Two-dimensional array: • A two-dimensional array is also referred as 2D arrays which can store multiple collections of data. • It contains the rows and columns of elements. • In two-dimensional array, normally the first subscript is called as row size and the second subscript is called as column size. • All the rows will have equal number of columns. So, the arrangement of array elements looks like rectangular structure. Declaration of two-dimensional array: The two size declarators are needed to declare the two-dimensional array. • First indicates the number of rows. • Second indicates the number of columns. The syntax to declare the two-dimensional array is given below: datatype[,] arrName = new datatype[rows, columns]; Where, • “datatype” indicates the data type of variable. • “arrName” indicates the name of two-dimensional array variable. • “rows” indicates the number of rows. • “columns” indicates the number of columns.

Question

Want to see the full answer?

Answer 1

Question

Chapter 7, Problem 4AW

Program Plan Intro

Two-dimensional array:

• A two-dimensional array is also referred as 2D arrays which can store multiple collections of data.

• It contains the rows and columns of elements.

• In two-dimensional array, normally the first subscript is called as row size and the second subscript is called as column size.

• All the rows will have equal number of columns. So, the arrangement of array elements looks like rectangular structure.

Declaration of two-dimensional array:

The two size declarators are needed to declare the two-dimensional array.

• First indicates the number of rows.

• Second indicates the number of columns.

The syntax to declare the two-dimensional array is given below:

datatype[,] arrName = new datatype[rows, columns];

Where,

• “datatype” indicates the data type of variable.

• “arrName” indicates the name of two-dimensional array variable.

• “rows” indicates the number of rows.

• “columns” indicates the number of columns.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

using r language for integration theta = integral 0 to infinity (x^4)*e^(-x^2)/2 dx (1) use the density function of standard normal distribution N(0,1) f(x) = 1/sqrt(2pi) * e^(-x^2)/2 -infinity <x<infinity as importance function and obtain an estimate theta 1 for theta set m=100 for the estimate whatt is the estimate theta 1? (2)use the density function of gamma (r=5 λ=1/2)distribution f(x)=λ^r/Γ(r) x^(r-1)e^(-λx) x>=0 as importance function and obtain an estimate theta 2 for theta set m=1000 fir the estimate what is the estimate theta2? (3) use simulation (repeat 1000 times) to estimate the variance of the estimates theta1 and theta 2 which one has smaller variance?

using r language A continuous random variable X has density function f(x)=1/56(3x^2+4x^3+5x^4).0<=x<=2 (1) secify the density g of the random variable Y you find for the acceptance rejection method. (2) what is the value of c you choose to use for the acceptance rejection method (3) use the acceptance rejection method to generate a random sample of size 1000 from the distribution of X .graph the density histogram of the sample and compare it with the density function f(x)

using r language a continuous random variable X has density function f(x)=1/4x^3e^-(pi/2)^4,x>=0 derive the probability inverse transformation F^(-1)x where F(x) is the cdf of the random variable X