Chapter 7, Problem 57A

Amanda looks at a 1.0-kg bag of jellybeans resting on a table.

a. Calculate the amount of force that the table exerts on the bag of jellybeans.

b. How does this compare with the force that the bag of jellybeans exerts on the table?

To determine

The amount of force that the table exerts on the bag of jellybeans.

Answer to Problem 57A

The amount of force that the table exerts on the bag of jellybeans is $9.8\text{ N}$ .

Explanation of Solution

Given info:

The mass of the bag of jellybeans is $m=1.0\text{ kg}$ .

Formula used:

The expression for Newton’s law of motion as follows:

  $F=mg$

Here, $m$ is the mass and $g$ is the acceleration due to gravity.

Calculation:

Consider the acceleration due to gravity as $g=9.8\text{m}/{\text{s}}^{\text{2}}$ .

Find the amount of force that the table exerts on the bag of jellybeans as follows:

  $\begin{array}{l}F=mg\\ F=\left(1.0\text{ kg}\right)\left(9.8\text{m}/{\text{s}}^{\text{2}}\right)\\ F=9.8\text{ N}\end{array}$

Conclusion:

Thus, the amount of force that the table exerts on the bag of jellybeans is $9.8\text{ N}$ .

To determine

To Compare: The amount of force that the table exerts on the bag of jellybeans with the force that the bag of jellybeans exerts on the table.

Answer to Problem 57A

The force that the bag of jellybeans exerts on the table is equal and opposite to the amount of force that the table exerts on the bag of jellybeans.

Explanation of Solution

Given info:

The mass of the bag of jellybeans is $m=1.0\text{ kg}$ .

Introduction:

The expression for Newton’s third law of motion as follows:

  $F_{\text{x}}=-F_{\text{x1}}$

Calculation:

Refer part (a).

The amount of force that the table exerts on the bag of jellybeans $F=9.8\text{ N}$ .

According to Newton’s third law of motion, the that the bag of jellybeans exerts on the table is $-9.8\text{ N}$ .

Conclusion:

Thus, the force that the bag of jellybeans exerts on the table is equal and opposite to the amount of force that the table exerts on the bag of jellybeans.