The recurrence relation h n = h n − 1 + 9 h n − 2 − 9 h n − 3 , ( n ≥ 3 ) with the initial value h 0 = 0 , h 1 = 1 , and h 2 = 2 .

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Chapter 7, Problem 33E

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To solve: The recurrence relation hn=hn−1+9hn−2−9hn−3, (n≥3) with the initial value h0=0, h1=1, and h2=2.

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