Inquiry into Physics
Inquiry into Physics
8th Edition
ISBN: 9781337515863
Author: Ostdiek
Publisher: Cengage
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Chapter 7, Problem 33Q
To determine

The ranking of the force on each point charges q1 and q2 in the given pairings from the most attractive to most repulsive. The separation, d, between each pair is given. Explain the reasoning you used to arrive at your rankings.

Pair 1:q1=+2 µC;q2= 4 µC and d= 10 cm Pair 2:q1=+2 µC;q2= 2 µC and d= 5 cm Pair 3:q1=+3 µC;q2= +3 µC and d= 10 cm Pair 4:q1=5 µC;q2= 2 µC and d= 20 cm.

Expert Solution & Answer
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Answer to Problem 33Q

Pair 2:F=14.4 N; attractivePair 1:F= 7.2 N; attractivePair 4:F=2.25N; repulsivePair 3:F=8.1 N; repulsive.

Explanation of Solution

Given:

Pair 1:q1=+2 µC;q2= 4 µC and d= 10 cm Pair 2:q1=+2 µC;q2= 2 µC and d= 5 cm Pair 3:q1=+3 µC;q2= +3 µC and d= 10 cm Pair 4:q1=5 µC;q2= 2 µC and d= 20 cm

Concept Used:

Force between two charges is given by Coulomb’s law:

F=Kq1×q2d2

Where, K= 9×109Nm2C-2.

Calculation:

Substitute the given values in the formula F=Kq1×q2d2, we get

Pair 1:F=(9×109)×2×106×4×106(10×102)2 = 7.2 N; attractive force (since the charges have opposite sign)

Pair 2:F=9×109×2×106×2×106(5×102)2= 14.4 N ; attractive force (since the charges have opposite sign)

Pair 3:F=9×109×3×106×3×106(10×102)2= 8.1 N ; repulsive force (since the charges have same sign)

Pair 4:F=9×109×5×106×2×106(20×102)2=2.25 N ; repulsive force (since the charges have same sign)

So, the order is: pair 2 - pair 1 - pair 4 - pair 3.

Conclusion:

The order from the most attractive to most repulsive is: pair 2 - pair 1 - pair 4 - pair 3.

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Chapter 7 Solutions

Inquiry into Physics

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