The electron configuration of B is 1 S 2 2 S 2 2 P 1 . (a) If each core electron (i.e., the is electrons) were totally effective in shielding the valence electrons (i.e., the 2 s and 2 p electrons) from the nucleus and the valence electrons did not shield one another, what would be the shielding constant ( σ ) and the effective nuclear charge ( Z eff ) for the 2s and 2 p electrons? (b) In reality, the shielding constants for the 2 s and 2 p electrons in B are slightly different. They are 2.42 and 2.58. respectively. Calculate Z eff for these electrons, and explain the differences from the values you determined in part (a).
The electron configuration of B is 1 S 2 2 S 2 2 P 1 . (a) If each core electron (i.e., the is electrons) were totally effective in shielding the valence electrons (i.e., the 2 s and 2 p electrons) from the nucleus and the valence electrons did not shield one another, what would be the shielding constant ( σ ) and the effective nuclear charge ( Z eff ) for the 2s and 2 p electrons? (b) In reality, the shielding constants for the 2 s and 2 p electrons in B are slightly different. They are 2.42 and 2.58. respectively. Calculate Z eff for these electrons, and explain the differences from the values you determined in part (a).
Solution Summary: The author explains that the shielding constant and the effective nuclear charge are to be calculated for 2s& 2p electrons.
The electron configuration of B is
1
S
2
2
S
2
2
P
1
. (a) If each core electron (i.e., the is electrons) were totally effective in shielding the valence electrons (i.e., the 2s and 2p electrons) from the nucleus and the valence electrons did not shield one another, what would be the shielding constant
(
σ
)
and the effective nuclear charge (
Z
eff
) for the 2s and 2p electrons? (b) In reality, the shielding constants for the 2s and 2p electrons in B are slightly different. They are 2.42 and 2.58. respectively. Calculate
Z
eff
for these electrons, and explain the differences from the values you determined in part (a).
Naming and drawing secondary
Write the systematic (IUPAC) name for each of the following organic molecules:
CH3
Z
structure
CH3
CH2
CH2
N-CH3
CH3-CH2-CH2-CH-CH3
NH
CH3-CH-CH2-CH2-CH2-CH2-CH2-CH3
Explanation
Check
☐
name
☐
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G
C
This question shows how molecular orbital (MO) theory can be used to understand the chemical
properties of elemental oxygen O₂ and its anionic derivative superoxide Oz.
a)
Draw the MO energy diagram for both O2 and O2. Clearly label your diagram with atomic orbital names
and molecular orbital symmetry labels and include electrons.
Draw the Lewis structure of O2. How does the MO description of O2 differ from the Lewis structure, and
how does this difference relate to the high reactivity and magnetic properties of oxygen?
) Use the MO diagram in (a) to explain the difference in bond length and bond energy between superoxide
ion (Oz, 135 pm, 360 kJ/mol) and oxygen (O2, 120.8 pm, 494 kJ/mol).
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