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(a)
Interpretation:
The major product for each of the given E2 reactions is has to be predicted.
Concept Introduction:
Elimination Reaction: It is just reverse reaction of addition where substituent from the given molecule is removed via
In an elimination reaction,
E2 reaction is a bimolecular elimination reaction in which only one step is involved.
The product of the elimination reaction is depends upon the two β-positions of alkyl halide. If the β-positions are identical and the products formed are also identical. If the β-positions are different and the products formed are also different. This means the double bond can form in two different regions so this type of reaction is called regioselective and the products are called as regiochemical outcomes.
The bulkiness of the base controls the regioselectivity in an elimination reaction. The sterically hindered bases form less substituted alkene and non-sterically hindered bases form more substituted alkenes.
If there are two different β-protons at a β-position of alkyl halide, then on the basis of stereoselectivity the trans-isomer is favored over cis-isomer.
(b)
Interpretation:
The major product for each of the given E2 reactions is has to be predicted.
Concept Introduction:
Elimination Reaction: It is just reverse reaction of addition where substituent from the given molecule is removed via
In an elimination reaction, alkenes are formed when alkyl halides are treated with bases via eliminating one proton and one halo group of the alkyl halide.
E2 reaction is a bimolecular elimination reaction in which only one step is involved.
The product of the elimination reaction is depends upon the two β-positions of alkyl halide. If the β-positions are identical and the products formed are also identical. If the β-positions are different and the products formed are also different. This means the double bond can form in two different regions so this type of reaction is called regioselective and the products are called as regiochemical outcomes.
The bulkiness of the base controls the regioselectivity in an elimination reaction. The sterically hindered bases form less substituted alkene and non-sterically hindered bases form more substituted alkenes.
If there are two different β-protons at a β-position of alkyl halide, then on the basis of stereoselectivity the trans-isomer is favored over cis-isomer.
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Chapter 7 Solutions
ORGANIC CHEMISTRY-STD.WILEY PLUS CARD
- Provide steps and explanation please.arrow_forwardDraw a structural formula for the major product of the acid-base reaction shown. H 0 N + HCI (1 mole) CH3 N' (1 mole) CH3 You do not have to consider stereochemistry. ● • Do not include counter-ions, e.g., Na+, I, in your answer. . In those cases in which there are two reactants, draw only the product from 989 CH3 344 ? [Farrow_forwardQuestion 15 What is the major neutral organic product for the following sequence? 1. POCI₂ pyridine ? 2. OsO4 OH 3. NaHSO Major Organic Product ✓ OH OH 'OH OH 'OH 'CIarrow_forward
- Could you please solve the first problem in this way and present it similarly but color-coded or step by step so I can understand it better? Thank you!arrow_forwardCould you please solve the first problem in this way and present it similarly but color-coded or step by step so I can understand it better? Thank you!arrow_forwardCould you please solve the first problem in this way and present it similarly but (color-coded) and step by step so I can understand it better? Thank you! I want to see what they are doingarrow_forward
- Can you please help mne with this problem. Im a visual person, so can you redraw it, potentislly color code and then as well explain it. I know im given CO2 use that to explain to me, as well as maybe give me a second example just to clarify even more with drawings (visuals) and explanations.arrow_forwardPart 1. Aqueous 0.010M AgNO 3 is slowly added to a 50-ml solution containing both carbonate [co32-] = 0.105 M and sulfate [soy] = 0.164 M anions. Given the ksp of Ag2CO3 and Ag₂ soy below. Answer the ff: Ag₂ CO3 = 2 Ag+ caq) + co} (aq) ksp = 8.10 × 10-12 Ag₂SO4 = 2Ag+(aq) + soy² (aq) ksp = 1.20 × 10-5 a) which salt will precipitate first? (b) What % of the first anion precipitated will remain in the solution. by the time the second anion starts to precipitate? (c) What is the effect of low pH (more acidic) condition on the separate of the carbonate and sulfate anions via silver precipitation? What is the effect of high pH (more basic)? Provide appropriate explanation per answerarrow_forwardPart 4. Butanoic acid (ka= 1.52× 10-5) has a partition coefficient of 3.0 (favors benzene) when distributed bet. water and benzene. What is the formal concentration of butanoic acid in each phase when 0.10M aqueous butanoic acid is extracted w❘ 25 mL of benzene 100 mL of a) at pit 5.00 b) at pH 9.00arrow_forward
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