a product. The stability of carbocation is given below,

Tertiary carbocation is more stable than the secondary, secondary carbocation is more stable than primary.

In dehydration reaction, sulfuric acid is act as a proton donor, and which is used to protonate the alcohol and makes carbocation therefore sulfuric acid is the driving force of the reaction. Dehydration reaction will not go without acid (sulfuric acid).

(c)

Interpretation Introduction

Interpretation:

The plausible mechanism for the given transformations should be drawn and identified.

Concept Introduction:

Elimination Reaction: It is just reverse reaction of addition where substituent from the given molecule is removed via E1 (the reaction depends only on the substrate involved in the reaction) or E2 (the reaction depends on both of the substituents in the reaction) mechanism.

E1 reaction is a unimolecular elimination reaction to produce alkene compounds in which carbocation is formed as an intermediate and it has stepwise mechanism.

E2 reaction is a bimolecular elimination reaction in which alkene compounds formed in a single step.

Example,

Alkenes are formed when alcohols are treated with strong acid via eliminating one β-proton and the −OH group of the alcohol.

Alkenes are formed when alkyl halides are treated with bases via eliminating one β-proton and one α-halo group of the alkyl halide.

Curved arrows are used for drawing the mechanism of reaction.

The tertiary carbocation is more stable than secondary carbocation.

(d)

Interpretation Introduction

Interpretation:

The plausible mechanism for the given transformations should be drawn and identified.

Concept Introduction:

Elimination Reaction: It is just reverse reaction of addition where substituent from the given molecule is removed via E1 (the reaction depends only on the substrate involved in the reaction) or E2 (the reaction depends on both of the substituents in the reaction) mechanism.

E1 reaction is a unimolecular elimination reaction to produce alkene compounds in which carbocation is formed as an intermediate and it has stepwise mechanism.

E2 reaction is a bimolecular elimination reaction in which alkene compounds formed in a single step.

Example,

Alkenes are formed when alcohols are treated with strong acid via eliminating one β-proton and the −OH group of the alcohol.

Alkenes are formed when alkyl halides are treated with bases via eliminating one β-proton and one α-halo group of the alkyl halide.

Curved arrows are used for drawing the mechanism of reaction.

The tertiary carbocation is more stable than secondary carbocation.

Expert Solution & Answer

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Answer 3

Question

Chapter 7, Problem 70PP

(a)

Interpretation Introduction

Interpretation:

The plausible mechanism for the given transformations should be drawn and identified.

Concept Introduction:

Dehydration reaction:

Removal of water molecule from the reaction when the alcohol is treated with strong acid like sulfuric acid.

Alcohol is reaction with concentrated sulfuric acid, first alcohol gets protonated forms carbocation (more stable carbocation) followed by elimination of proton (H+) yields alkene as a product. The stability of carbocation is given below,

Tertiary carbocation is more stable than the secondary, secondary carbocation is more stable than primary.

In dehydration reaction, sulfuric acid is act as a proton donor, and which is used to protonate the alcohol and makes carbocation therefore sulfuric acid is the driving force of the reaction. Dehydration reaction will not go without acid (sulfuric acid).

(b)

Interpretation Introduction

Interpretation:

The plausible mechanism for the given transformations should be drawn and identified.

Concept Introduction:

Dehydration reaction:

Removal of water molecule from the reaction when the alcohol is treated with strong acid like sulfuric acid.

Alcohol is reaction with concentrated sulfuric acid, first alcohol gets protonated forms carbocation (more stable carbocation) followed by elimination of proton (H+) yields alkene as a product. The stability of carbocation is given below,

Tertiary carbocation is more stable than the secondary, secondary carbocation is more stable than primary.

In dehydration reaction, sulfuric acid is act as a proton donor, and which is used to protonate the alcohol and makes carbocation therefore sulfuric acid is the driving force of the reaction. Dehydration reaction will not go without acid (sulfuric acid).

(c)

Interpretation Introduction

Interpretation:

The plausible mechanism for the given transformations should be drawn and identified.

Concept Introduction:

Elimination Reaction: It is just reverse reaction of addition where substituent from the given molecule is removed via E1 (the reaction depends only on the substrate involved in the reaction) or E2 (the reaction depends on both of the substituents in the reaction) mechanism.

E1 reaction is a unimolecular elimination reaction to produce alkene compounds in which carbocation is formed as an intermediate and it has stepwise mechanism.

E2 reaction is a bimolecular elimination reaction in which alkene compounds formed in a single step.

Example,

Alkenes are formed when alcohols are treated with strong acid via eliminating one β-proton and the −OH group of the alcohol.

Alkenes are formed when alkyl halides are treated with bases via eliminating one β-proton and one α-halo group of the alkyl halide.

Curved arrows are used for drawing the mechanism of reaction.

The tertiary carbocation is more stable than secondary carbocation.

(d)

Interpretation Introduction

Interpretation:

The plausible mechanism for the given transformations should be drawn and identified.

Concept Introduction:

Elimination Reaction: It is just reverse reaction of addition where substituent from the given molecule is removed via E1 (the reaction depends only on the substrate involved in the reaction) or E2 (the reaction depends on both of the substituents in the reaction) mechanism.

E1 reaction is a unimolecular elimination reaction to produce alkene compounds in which carbocation is formed as an intermediate and it has stepwise mechanism.

E2 reaction is a bimolecular elimination reaction in which alkene compounds formed in a single step.

Example,

Alkenes are formed when alcohols are treated with strong acid via eliminating one β-proton and the −OH group of the alcohol.

Alkenes are formed when alkyl halides are treated with bases via eliminating one β-proton and one α-halo group of the alkyl halide.

Curved arrows are used for drawing the mechanism of reaction.

The tertiary carbocation is more stable than secondary carbocation.

Expert Solution & Answer

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Answer 4

Question

Chapter 7, Problem 70PP

(a)

Interpretation Introduction

Interpretation:

The plausible mechanism for the given transformations should be drawn and identified.

Concept Introduction:

Dehydration reaction:

Removal of water molecule from the reaction when the alcohol is treated with strong acid like sulfuric acid.

Alcohol is reaction with concentrated sulfuric acid, first alcohol gets protonated forms carbocation (more stable carbocation) followed by elimination of proton (H+) yields alkene as a product. The stability of carbocation is given below,

Tertiary carbocation is more stable than the secondary, secondary carbocation is more stable than primary.

In dehydration reaction, sulfuric acid is act as a proton donor, and which is used to protonate the alcohol and makes carbocation therefore sulfuric acid is the driving force of the reaction. Dehydration reaction will not go without acid (sulfuric acid).

(b)

Interpretation Introduction

Interpretation:

The plausible mechanism for the given transformations should be drawn and identified.

Concept Introduction:

Dehydration reaction:

Removal of water molecule from the reaction when the alcohol is treated with strong acid like sulfuric acid.

Alcohol is reaction with concentrated sulfuric acid, first alcohol gets protonated forms carbocation (more stable carbocation) followed by elimination of proton (H+) yields alkene as a product. The stability of carbocation is given below,

Tertiary carbocation is more stable than the secondary, secondary carbocation is more stable than primary.

In dehydration reaction, sulfuric acid is act as a proton donor, and which is used to protonate the alcohol and makes carbocation therefore sulfuric acid is the driving force of the reaction. Dehydration reaction will not go without acid (sulfuric acid).

(c)

Interpretation Introduction

Interpretation:

The plausible mechanism for the given transformations should be drawn and identified.

Concept Introduction:

Elimination Reaction: It is just reverse reaction of addition where substituent from the given molecule is removed via E1 (the reaction depends only on the substrate involved in the reaction) or E2 (the reaction depends on both of the substituents in the reaction) mechanism.

E1 reaction is a unimolecular elimination reaction to produce alkene compounds in which carbocation is formed as an intermediate and it has stepwise mechanism.

E2 reaction is a bimolecular elimination reaction in which alkene compounds formed in a single step.

Example,

Alkenes are formed when alcohols are treated with strong acid via eliminating one β-proton and the −OH group of the alcohol.

Alkenes are formed when alkyl halides are treated with bases via eliminating one β-proton and one α-halo group of the alkyl halide.

Curved arrows are used for drawing the mechanism of reaction.

The tertiary carbocation is more stable than secondary carbocation.

(d)

Interpretation Introduction

Interpretation:

The plausible mechanism for the given transformations should be drawn and identified.

Concept Introduction:

Elimination Reaction: It is just reverse reaction of addition where substituent from the given molecule is removed via E1 (the reaction depends only on the substrate involved in the reaction) or E2 (the reaction depends on both of the substituents in the reaction) mechanism.

E1 reaction is a unimolecular elimination reaction to produce alkene compounds in which carbocation is formed as an intermediate and it has stepwise mechanism.

E2 reaction is a bimolecular elimination reaction in which alkene compounds formed in a single step.

Example,

Alkenes are formed when alcohols are treated with strong acid via eliminating one β-proton and the −OH group of the alcohol.

Alkenes are formed when alkyl halides are treated with bases via eliminating one β-proton and one α-halo group of the alkyl halide.

Curved arrows are used for drawing the mechanism of reaction.

The tertiary carbocation is more stable than secondary carbocation.

Expert Solution & Answer

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Answer 5

Chapter 7, Problem 70PP

(a)

Interpretation Introduction

Interpretation:

The plausible mechanism for the given transformations should be drawn and identified.

Concept Introduction:

Dehydration reaction:

Removal of water molecule from the reaction when the alcohol is treated with strong acid like sulfuric acid.

Alcohol is reaction with concentrated sulfuric acid, first alcohol gets protonated forms carbocation (more stable carbocation) followed by elimination of proton (H+) yields alkene as a product. The stability of carbocation is given below,

Tertiary carbocation is more stable than the secondary, secondary carbocation is more stable than primary.

In dehydration reaction, sulfuric acid is act as a proton donor, and which is used to protonate the alcohol and makes carbocation therefore sulfuric acid is the driving force of the reaction. Dehydration reaction will not go without acid (sulfuric acid).

(b)

Interpretation Introduction

Interpretation:

The plausible mechanism for the given transformations should be drawn and identified.

Concept Introduction:

Dehydration reaction:

Removal of water molecule from the reaction when the alcohol is treated with strong acid like sulfuric acid.

Alcohol is reaction with concentrated sulfuric acid, first alcohol gets protonated forms carbocation (more stable carbocation) followed by elimination of proton (H+) yields alkene as a product. The stability of carbocation is given below,

Tertiary carbocation is more stable than the secondary, secondary carbocation is more stable than primary.

In dehydration reaction, sulfuric acid is act as a proton donor, and which is used to protonate the alcohol and makes carbocation therefore sulfuric acid is the driving force of the reaction. Dehydration reaction will not go without acid (sulfuric acid).

(c)

Interpretation Introduction

Interpretation:

The plausible mechanism for the given transformations should be drawn and identified.

Concept Introduction:

Elimination Reaction: It is just reverse reaction of addition where substituent from the given molecule is removed via E1 (the reaction depends only on the substrate involved in the reaction) or E2 (the reaction depends on both of the substituents in the reaction) mechanism.

E1 reaction is a unimolecular elimination reaction to produce alkene compounds in which carbocation is formed as an intermediate and it has stepwise mechanism.

E2 reaction is a bimolecular elimination reaction in which alkene compounds formed in a single step.

Example,

Alkenes are formed when alcohols are treated with strong acid via eliminating one β-proton and the −OH group of the alcohol.

Alkenes are formed when alkyl halides are treated with bases via eliminating one β-proton and one α-halo group of the alkyl halide.

Curved arrows are used for drawing the mechanism of reaction.

The tertiary carbocation is more stable than secondary carbocation.

(d)

Interpretation Introduction

Interpretation:

The plausible mechanism for the given transformations should be drawn and identified.

Concept Introduction:

Elimination Reaction: It is just reverse reaction of addition where substituent from the given molecule is removed via E1 (the reaction depends only on the substrate involved in the reaction) or E2 (the reaction depends on both of the substituents in the reaction) mechanism.

E1 reaction is a unimolecular elimination reaction to produce alkene compounds in which carbocation is formed as an intermediate and it has stepwise mechanism.

E2 reaction is a bimolecular elimination reaction in which alkene compounds formed in a single step.

Example,

Alkenes are formed when alcohols are treated with strong acid via eliminating one β-proton and the −OH group of the alcohol.

Alkenes are formed when alkyl halides are treated with bases via eliminating one β-proton and one α-halo group of the alkyl halide.

Curved arrows are used for drawing the mechanism of reaction.

The tertiary carbocation is more stable than secondary carbocation.

Answer 6

Chapter 7, Problem 70PP

(a)

Interpretation Introduction

Interpretation:

The plausible mechanism for the given transformations should be drawn and identified.

Concept Introduction:

Dehydration reaction:

Removal of water molecule from the reaction when the alcohol is treated with strong acid like sulfuric acid.

Alcohol is reaction with concentrated sulfuric acid, first alcohol gets protonated forms carbocation (more stable carbocation) followed by elimination of proton (H+) yields alkene as a product. The stability of carbocation is given below,

Tertiary carbocation is more stable than the secondary, secondary carbocation is more stable than primary.

In dehydration reaction, sulfuric acid is act as a proton donor, and which is used to protonate the alcohol and makes carbocation therefore sulfuric acid is the driving force of the reaction. Dehydration reaction will not go without acid (sulfuric acid).

Answer 7

Chapter 7, Problem 70PP

(a)

Interpretation Introduction

Interpretation:

The plausible mechanism for the given transformations should be drawn and identified.

Concept Introduction:

Dehydration reaction:

Removal of water molecule from the reaction when the alcohol is treated with strong acid like sulfuric acid.

Alcohol is reaction with concentrated sulfuric acid, first alcohol gets protonated forms carbocation (more stable carbocation) followed by elimination of proton (H+) yields alkene as a product. The stability of carbocation is given below,

Tertiary carbocation is more stable than the secondary, secondary carbocation is more stable than primary.

In dehydration reaction, sulfuric acid is act as a proton donor, and which is used to protonate the alcohol and makes carbocation therefore sulfuric acid is the driving force of the reaction. Dehydration reaction will not go without acid (sulfuric acid).

Answer 8

(b)

Interpretation Introduction

Interpretation:

The plausible mechanism for the given transformations should be drawn and identified.

Concept Introduction:

Dehydration reaction:

Removal of water molecule from the reaction when the alcohol is treated with strong acid like sulfuric acid.

Alcohol is reaction with concentrated sulfuric acid, first alcohol gets protonated forms carbocation (more stable carbocation) followed by elimination of proton (H+) yields alkene as a product. The stability of carbocation is given below,

Tertiary carbocation is more stable than the secondary, secondary carbocation is more stable than primary.

In dehydration reaction, sulfuric acid is act as a proton donor, and which is used to protonate the alcohol and makes carbocation therefore sulfuric acid is the driving force of the reaction. Dehydration reaction will not go without acid (sulfuric acid).

Answer 9

(b)

Interpretation Introduction

Interpretation:

The plausible mechanism for the given transformations should be drawn and identified.

Concept Introduction:

Dehydration reaction:

Removal of water molecule from the reaction when the alcohol is treated with strong acid like sulfuric acid.

Alcohol is reaction with concentrated sulfuric acid, first alcohol gets protonated forms carbocation (more stable carbocation) followed by elimination of proton (H+) yields alkene as a product. The stability of carbocation is given below,

Tertiary carbocation is more stable than the secondary, secondary carbocation is more stable than primary.

In dehydration reaction, sulfuric acid is act as a proton donor, and which is used to protonate the alcohol and makes carbocation therefore sulfuric acid is the driving force of the reaction. Dehydration reaction will not go without acid (sulfuric acid).

Answer 10

(c)

Interpretation Introduction

Interpretation:

The plausible mechanism for the given transformations should be drawn and identified.

Concept Introduction:

Elimination Reaction: It is just reverse reaction of addition where substituent from the given molecule is removed via E1 (the reaction depends only on the substrate involved in the reaction) or E2 (the reaction depends on both of the substituents in the reaction) mechanism.

E1 reaction is a unimolecular elimination reaction to produce alkene compounds in which carbocation is formed as an intermediate and it has stepwise mechanism.

E2 reaction is a bimolecular elimination reaction in which alkene compounds formed in a single step.

Example,

Alkenes are formed when alcohols are treated with strong acid via eliminating one β-proton and the −OH group of the alcohol.

Alkenes are formed when alkyl halides are treated with bases via eliminating one β-proton and one α-halo group of the alkyl halide.

Curved arrows are used for drawing the mechanism of reaction.

The tertiary carbocation is more stable than secondary carbocation.

Answer 11

(c)

Interpretation Introduction

Interpretation:

The plausible mechanism for the given transformations should be drawn and identified.

Concept Introduction:

Elimination Reaction: It is just reverse reaction of addition where substituent from the given molecule is removed via E1 (the reaction depends only on the substrate involved in the reaction) or E2 (the reaction depends on both of the substituents in the reaction) mechanism.

E1 reaction is a unimolecular elimination reaction to produce alkene compounds in which carbocation is formed as an intermediate and it has stepwise mechanism.

E2 reaction is a bimolecular elimination reaction in which alkene compounds formed in a single step.

Example,

Alkenes are formed when alcohols are treated with strong acid via eliminating one β-proton and the −OH group of the alcohol.

Alkenes are formed when alkyl halides are treated with bases via eliminating one β-proton and one α-halo group of the alkyl halide.

Curved arrows are used for drawing the mechanism of reaction.

The tertiary carbocation is more stable than secondary carbocation.

Answer 12

(d)

Interpretation Introduction

Interpretation:

The plausible mechanism for the given transformations should be drawn and identified.

Concept Introduction:

Elimination Reaction: It is just reverse reaction of addition where substituent from the given molecule is removed via E1 (the reaction depends only on the substrate involved in the reaction) or E2 (the reaction depends on both of the substituents in the reaction) mechanism.

E1 reaction is a unimolecular elimination reaction to produce alkene compounds in which carbocation is formed as an intermediate and it has stepwise mechanism.

E2 reaction is a bimolecular elimination reaction in which alkene compounds formed in a single step.

Example,

Alkenes are formed when alcohols are treated with strong acid via eliminating one β-proton and the −OH group of the alcohol.

Alkenes are formed when alkyl halides are treated with bases via eliminating one β-proton and one α-halo group of the alkyl halide.

Curved arrows are used for drawing the mechanism of reaction.

The tertiary carbocation is more stable than secondary carbocation.

Answer 13

(d)

Interpretation Introduction

Interpretation:

The plausible mechanism for the given transformations should be drawn and identified.

Concept Introduction:

Elimination Reaction: It is just reverse reaction of addition where substituent from the given molecule is removed via E1 (the reaction depends only on the substrate involved in the reaction) or E2 (the reaction depends on both of the substituents in the reaction) mechanism.

E1 reaction is a unimolecular elimination reaction to produce alkene compounds in which carbocation is formed as an intermediate and it has stepwise mechanism.

E2 reaction is a bimolecular elimination reaction in which alkene compounds formed in a single step.

Example,

Alkenes are formed when alcohols are treated with strong acid via eliminating one β-proton and the −OH group of the alcohol.

Alkenes are formed when alkyl halides are treated with bases via eliminating one β-proton and one α-halo group of the alkyl halide.

Curved arrows are used for drawing the mechanism of reaction.

The tertiary carbocation is more stable than secondary carbocation.

Answer 14

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Answer 25

Ch. 7.2 - Prob. 1CC Ch. 7.3 - Prob. 2CC Ch. 7.3 - Prob. 1LTS Ch. 7.3 - Prob. 3PTS Ch. 7.3 - Prob. 4ATS Ch. 7.3 - Prob. 2LTS Ch. 7.3 - Prob. 5PTS Ch. 7.3 - Prob. 6ATS Ch. 7.3 - Prob. 7CC Ch. 7.4 - Prob. 8CC

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Chapter 7 Solutions