
Concept explainers
Using the rules for parallel circuits and Ohm’slaw, solve for the missing values.

The missing values in the given table using rules for parallel circuit and ohm’s law.
Answer to Problem 4PP
ET = 240.24 V | E1 = 240.24 V | E2 = 240.24 V | E3 = 240.24 V | E4 = 240.24 V |
IT = 14.30 mA | I1 = 2.92 mA | I2 = 3.20 mA | I3 = 4.29 mA | I4 = 3.87 mA |
RT= 16.80 kΩ | R1 = 82kΩ | R2 = 75kΩ | R3 = 56kΩ | R4 = 62 kΩ |
PT = 3.436W | P1 = 0.6991 W | P2 = 0.768 W | P3 = 1.0306 W | P4 = 0.9285 W |
Explanation of Solution
Description:
In a parallel circuit, the total resistance is equal to the reciprocal of the sum of reciprocal resistances of the individual branches.
Substitute the values and compute the unknown resistor RT
Using the values for total power dissipation and total resistance, we can calculate the total current IT
Using the Total current and Total resistance, we calculate the Total voltage ET
By rule of parallel circuits, the total voltage drop across any branch of a parallel circuit is the same as the applied voltage. Therefore,
The current flowing in individual branches can be calculated from the voltage and resistor values. Therefore,
The power consumed by the resistors is given as,
Conclusion:
The missing values in the given table have been calculated using rules for parallel circuit and ohm’s law.
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Chapter 7 Solutions
Delmar's Standard Textbook Of Electricity
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- Delmar's Standard Textbook Of ElectricityElectrical EngineeringISBN:9781337900348Author:Stephen L. HermanPublisher:Cengage Learning
