Chapter 7, Problem 6CT

To determine

The mean, media, mode, range and standard deviation of the given data.

Answer to Problem 6CT

  $\begin{array}{c}Mean=12\\ Median=11.1\end{array}$

There will be no mode as all the terms are occurring once.

The range will be $=12.56$

Standard deviation will be $=4.37$

Explanation of Solution

Given:

The given data is:

  

Calculation:

All shirts are on 20 per cent off.

The new data will be:

  

The mean, media, mode, range and standard deviation of the given data will be:

  $\begin{array}{c}Mean=\frac{12.40+6.24+15.12+18.8+8.48+7.8+9.8+17.36}{8}\\ =\frac{96}{8}\\ =12\\ Median=\frac{9.80+12.40}{2}\\ =\frac{22.2}{2}\\ =11.1\end{array}$

There will be no mode as all the terms are occurring once.

The range will be:

  $\begin{array}{l}=18.80-6.24\\ =12.56\end{array}$

The table can be drawn as:

  

Standard deviation will be:

  $\begin{array}{l}=\sqrt{\frac{152.91}{8}}\\ =4.37\end{array}$