The products formed due to elimination and most likely mechanism for below reaction should be written. Concept introduction: Carbocations generated from alkyl halides have two fates; they can be either trapped by nucleophiles to give substitution product or may deprotonate to yield a small amount of alkene . If the leaving group present eliminates along with a proton in absence of any strong nucleophile the double bond formation might occur. Such reactions are known as two-step unimolecuar elimination, abbreviated as E2 .If the still higher concentration is employed, reaction proceeds via bimolecular elimination. On the other hand, the weak base waits until the carbocation is formed and the type of elimination with a relatively weak base is two-step elimination or E1 .

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Answer 1

Question

Chapter 7, Problem 43P

(a)

Interpretation Introduction

Interpretation: The products formed due to elimination and most likely mechanism for below reaction should be written.

Concept introduction: Carbocations generated from alkyl halides have two fates; they can be either trapped by nucleophiles to give substitution product or may deprotonate to yield a small amount of alkene.

If the leaving group present eliminates along with a proton in absence of any strong nucleophile the double bond formation might occur. Such reactions are known as two-step unimolecuar elimination, abbreviated as E2 .If the still higher concentration is employed, reaction proceeds via bimolecular elimination. On the other hand, the weak base waits until the carbocation is formed and the type of elimination with a relatively weak base is two-step elimination or E1 .

(b)

Interpretation Introduction

Interpretation: The products formed due to elimination and most likely mechanism for below reaction should be written.

Concept introduction: Carbocations generated from alkyl halides have two fates; they can be either trapped by nucleophiles to give substitution product or may deprotonate to yield a small amount of alkene.

If the leaving group present eliminates along with a proton in absence of any strong nucleophile the double bond formation might occur. Such reactions are known as two-step unimolecuar elimination, abbreviated as E2 .If the still higher concentration is employed, reaction proceeds via bimolecular elimination. On the other hand, the weak base waits until the carbocation is formed and the type of elimination with a relatively weak base is two-step elimination or E1 .

(c)

Interpretation Introduction

Interpretation: The products formed due to elimination and most likely mechanism for below reactionshould be written.

Concept introduction: Carbocations generated from alkyl halides have two fates; they can be either trapped by nucleophiles to give substitution product or may deprotonate to yield a small amount of alkene.

If the leaving group present eliminates along with a proton in absence of any strong nucleophile the double bond formation might occur. Such reactions are known as two-step unimolecuar elimination, abbreviated as E2 .If the still higher concentration is employed, reaction proceeds via bimolecular elimination. On the other hand, the weak base waits until the carbocation is formed and the type of elimination with a relatively weak base is two-step elimination or E1 .

(d)

Interpretation Introduction

Interpretation: The products formed due to elimination and most likely mechanism should be written.

Concept introduction: Carbocations generated from alkyl halides have two fates; they can be either trapped by nucleophiles to give substitution product or may deprotonate to yield a small amount of alkene.

If the leaving group present eliminates along with a proton in absence of any strong nucleophile the double bond formation might occur. Such reactions are known as two-step unimolecuar elimination, abbreviated as E2 .If the still higher concentration is employed, reaction proceeds via bimolecular elimination. On the other hand, the weak base waits until the carbocation is formed and the type of elimination with a relatively weak base is two-step elimination or E1 .

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Answer 2

Question

Chapter 7, Problem 43P

(a)

Interpretation Introduction

Interpretation: The products formed due to elimination and most likely mechanism for below reaction should be written.

Concept introduction: Carbocations generated from alkyl halides have two fates; they can be either trapped by nucleophiles to give substitution product or may deprotonate to yield a small amount of alkene.

If the leaving group present eliminates along with a proton in absence of any strong nucleophile the double bond formation might occur. Such reactions are known as two-step unimolecuar elimination, abbreviated as E2 .If the still higher concentration is employed, reaction proceeds via bimolecular elimination. On the other hand, the weak base waits until the carbocation is formed and the type of elimination with a relatively weak base is two-step elimination or E1 .

(b)

Interpretation Introduction

Interpretation: The products formed due to elimination and most likely mechanism for below reaction should be written.

Concept introduction: Carbocations generated from alkyl halides have two fates; they can be either trapped by nucleophiles to give substitution product or may deprotonate to yield a small amount of alkene.

If the leaving group present eliminates along with a proton in absence of any strong nucleophile the double bond formation might occur. Such reactions are known as two-step unimolecuar elimination, abbreviated as E2 .If the still higher concentration is employed, reaction proceeds via bimolecular elimination. On the other hand, the weak base waits until the carbocation is formed and the type of elimination with a relatively weak base is two-step elimination or E1 .

(c)

Interpretation Introduction

Interpretation: The products formed due to elimination and most likely mechanism for below reactionshould be written.

Concept introduction: Carbocations generated from alkyl halides have two fates; they can be either trapped by nucleophiles to give substitution product or may deprotonate to yield a small amount of alkene.

If the leaving group present eliminates along with a proton in absence of any strong nucleophile the double bond formation might occur. Such reactions are known as two-step unimolecuar elimination, abbreviated as E2 .If the still higher concentration is employed, reaction proceeds via bimolecular elimination. On the other hand, the weak base waits until the carbocation is formed and the type of elimination with a relatively weak base is two-step elimination or E1 .

(d)

Interpretation Introduction

Interpretation: The products formed due to elimination and most likely mechanism should be written.

Concept introduction: Carbocations generated from alkyl halides have two fates; they can be either trapped by nucleophiles to give substitution product or may deprotonate to yield a small amount of alkene.

If the leaving group present eliminates along with a proton in absence of any strong nucleophile the double bond formation might occur. Such reactions are known as two-step unimolecuar elimination, abbreviated as E2 .If the still higher concentration is employed, reaction proceeds via bimolecular elimination. On the other hand, the weak base waits until the carbocation is formed and the type of elimination with a relatively weak base is two-step elimination or E1 .

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Answer 3

Question

Chapter 7, Problem 43P

(a)

Interpretation Introduction

Interpretation: The products formed due to elimination and most likely mechanism for below reaction should be written.

Concept introduction: Carbocations generated from alkyl halides have two fates; they can be either trapped by nucleophiles to give substitution product or may deprotonate to yield a small amount of alkene.

If the leaving group present eliminates along with a proton in absence of any strong nucleophile the double bond formation might occur. Such reactions are known as two-step unimolecuar elimination, abbreviated as E2 .If the still higher concentration is employed, reaction proceeds via bimolecular elimination. On the other hand, the weak base waits until the carbocation is formed and the type of elimination with a relatively weak base is two-step elimination or E1 .

(b)

Interpretation Introduction

Interpretation: The products formed due to elimination and most likely mechanism for below reaction should be written.

Concept introduction: Carbocations generated from alkyl halides have two fates; they can be either trapped by nucleophiles to give substitution product or may deprotonate to yield a small amount of alkene.

If the leaving group present eliminates along with a proton in absence of any strong nucleophile the double bond formation might occur. Such reactions are known as two-step unimolecuar elimination, abbreviated as E2 .If the still higher concentration is employed, reaction proceeds via bimolecular elimination. On the other hand, the weak base waits until the carbocation is formed and the type of elimination with a relatively weak base is two-step elimination or E1 .

(c)

Interpretation Introduction

Interpretation: The products formed due to elimination and most likely mechanism for below reactionshould be written.

Concept introduction: Carbocations generated from alkyl halides have two fates; they can be either trapped by nucleophiles to give substitution product or may deprotonate to yield a small amount of alkene.

If the leaving group present eliminates along with a proton in absence of any strong nucleophile the double bond formation might occur. Such reactions are known as two-step unimolecuar elimination, abbreviated as E2 .If the still higher concentration is employed, reaction proceeds via bimolecular elimination. On the other hand, the weak base waits until the carbocation is formed and the type of elimination with a relatively weak base is two-step elimination or E1 .

(d)

Interpretation Introduction

Interpretation: The products formed due to elimination and most likely mechanism should be written.

Concept introduction: Carbocations generated from alkyl halides have two fates; they can be either trapped by nucleophiles to give substitution product or may deprotonate to yield a small amount of alkene.

If the leaving group present eliminates along with a proton in absence of any strong nucleophile the double bond formation might occur. Such reactions are known as two-step unimolecuar elimination, abbreviated as E2 .If the still higher concentration is employed, reaction proceeds via bimolecular elimination. On the other hand, the weak base waits until the carbocation is formed and the type of elimination with a relatively weak base is two-step elimination or E1 .

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Answer 4

Question

Chapter 7, Problem 43P

(a)

Interpretation Introduction

Interpretation: The products formed due to elimination and most likely mechanism for below reaction should be written.

Concept introduction: Carbocations generated from alkyl halides have two fates; they can be either trapped by nucleophiles to give substitution product or may deprotonate to yield a small amount of alkene.

If the leaving group present eliminates along with a proton in absence of any strong nucleophile the double bond formation might occur. Such reactions are known as two-step unimolecuar elimination, abbreviated as E2 .If the still higher concentration is employed, reaction proceeds via bimolecular elimination. On the other hand, the weak base waits until the carbocation is formed and the type of elimination with a relatively weak base is two-step elimination or E1 .

(b)

Interpretation Introduction

Interpretation: The products formed due to elimination and most likely mechanism for below reaction should be written.

Concept introduction: Carbocations generated from alkyl halides have two fates; they can be either trapped by nucleophiles to give substitution product or may deprotonate to yield a small amount of alkene.

If the leaving group present eliminates along with a proton in absence of any strong nucleophile the double bond formation might occur. Such reactions are known as two-step unimolecuar elimination, abbreviated as E2 .If the still higher concentration is employed, reaction proceeds via bimolecular elimination. On the other hand, the weak base waits until the carbocation is formed and the type of elimination with a relatively weak base is two-step elimination or E1 .

(c)

Interpretation Introduction

Interpretation: The products formed due to elimination and most likely mechanism for below reactionshould be written.

Concept introduction: Carbocations generated from alkyl halides have two fates; they can be either trapped by nucleophiles to give substitution product or may deprotonate to yield a small amount of alkene.

If the leaving group present eliminates along with a proton in absence of any strong nucleophile the double bond formation might occur. Such reactions are known as two-step unimolecuar elimination, abbreviated as E2 .If the still higher concentration is employed, reaction proceeds via bimolecular elimination. On the other hand, the weak base waits until the carbocation is formed and the type of elimination with a relatively weak base is two-step elimination or E1 .

(d)

Interpretation Introduction

Interpretation: The products formed due to elimination and most likely mechanism should be written.

Concept introduction: Carbocations generated from alkyl halides have two fates; they can be either trapped by nucleophiles to give substitution product or may deprotonate to yield a small amount of alkene.

If the leaving group present eliminates along with a proton in absence of any strong nucleophile the double bond formation might occur. Such reactions are known as two-step unimolecuar elimination, abbreviated as E2 .If the still higher concentration is employed, reaction proceeds via bimolecular elimination. On the other hand, the weak base waits until the carbocation is formed and the type of elimination with a relatively weak base is two-step elimination or E1 .

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Answer 5

Chapter 7, Problem 43P

(a)

Interpretation Introduction

Interpretation: The products formed due to elimination and most likely mechanism for below reaction should be written.

Concept introduction: Carbocations generated from alkyl halides have two fates; they can be either trapped by nucleophiles to give substitution product or may deprotonate to yield a small amount of alkene.

If the leaving group present eliminates along with a proton in absence of any strong nucleophile the double bond formation might occur. Such reactions are known as two-step unimolecuar elimination, abbreviated as E2 .If the still higher concentration is employed, reaction proceeds via bimolecular elimination. On the other hand, the weak base waits until the carbocation is formed and the type of elimination with a relatively weak base is two-step elimination or E1 .

(b)

Interpretation Introduction

Interpretation: The products formed due to elimination and most likely mechanism for below reaction should be written.

Concept introduction: Carbocations generated from alkyl halides have two fates; they can be either trapped by nucleophiles to give substitution product or may deprotonate to yield a small amount of alkene.

If the leaving group present eliminates along with a proton in absence of any strong nucleophile the double bond formation might occur. Such reactions are known as two-step unimolecuar elimination, abbreviated as E2 .If the still higher concentration is employed, reaction proceeds via bimolecular elimination. On the other hand, the weak base waits until the carbocation is formed and the type of elimination with a relatively weak base is two-step elimination or E1 .

(c)

Interpretation Introduction

Interpretation: The products formed due to elimination and most likely mechanism for below reactionshould be written.

Concept introduction: Carbocations generated from alkyl halides have two fates; they can be either trapped by nucleophiles to give substitution product or may deprotonate to yield a small amount of alkene.

If the leaving group present eliminates along with a proton in absence of any strong nucleophile the double bond formation might occur. Such reactions are known as two-step unimolecuar elimination, abbreviated as E2 .If the still higher concentration is employed, reaction proceeds via bimolecular elimination. On the other hand, the weak base waits until the carbocation is formed and the type of elimination with a relatively weak base is two-step elimination or E1 .

(d)

Interpretation Introduction

Interpretation: The products formed due to elimination and most likely mechanism should be written.

Concept introduction: Carbocations generated from alkyl halides have two fates; they can be either trapped by nucleophiles to give substitution product or may deprotonate to yield a small amount of alkene.

If the leaving group present eliminates along with a proton in absence of any strong nucleophile the double bond formation might occur. Such reactions are known as two-step unimolecuar elimination, abbreviated as E2 .If the still higher concentration is employed, reaction proceeds via bimolecular elimination. On the other hand, the weak base waits until the carbocation is formed and the type of elimination with a relatively weak base is two-step elimination or E1 .

Answer 6

Chapter 7, Problem 43P

(a)

Interpretation Introduction

Interpretation: The products formed due to elimination and most likely mechanism for below reaction should be written.

Concept introduction: Carbocations generated from alkyl halides have two fates; they can be either trapped by nucleophiles to give substitution product or may deprotonate to yield a small amount of alkene.

If the leaving group present eliminates along with a proton in absence of any strong nucleophile the double bond formation might occur. Such reactions are known as two-step unimolecuar elimination, abbreviated as E2 .If the still higher concentration is employed, reaction proceeds via bimolecular elimination. On the other hand, the weak base waits until the carbocation is formed and the type of elimination with a relatively weak base is two-step elimination or E1 .

Answer 7

Chapter 7, Problem 43P

(a)

Interpretation Introduction

Interpretation: The products formed due to elimination and most likely mechanism for below reaction should be written.

Concept introduction: Carbocations generated from alkyl halides have two fates; they can be either trapped by nucleophiles to give substitution product or may deprotonate to yield a small amount of alkene.

If the leaving group present eliminates along with a proton in absence of any strong nucleophile the double bond formation might occur. Such reactions are known as two-step unimolecuar elimination, abbreviated as E2 .If the still higher concentration is employed, reaction proceeds via bimolecular elimination. On the other hand, the weak base waits until the carbocation is formed and the type of elimination with a relatively weak base is two-step elimination or E1 .

Answer 8

(b)

Interpretation Introduction

Interpretation: The products formed due to elimination and most likely mechanism for below reaction should be written.

Concept introduction: Carbocations generated from alkyl halides have two fates; they can be either trapped by nucleophiles to give substitution product or may deprotonate to yield a small amount of alkene.

If the leaving group present eliminates along with a proton in absence of any strong nucleophile the double bond formation might occur. Such reactions are known as two-step unimolecuar elimination, abbreviated as E2 .If the still higher concentration is employed, reaction proceeds via bimolecular elimination. On the other hand, the weak base waits until the carbocation is formed and the type of elimination with a relatively weak base is two-step elimination or E1 .

Answer 9

(b)

Interpretation Introduction

Interpretation: The products formed due to elimination and most likely mechanism for below reaction should be written.

Concept introduction: Carbocations generated from alkyl halides have two fates; they can be either trapped by nucleophiles to give substitution product or may deprotonate to yield a small amount of alkene.

If the leaving group present eliminates along with a proton in absence of any strong nucleophile the double bond formation might occur. Such reactions are known as two-step unimolecuar elimination, abbreviated as E2 .If the still higher concentration is employed, reaction proceeds via bimolecular elimination. On the other hand, the weak base waits until the carbocation is formed and the type of elimination with a relatively weak base is two-step elimination or E1 .

Answer 10

(c)

Interpretation Introduction

Interpretation: The products formed due to elimination and most likely mechanism for below reactionshould be written.

Concept introduction: Carbocations generated from alkyl halides have two fates; they can be either trapped by nucleophiles to give substitution product or may deprotonate to yield a small amount of alkene.

If the leaving group present eliminates along with a proton in absence of any strong nucleophile the double bond formation might occur. Such reactions are known as two-step unimolecuar elimination, abbreviated as E2 .If the still higher concentration is employed, reaction proceeds via bimolecular elimination. On the other hand, the weak base waits until the carbocation is formed and the type of elimination with a relatively weak base is two-step elimination or E1 .

Answer 11

(c)

Interpretation Introduction

Interpretation: The products formed due to elimination and most likely mechanism for below reactionshould be written.

Concept introduction: Carbocations generated from alkyl halides have two fates; they can be either trapped by nucleophiles to give substitution product or may deprotonate to yield a small amount of alkene.

If the leaving group present eliminates along with a proton in absence of any strong nucleophile the double bond formation might occur. Such reactions are known as two-step unimolecuar elimination, abbreviated as E2 .If the still higher concentration is employed, reaction proceeds via bimolecular elimination. On the other hand, the weak base waits until the carbocation is formed and the type of elimination with a relatively weak base is two-step elimination or E1 .

Answer 12

(d)

Interpretation Introduction

Interpretation: The products formed due to elimination and most likely mechanism should be written.

Concept introduction: Carbocations generated from alkyl halides have two fates; they can be either trapped by nucleophiles to give substitution product or may deprotonate to yield a small amount of alkene.

If the leaving group present eliminates along with a proton in absence of any strong nucleophile the double bond formation might occur. Such reactions are known as two-step unimolecuar elimination, abbreviated as E2 .If the still higher concentration is employed, reaction proceeds via bimolecular elimination. On the other hand, the weak base waits until the carbocation is formed and the type of elimination with a relatively weak base is two-step elimination or E1 .

Answer 13

(d)

Interpretation Introduction

Interpretation: The products formed due to elimination and most likely mechanism should be written.

Concept introduction: Carbocations generated from alkyl halides have two fates; they can be either trapped by nucleophiles to give substitution product or may deprotonate to yield a small amount of alkene.

If the leaving group present eliminates along with a proton in absence of any strong nucleophile the double bond formation might occur. Such reactions are known as two-step unimolecuar elimination, abbreviated as E2 .If the still higher concentration is employed, reaction proceeds via bimolecular elimination. On the other hand, the weak base waits until the carbocation is formed and the type of elimination with a relatively weak base is two-step elimination or E1 .

Answer 14

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Answer 15

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Answer 16

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Answer 17

Ch. 7.1 - Prob. 7.1E Ch. 7.2 - Prob. 7.2E Ch. 7.3 - Prob. 7.3E Ch. 7.3 - Prob. 7.5TIY Ch. 7.4 - Prob. 7.7TIY Ch. 7.5 - Prob. 7.9TIY Ch. 7.6 - Prob. 7.10E Ch. 7.7 - Prob. 7.11E Ch. 7.7 - Prob. 7.12E Ch. 7.7 - Prob. 7.13E

Solution Summary: The author explains that carbocations generated from alkyl halides have two fates; they can be either trapped by nucleophiles to give substitution product or may deprotonate to yield a small amount

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