Sigma bonds in the molecule have to be located and have to be counted. Concept Introduction: Sigma (σ) bonds are the bonds in which shared hybrid orbital’s electron density are concentrated along the internuclear axis.

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Answer 1

Question

Chapter 7, Problem 41QRT

(a)

Interpretation Introduction

Interpretation:

Sigma bonds in the molecule have to be located and have to be counted.

Concept Introduction:

Sigma (σ) bonds are the bonds in which shared hybrid orbital’s electron density are concentrated along the internuclear axis.

(b)

Interpretation Introduction

Interpretation:

Pi bonds in the molecule have to be located and have to be counted.

Concept Introduction:

Pi (π) bonds are the bonds in which shared un-hybridized orbital’s (p, d, etc) electron density are concentrated in above and below the plane of the molecule.

(c)

Interpretation Introduction

Interpretation:

Hybridization of carbon atom that is bonded to the nitrogen atom in the molecule has to be given.

Concept Introduction:

Hybridization is the mixing of valence atomic orbitals to get equivalent hybridized orbitals that having similar characteristics and energy.

Geometry of different types of molecule with respect to the hybridizations is mentioned are mentioned below,

Type of moleculeHybridaization Atomic orbitals used for hybridaization GeometryAX2sp1s+1pLinearAX3,AX2Bsp21s+2pTrigonal planarAX4,AX3B,AX2B2sp31s+3pTetrahedralAX5,AX4B,AX3B2,AX2B3sp3d1s+3p+1dTrigonal bipyramidalAX6,AX5B,AX4B2sp3d21s+3p+2dOctahedralA → Central atomX → Atoms bonded to AB → Non bonding electron pairs on A

(d)

Interpretation Introduction

Interpretation:

Hybridization of nitrogen atom in the molecule has to be given.

Concept Introduction:

Refer to (c).

(e)

Interpretation Introduction

Interpretation:

Hybridization of hydrogen bearing carbon atoms in the molecule has to be given.

Concept Introduction:

Refer to (c).

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Answer 2

Question

Chapter 7, Problem 41QRT

(a)

Interpretation Introduction

Interpretation:

Sigma bonds in the molecule have to be located and have to be counted.

Concept Introduction:

Sigma (σ) bonds are the bonds in which shared hybrid orbital’s electron density are concentrated along the internuclear axis.

(b)

Interpretation Introduction

Interpretation:

Pi bonds in the molecule have to be located and have to be counted.

Concept Introduction:

Pi (π) bonds are the bonds in which shared un-hybridized orbital’s (p, d, etc) electron density are concentrated in above and below the plane of the molecule.

(c)

Interpretation Introduction

Interpretation:

Hybridization of carbon atom that is bonded to the nitrogen atom in the molecule has to be given.

Concept Introduction:

Hybridization is the mixing of valence atomic orbitals to get equivalent hybridized orbitals that having similar characteristics and energy.

Geometry of different types of molecule with respect to the hybridizations is mentioned are mentioned below,

Type of moleculeHybridaization Atomic orbitals used for hybridaization GeometryAX2sp1s+1pLinearAX3,AX2Bsp21s+2pTrigonal planarAX4,AX3B,AX2B2sp31s+3pTetrahedralAX5,AX4B,AX3B2,AX2B3sp3d1s+3p+1dTrigonal bipyramidalAX6,AX5B,AX4B2sp3d21s+3p+2dOctahedralA → Central atomX → Atoms bonded to AB → Non bonding electron pairs on A

(d)

Interpretation Introduction

Interpretation:

Hybridization of nitrogen atom in the molecule has to be given.

Concept Introduction:

Refer to (c).

(e)

Interpretation Introduction

Interpretation:

Hybridization of hydrogen bearing carbon atoms in the molecule has to be given.

Concept Introduction:

Refer to (c).

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Answer 3

Question

Chapter 7, Problem 41QRT

(a)

Interpretation Introduction

Interpretation:

Sigma bonds in the molecule have to be located and have to be counted.

Concept Introduction:

Sigma (σ) bonds are the bonds in which shared hybrid orbital’s electron density are concentrated along the internuclear axis.

(b)

Interpretation Introduction

Interpretation:

Pi bonds in the molecule have to be located and have to be counted.

Concept Introduction:

Pi (π) bonds are the bonds in which shared un-hybridized orbital’s (p, d, etc) electron density are concentrated in above and below the plane of the molecule.

(c)

Interpretation Introduction

Interpretation:

Hybridization of carbon atom that is bonded to the nitrogen atom in the molecule has to be given.

Concept Introduction:

Hybridization is the mixing of valence atomic orbitals to get equivalent hybridized orbitals that having similar characteristics and energy.

Geometry of different types of molecule with respect to the hybridizations is mentioned are mentioned below,

Type of moleculeHybridaization Atomic orbitals used for hybridaization GeometryAX2sp1s+1pLinearAX3,AX2Bsp21s+2pTrigonal planarAX4,AX3B,AX2B2sp31s+3pTetrahedralAX5,AX4B,AX3B2,AX2B3sp3d1s+3p+1dTrigonal bipyramidalAX6,AX5B,AX4B2sp3d21s+3p+2dOctahedralA → Central atomX → Atoms bonded to AB → Non bonding electron pairs on A

(d)

Interpretation Introduction

Interpretation:

Hybridization of nitrogen atom in the molecule has to be given.

Concept Introduction:

Refer to (c).

(e)

Interpretation Introduction

Interpretation:

Hybridization of hydrogen bearing carbon atoms in the molecule has to be given.

Concept Introduction:

Refer to (c).

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Answer 4

Question

Chapter 7, Problem 41QRT

(a)

Interpretation Introduction

Interpretation:

Sigma bonds in the molecule have to be located and have to be counted.

Concept Introduction:

Sigma (σ) bonds are the bonds in which shared hybrid orbital’s electron density are concentrated along the internuclear axis.

(b)

Interpretation Introduction

Interpretation:

Pi bonds in the molecule have to be located and have to be counted.

Concept Introduction:

Pi (π) bonds are the bonds in which shared un-hybridized orbital’s (p, d, etc) electron density are concentrated in above and below the plane of the molecule.

(c)

Interpretation Introduction

Interpretation:

Hybridization of carbon atom that is bonded to the nitrogen atom in the molecule has to be given.

Concept Introduction:

Hybridization is the mixing of valence atomic orbitals to get equivalent hybridized orbitals that having similar characteristics and energy.

Geometry of different types of molecule with respect to the hybridizations is mentioned are mentioned below,

Type of moleculeHybridaization Atomic orbitals used for hybridaization GeometryAX2sp1s+1pLinearAX3,AX2Bsp21s+2pTrigonal planarAX4,AX3B,AX2B2sp31s+3pTetrahedralAX5,AX4B,AX3B2,AX2B3sp3d1s+3p+1dTrigonal bipyramidalAX6,AX5B,AX4B2sp3d21s+3p+2dOctahedralA → Central atomX → Atoms bonded to AB → Non bonding electron pairs on A

(d)

Interpretation Introduction

Interpretation:

Hybridization of nitrogen atom in the molecule has to be given.

Concept Introduction:

Refer to (c).

(e)

Interpretation Introduction

Interpretation:

Hybridization of hydrogen bearing carbon atoms in the molecule has to be given.

Concept Introduction:

Refer to (c).

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Answer 5

Chapter 7, Problem 41QRT

(a)

Interpretation Introduction

Interpretation:

Sigma bonds in the molecule have to be located and have to be counted.

Concept Introduction:

Sigma (σ) bonds are the bonds in which shared hybrid orbital’s electron density are concentrated along the internuclear axis.

(b)

Interpretation Introduction

Interpretation:

Pi bonds in the molecule have to be located and have to be counted.

Concept Introduction:

Pi (π) bonds are the bonds in which shared un-hybridized orbital’s (p, d, etc) electron density are concentrated in above and below the plane of the molecule.

(c)

Interpretation Introduction

Interpretation:

Hybridization of carbon atom that is bonded to the nitrogen atom in the molecule has to be given.

Concept Introduction:

Hybridization is the mixing of valence atomic orbitals to get equivalent hybridized orbitals that having similar characteristics and energy.

Geometry of different types of molecule with respect to the hybridizations is mentioned are mentioned below,

Type of moleculeHybridaization Atomic orbitals used for hybridaization GeometryAX2sp1s+1pLinearAX3,AX2Bsp21s+2pTrigonal planarAX4,AX3B,AX2B2sp31s+3pTetrahedralAX5,AX4B,AX3B2,AX2B3sp3d1s+3p+1dTrigonal bipyramidalAX6,AX5B,AX4B2sp3d21s+3p+2dOctahedralA → Central atomX → Atoms bonded to AB → Non bonding electron pairs on A

(d)

Interpretation Introduction

Interpretation:

Hybridization of nitrogen atom in the molecule has to be given.

Concept Introduction:

Refer to (c).

(e)

Interpretation Introduction

Interpretation:

Hybridization of hydrogen bearing carbon atoms in the molecule has to be given.

Concept Introduction:

Refer to (c).

Answer 6

Chapter 7, Problem 41QRT

(a)

Interpretation Introduction

Interpretation:

Sigma bonds in the molecule have to be located and have to be counted.

Concept Introduction:

Sigma (σ) bonds are the bonds in which shared hybrid orbital’s electron density are concentrated along the internuclear axis.

Answer 7

Chapter 7, Problem 41QRT

(a)

Interpretation Introduction

Interpretation:

Sigma bonds in the molecule have to be located and have to be counted.

Concept Introduction:

Sigma (σ) bonds are the bonds in which shared hybrid orbital’s electron density are concentrated along the internuclear axis.

Answer 8

(b)

Interpretation Introduction

Interpretation:

Pi bonds in the molecule have to be located and have to be counted.

Concept Introduction:

Pi (π) bonds are the bonds in which shared un-hybridized orbital’s (p, d, etc) electron density are concentrated in above and below the plane of the molecule.

Answer 9

(b)

Interpretation Introduction

Interpretation:

Pi bonds in the molecule have to be located and have to be counted.

Concept Introduction:

Pi (π) bonds are the bonds in which shared un-hybridized orbital’s (p, d, etc) electron density are concentrated in above and below the plane of the molecule.

Answer 10

(c)

Interpretation Introduction

Interpretation:

Hybridization of carbon atom that is bonded to the nitrogen atom in the molecule has to be given.

Concept Introduction:

Hybridization is the mixing of valence atomic orbitals to get equivalent hybridized orbitals that having similar characteristics and energy.

Geometry of different types of molecule with respect to the hybridizations is mentioned are mentioned below,

Type of moleculeHybridaization Atomic orbitals used for hybridaization GeometryAX2sp1s+1pLinearAX3,AX2Bsp21s+2pTrigonal planarAX4,AX3B,AX2B2sp31s+3pTetrahedralAX5,AX4B,AX3B2,AX2B3sp3d1s+3p+1dTrigonal bipyramidalAX6,AX5B,AX4B2sp3d21s+3p+2dOctahedralA → Central atomX → Atoms bonded to AB → Non bonding electron pairs on A

Answer 11

(c)

Interpretation Introduction

Interpretation:

Hybridization of carbon atom that is bonded to the nitrogen atom in the molecule has to be given.

Concept Introduction:

Hybridization is the mixing of valence atomic orbitals to get equivalent hybridized orbitals that having similar characteristics and energy.

Geometry of different types of molecule with respect to the hybridizations is mentioned are mentioned below,

Type of moleculeHybridaization Atomic orbitals used for hybridaization GeometryAX2sp1s+1pLinearAX3,AX2Bsp21s+2pTrigonal planarAX4,AX3B,AX2B2sp31s+3pTetrahedralAX5,AX4B,AX3B2,AX2B3sp3d1s+3p+1dTrigonal bipyramidalAX6,AX5B,AX4B2sp3d21s+3p+2dOctahedralA → Central atomX → Atoms bonded to AB → Non bonding electron pairs on A

Answer 12

(d)

Interpretation Introduction

Interpretation:

Hybridization of nitrogen atom in the molecule has to be given.

Concept Introduction:

Refer to (c).

Answer 13

(d)

Interpretation Introduction

Interpretation:

Hybridization of nitrogen atom in the molecule has to be given.

Concept Introduction:

Refer to (c).

Answer 14

(e)

Interpretation Introduction

Interpretation:

Hybridization of hydrogen bearing carbon atoms in the molecule has to be given.

Concept Introduction:

Refer to (c).

Answer 15

(e)

Interpretation Introduction

Interpretation:

Hybridization of hydrogen bearing carbon atoms in the molecule has to be given.

Concept Introduction:

Refer to (c).

Answer 16

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Answer 17

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Answer 18

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Answer 19

Ch. 7.2 - Identify the electron-region geometry, the...Ch. 7.2 - Based on the discussion so far, identify a...Ch. 7.2 - Prob. 7.2PSP Ch. 7.2 - Determine the electron-region geometry and the...Ch. 7.2 - Prob. 7.2CE Ch. 7.2 - Prob. 7.3E Ch. 7.2 - Prob. 7.4PSP Ch. 7.4 - Using hybridization and sigma and pi bonding,...Ch. 7.4 - Prob. 7.4CE Ch. 7.5 - Decide whether each molecule is polar and, if so,...

Sigma bonds in the molecule have to be located and have to be counted. Concept Introduction: Sigma (σ) bonds are the bonds in which shared hybrid orbital’s electron density are concentrated along the internuclear axis.

Solution Summary: The author explains that sigma bonds are the bonds in which shared hybrid orbital’s electron density are concentrated along the internuclear axis.

Concept explainers

Videos

Interpretation:

Sigma bonds in the molecule have to be located and have to be counted.

Concept Introduction:

Sigma (σ) bonds are the bonds in which shared hybrid orbital’s electron density are concentrated along the internuclear axis.

Interpretation:

Pi bonds in the molecule have to be located and have to be counted.

Concept Introduction:

Pi (π) bonds are the bonds in which shared un-hybridized orbital’s (p, d, etc) electron density are concentrated in above and below the plane of the molecule.

Interpretation:

Hybridization of nitrogen atom in the molecule has to be given.

Concept Introduction:

Refer to (c).

Interpretation:

Hybridization of hydrogen bearing carbon atoms in the molecule has to be given.

Concept Introduction:

Refer to (c).

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Chapter 7 Solutions

Sigma bonds in the molecule have to be located and have to be counted. Concept Introduction: Sigma (σ) bonds are the bonds in which shared hybrid orbital’s electron density are concentrated along the internuclear axis.

Solution Summary: The author explains that sigma bonds are the bonds in which shared hybrid orbital’s electron density are concentrated along the internuclear axis.

Concept explainers

Videos

Interpretation: Sigma bonds in the molecule have to be located and have to be counted. Concept Introduction: Sigma (σ) bonds are the bonds in which shared hybrid orbital’s electron density are concentrated along the internuclear axis.

Interpretation: Pi bonds in the molecule have to be located and have to be counted. Concept Introduction: Pi (π) bonds are the bonds in which shared un-hybridized orbital’s (p, d, etc) electron density are concentrated in above and below the plane of the molecule.

Interpretation: Hybridization of nitrogen atom in the molecule has to be given. Concept Introduction: Refer to (c).

Interpretation: Hybridization of hydrogen bearing carbon atoms in the molecule has to be given. Concept Introduction: Refer to (c).

Want to see the full answer?

Chapter 7 Solutions

Interpretation:

Sigma bonds in the molecule have to be located and have to be counted.

Concept Introduction:

Sigma (σ) bonds are the bonds in which shared hybrid orbital’s electron density are concentrated along the internuclear axis.

Interpretation:

Pi bonds in the molecule have to be located and have to be counted.

Concept Introduction:

Pi (π) bonds are the bonds in which shared un-hybridized orbital’s (p, d, etc) electron density are concentrated in above and below the plane of the molecule.

Interpretation:

Hybridization of nitrogen atom in the molecule has to be given.

Concept Introduction:

Refer to (c).

Interpretation:

Hybridization of hydrogen bearing carbon atoms in the molecule has to be given.

Concept Introduction:

Refer to (c).