OPERATION MANAGEMENT
OPERATION MANAGEMENT
2nd Edition
ISBN: 9781260242423
Author: CACHON
Publisher: MCG
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Chapter 7, Problem 5PA

a)

Summary Introduction

To determine: The maximum number horse sculptures that can be made in an hour.

a)

Expert Solution
Check Mark

Explanation of Solution

Given information:

OPERATION MANAGEMENT, Chapter 7, Problem 5PA , additional homework tip  1

Calculation of maximum number of horses:

OPERATION MANAGEMENT, Chapter 7, Problem 5PA , additional homework tip  2

Formula:

OPERATION MANAGEMENT, Chapter 7, Problem 5PA , additional homework tip  3

The maximum number of horse sculptures made in an hour is 4.8.

b)

Summary Introduction

To determine: The utilization % of the lathe.

b)

Expert Solution
Check Mark

Explanation of Solution

Given information:

OPERATION MANAGEMENT, Chapter 7, Problem 5PA , additional homework tip  4

Calculation of utilization of lathe:

OPERATION MANAGEMENT, Chapter 7, Problem 5PA , additional homework tip  5

Formula:

OPERATION MANAGEMENT, Chapter 7, Problem 5PA , additional homework tip  6

The utilization of lathe is 96%.

c)

Summary Introduction

To determine: The average inventory of body parts.

c)

Expert Solution
Check Mark

Explanation of Solution

Given information:

OPERATION MANAGEMENT, Chapter 7, Problem 5PA , additional homework tip  7

1 worker can assemble the horse sculpture in 16 minutes.

Calculation of flow rate:

Flow rate=16 minutes60 minutes=3.75 sculptures per hour.

Calculation of average inventory:

The total batch size of legs is 100 and the processing time is 4 minutes.

Average inventory=100×[1-Flow rate×(Processing time60minutes)]2=100×[1-3.75×(460)]2=37.5 body

The average inventory is 37.5 body.

d)

Summary Introduction

To determine: The average inventory of leg parts.

d)

Expert Solution
Check Mark

Explanation of Solution

Given information:

OPERATION MANAGEMENT, Chapter 7, Problem 5PA , additional homework tip  8

1 worker can assemble the horse sculpture in 16 minutes.

Calculation of flow rate:

Flow rate=16 minutes60 minutes=3.75 sculptures per hour.

Calculation of average inventory:

The total batch size of legs is 400 and the processing time is 2 minutes.

Average inventory=400×[1-Flow rate×(Processing time60minutes)]2=400×[1-3.75×(260)]2=100 legs

The average inventory is 100 legs.

e)

Summary Introduction

To determine: The number of body parts that needs to be made to minimize the inventory while not constraining the flow through the assembly.

e)

Expert Solution
Check Mark

Explanation of Solution

Given information:

OPERATION MANAGEMENT, Chapter 7, Problem 5PA , additional homework tip  9

1 worker can assemble the horse sculpture in 16 minutes.

Calculation of batch size:

The target capacity is the flow rate at 3.75 sculptures per hour. There is 1 body in each component set. Therefore, the batch size will be:

Batch size=Target capacity×Total setup time60 minutes1-(Flow rate×Processing time60 minutes)×1 Body part=3.75×50601-(3.75×1260)×1=12.5 body

The body parts batch size is 12.5 body.

f)

Summary Introduction

To determine: The number of leg parts that needs to be made to minimize the inventory while not constraining the flow through the assembly.

f)

Expert Solution
Check Mark

Explanation of Solution

Given information:

OPERATION MANAGEMENT, Chapter 7, Problem 5PA , additional homework tip  10

1 worker can assemble the horse sculpture in 16 minutes.

Calculation of batch size:

The target capacity is the flow rate at 3.75 sculptures per hour. There is 4 body in each component set. Therefore, the batch size will be:

Batch size=Target capacity×Total setup time60 minutes1-(Flow rate×Processing time60 minutes)×4 Leg part=3.75×50601-(3.75×1260)×4=50 leg

The leg parts batch size is 50 leg.

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