Concept explainers
Suppose you exert 200 N on your refrigerator and push it across the kitchen floor at constant velocity. What friction force acts between the refrigerator and the floor? Is the friction force equal and opposite to your 200-N push? Does the friction force make up the reaction force to your push?
The friction force between the refrigerator and the floor.
To identify: Whether the friction force equal and opposite to the
Answer to Problem 42A
The friction force acts between the refrigerator and floor is
The friction force equal and opposite to the
The friction force does not make up the reaction force to the push.
Explanation of Solution
Given:
Force exerted on refrigerator is 20 N.
Formula used:
The frictional force which is acting in between any of the two surfaces will depends on the type of material with which it is in contact.
The expression for friction force is
Here,
Calculation:
The net force acting on the block is zero due to the constant velocity. So the friction force acting on the floor is equal and opposite to the force exerted on the system.
Hence, the friction force that is acting between the refrigerator and floor will be
The reaction force is the force applied by the body on an object. Hence, the friction force will not exert the reaction force. Also, the friction force does not make up the reaction force to the push.
Conclusion:
Thus, the friction force acts between the refrigerator and floor is
Thus, the friction force equal and opposite to the
Thus, the friction force does not make up the reaction force to the push.
Chapter 7 Solutions
CONCEPTUAL PHYSICS-W/PRACTICING PHYSICS
Additional Science Textbook Solutions
Introductory Chemistry (6th Edition)
Microbiology with Diseases by Body System (5th Edition)
Anatomy & Physiology (6th Edition)
Microbiology: An Introduction
Organic Chemistry (8th Edition)
Campbell Essential Biology (7th Edition)
- two satellites are in circular orbits around the Earth. Satellite A is at an altitude equal to the Earth's radius, while satellite B is at an altitude equal to twice the Earth's radius. What is the ratio of their periods, Tb/Taarrow_forwardFresnel lens: You would like to design a 25 mm diameter blazed Fresnel zone plate with a first-order power of +1.5 diopters. What is the lithography requirement (resolution required) for making this lens that is designed for 550 nm? Express your answer in units of μm to one decimal point. Fresnel lens: What would the power of the first diffracted order of this lens be at wavelength of 400 nm? Express your answer in diopters to one decimal point. Eye: A person with myopic eyes has a far point of 15 cm. What power contact lenses does she need to correct her version to a standard far point at infinity? Give your answer in diopter to one decimal point.arrow_forwardParaxial design of a field flattener. Imagine your optical system has Petzal curvature of the field with radius p. In Module 1 of Course 1, a homework problem asked you to derive the paraxial focus shift along the axis when a slab of glass was inserted in a converging cone of rays. Find or re-derive that result, then use it to calculate the paraxial radius of curvature of a field flattener of refractive index n that will correct the observed Petzval. Assume that the side of the flattener facing the image plane is plano. What is the required radius of the plano-convex field flattener? (p written as rho )arrow_forward
- 3.37(a) Five free electrons exist in a three-dimensional infinite potential well with all three widths equal to \( a = 12 \, \text{Å} \). Determine the Fermi energy level at \( T = 0 \, \text{K} \). (b) Repeat part (a) for 13 electrons. Book: Semiconductor Physics and Devices 4th ed, NeamanChapter-3Please expert answer only. don't give gpt-generated answers, & please clear the concept of quantum states for determining nx, ny, nz to determine E, as I don't have much idea about that topic.arrow_forward3.37(a) Five free electrons exist in a three-dimensional infinite potential well with all three widths equal to \( a = 12 \, \text{Å} \). Determine the Fermi energy level at \( T = 0 \, \text{K} \). (b) Repeat part (a) for 13 electrons. Book: Semiconductor Physics and Devices 4th ed, NeamanChapter-3Please expert answer only. don't give gpt-generated answers, & please clear the concept of quantum states for determining nx, ny, nz to determine E, as I don't have much idea about that topic.arrow_forwardNo chatgpt pls will upvotearrow_forward
- Use the following information to answer the next question. Two mirrors meet an angle, a, of 105°. A ray of light is incident upon mirror A at an angle, i, of 42°. The ray of light reflects off mirror B and then enters water, as shown below: Incident ray at A Note: This diagram is not to scale. a Air (n = 1.00) Water (n = 1.34) 1) Determine the angle of refraction of the ray of light in the water. Barrow_forwardHi can u please solvearrow_forward6. Bending a lens in OpticStudio or OSLO. In either package, create a BK7 singlet lens of 10 mm semi-diameter and with 10 mm thickness. Set the wavelength to the (default) 0.55 microns and a single on-axis field point at infinite object distance. Set the image distance to 200 mm. Make the first surface the stop insure that the lens is fully filled (that is, that the entrance beam has a radius of 10 mm). Use the lens-maker's equation to calculate initial glass curvatures assuming you want a symmetric, bi-convex lens with an effective focal length of 200 mm. Get this working and examine the RMS spot size using the "Text" tab of the Spot Diagram analysis tab (OpticStudio) or the Spd command of the text widnow (OSLO). You should find the lens is far from diffraction limited, with a spot size of more than 100 microns. Now let's optimize this lens. In OpticStudio, create a default merit function optimizing on spot size.Then insert one extra line at the top of the merit function. Assign the…arrow_forward
- No chatgpt pls will upvote Already got wrong chatgpt answer .arrow_forwardUse the following information to answer the next question. Two mirrors meet an angle, a, of 105°. A ray of light is incident upon mirror A at an angle, i, of 42°. The ray of light reflects off mirror B and then enters water, as shown below: A Incident ray at A Note: This diagram is not to scale. Air (n = 1.00) Water (n = 1.34) Barrow_forwardUse the following information to answer the next question. Two mirrors meet an angle, a, of 105°. A ray of light is incident upon mirror A at an angle, i, of 42°. The ray of light reflects off mirror B and then enters water, as shown below: A Incident ray at A Note: This diagram is not to scale. Air (n = 1.00) Water (n = 1.34) Barrow_forward
- College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningUniversity Physics (14th Edition)PhysicsISBN:9780133969290Author:Hugh D. Young, Roger A. FreedmanPublisher:PEARSONIntroduction To Quantum MechanicsPhysicsISBN:9781107189638Author:Griffiths, David J., Schroeter, Darrell F.Publisher:Cambridge University Press
- Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningLecture- Tutorials for Introductory AstronomyPhysicsISBN:9780321820464Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina BrissendenPublisher:Addison-WesleyCollege Physics: A Strategic Approach (4th Editio...PhysicsISBN:9780134609034Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart FieldPublisher:PEARSON