EBK BIOLOGY
5th Edition
ISBN: 8220101337627
Author: Maier
Publisher: PEARSON
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Chapter 7, Problem 2AAATB
Summary Introduction
To describe:
A high value of heritability of a trait indicate that the average trait in the population cannot change due to the environmental influence is correct or not.
Introduction:
The quantitative traits are the measurable
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Students have asked these similar questions
A population of cats can be either black or white; the black allele (B) has complete dominance over the white allele. Given a population of 1,000 cats, 720 black and 280 white, determine the allele frequency, the frequency of individuals per genotype, and a number of individuals per genotype.
A gardener grows two different colors of apples under exactly the same environmental
conditions. Red apples have a heritability of 0.14 for the value of apple weight, and green apples
have a heritability of 0.41 for the value of apple weight. The gardener plotted the number of
apples present at each weight. Which graph would you hypothesize represents the red apples?
Number
of
apples
Weight
GRAPH A
Number
of
apples
Weight
GRAPH B
O Graph A
O Graph B
There is not enough information to make a hypothesis.
Fur colour in mice is a single gene trait controlled by two alleles. In a population of 75 mice, 21 are homozygous dominant, 37 are heterozygous dominant, and 17 are homozygous recessive. What is the frequency of the dominant allele in the population? Show all work and record your answer as a value between 0 and 1 rounded to two decimal places.
Chapter 7 Solutions
EBK BIOLOGY
Ch. 7 - What is the relationship between genotype and...Ch. 7 - Prob. 2LTBCh. 7 - Prob. 3LTBCh. 7 - Prob. 4LTBCh. 7 - Prob. 5LTBCh. 7 - Scientists have recently developed a process by...Ch. 7 - What is the physical basis for the independent...Ch. 7 - Prob. 8LTBCh. 7 - Prob. 9LTBCh. 7 - Prob. 10LTB
Ch. 7 - Prob. 1GPCh. 7 - Prob. 2GPCh. 7 - Prob. 3GPCh. 7 - Prob. 4GPCh. 7 - Pfeiffer syndrome is a dominant genetic disease...Ch. 7 - Prob. 6GPCh. 7 - A cross between a pea plant that produces round...Ch. 7 - Prob. 8GPCh. 7 - The allele BRCA2 was identified in families with...Ch. 7 - Two parents both have brown eyes, but they have...Ch. 7 - Prob. 2AAATBCh. 7 - Prob. 3AAATBCh. 7 - Prob. 1CTSCh. 7 - Prob. 2CTSCh. 7 - Prob. 3CTS
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- A population is made up of individuals where 77 have the A1A1 genotype, 65 have the A1 A2 genotype, and 123 have the A2A2 genotype. What is the allele frequency of A1? Answer to 2 decimal places.arrow_forwardMany genetic disorders, such as cystic fibrosis and sickle-cell disease are due to mutations in a recessive allele. You have sampled an isolated population in which you know that the percentage of the homozygous recessive genotype (aa) is 36%. Using that 36%, calculate: 1f. the frequency of the dominant phenotype if "A" is completely dominant over "a” (round to the nearest hundredth)arrow_forwardWhich of the following statements about quantitative genetics is TRUE? Heritability is the measure of the proportion of an individual's phenotype that is due to genetics. QTL mapping provides an overestimate of the number of genes contributing to a quantitative trait. A threshold trait is measured in whole numbers. An H2 value (broad-sense heritability) that approaches 0.0 means that almost all the phenotypic variation is determined by genetic differences. The h2 (narrow-sense heritability) value is a prediction of the impact that selection may have in altering an initial population by artificial selection.arrow_forward
- A given autosomal locus has three possible alleles (A1, A2, and A3). Assuming that the numbers of individuals with the six possible genotypes are as follows, what would be the frequency of the A1 allele in the population? A1A1 = 30 A1A2 = 27 A2A2 = 12 A1A3 = 17 A2A3 = 10 A3A3 = 4 What is the frequency of A1 allele in the population? A. 0.375 B. 0.52 C. 0.305 D. 0.175 E. 0.74arrow_forwardThe graph below shows values for body size in parents and offspring. The data shown are consistent with which of the following situations. ANSWER CHOICES A. variation in body size is completely due to variation in the environment (heritability is 0) B. most of the variation in body size is due to variation in the environment but there is a small effect of genes (heritability is around 0.2) C. variation in body size is completely due to variation in genes (heritability is 1.0) D. most of the variation in body size is due to variation in genes but there is some effect of the environment (heritability is about 0.8)arrow_forwardFlower colour in snapdragon plants is a single gene trait controlled by two alleles.In a population of 350 plants, 56% of the alleles are recessive. What is the frequency of the dominant allele in the gene pool?Record your answer as a value between 0 and 1 rounded to two decimal places.arrow_forward
- A survey was conducted for a certain trait (the ability to roll tongue or inability to roll the tongue) in a population. The result shows that 215 of the respondents can roll their tongue and 85 cannot roll their tongue. The picture below shows a person rolling his tongue. Rolling the tongue into a tube shape is often described as a dominant trait. If the dominant allele is represented by R (can roll tongue) and r represents the recessive allele, calculate the phenotypic frequencies, allele frequencies, the expected numbers of the three genotypic classes and the expected numbers of the two phenotypic classes (assuming random mating). Using chi-square test, determine whether or not this population is in Hardy-Weinberg equilibrium. REMEMBER: Genotype Phenotype HWE term RR and Rr Can roll tongue p2 and 2pq rr Cannot roll tongue q2 Again, follow the format below for your answers. Regarding letter “F” on the format, you will show the computations on how you arrive to the chi-square value…arrow_forwardHeritability is the amount of variation in a trait that can be accounted for by gene variation in a population. Examine the following table and determine which of the following traits has the highest broad sense heritability (H2). Hint: A common environment (in this case the greenhouse) should remove, or at least severely diminish, the amount of trait variation due to the environment. Table 1. Plants were measured in the field and in a common greenhouse environment after 200 days of growth. Each row represents a trait measured in both the field and greenhouse. Columns represent the average phenotype value of all clones of a genotype being measured. The first three columns represent phenotypes observed in the field, the last three columns represent greenhouse observations. A more complex version of this analysis was common in my graduate lab! G107a G556 G1301 G107a G556 G1301 (Blue (Ogden (Snake (Greenhouse) (Greenhouse) (Greenhouse) River) Leaf out 35 River) 62 River) 142 44 65 131…arrow_forwardThe cornsnake (Pantherophis guttatus) has a recessive allele for pigmentation that causes albinism (lack of black pigment) . Normally pigmented cornsnakes will have a wild-type pigmentation containing black coloration. Albino = bb, Wild- %3D Type = BB and Bb. In a population of 800, there are 75 albino individuals. Calculate q, p, p^2, 2pq, q^2.Then determine the number of mottled and orange individuals in the population. Select all the answer below that are correct. Note p2 and p^2 are equivalent notation.arrow_forward
- Out of 10 people (20 alleles), if there are 14 alleles for tongue curling (dominant over non-tongue curling), what is the minimum and maximum number of people who can exhibit the trait? Group of answer choices 7, 9 0, 10 cannot be determined 6, 7 7, 10arrow_forwardExample: I go to a different population of fruit flies that have the same two alleles for eye-color. I suspect that the alleles occur in different frequencies in this second population. I sample 1000 flies and discover 10 that have brown eyes. What are the estimated frequencies of the "R" and "r" alleles in this population? Answer: Again, p2 + 2pq + q2 = 1. The term q2 = the relative frequency of homozygous recessive individuals, which corresponds to the ten brown-eyed flies I counted out of 1000 flies sampled. Thus, q2 = 10/1000 = 1/100. q = the square root of 1/100 or 0.1. Thus the frequency of "r" in this second population is 0.1 and the frequency of the "R" allele is 1 - q or 0.9. Problem 1: Phenylketonuria (PKU) is a disease caused by the build-up of the byproducts of metabolizing phenylalanine. It is caused by a defective, recessive allele. If a child is homozygous for this recessive allele, it will develop PKU. In the United States, PKU is detected in approximately 1 in 10,000…arrow_forwardAssume that in a certain population of giraffes, dark brown spots are dominant to light brown spots. If the frequency of dark brown giraffes is 56%, what is the frequency of the dark brown allele? Hint: the frequency that is provided is the frequency of a specific phenotype (i.e. not a genotype frequency)arrow_forward
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