Chemistry & Chemical Reactivity, Hybrid Edition (with OWLv2 24-Months Printed Access Card)
Chemistry & Chemical Reactivity, Hybrid Edition (with OWLv2 24-Months Printed Access Card)
9th Edition
ISBN: 9781285462530
Author: John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher: Cengage Learning
bartleby

Concept explainers

bartleby

Videos

Textbook Question
Book Icon
Chapter 7, Problem 21PS

Manganese is found as MnO2 in deep ocean deposits.

  1. (a) Depict the electron configuration of this element using the noble gas notation and an orbital box diagram.
  2. (b) Using an orbital box diagram, show the electrons beyond those of the preceding noble gas for Mn4+.
  3. (c) Is Mn4+ paramagnetic?
  4. (d) How many unpaired electrons does the Mn4+ ion have?

(a)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation:

The electronic configuration of Manganese has to be depicted using its orbital notation box and noble gas electron filling methods.

Concept Introduction:

Electronic configuration: The electronic configuration is the distribution of electrons of an given molecule or respective atoms in atomic or molecular orbitals.

The important there rules for electronic configuration given below:

Aufbau principle: This rule statues that ground state of an atom or ions electrons fill atomic orbitals of the lowest available energy levels before occupying higher levels. If consider the 1s shell is filled the 2s subshell is occupied.

Hund's Rule: The every orbital in a subshell is singly occupied with one electron before any one orbital is doubly occupied, and all electrons in singly occupied orbitals have the same spin.

Pauli exclusion rule: an atomic orbital may describe at most two electrons, each with opposite spin direction.

Paramagnetic: The Paramagnetic properties are due to the presence of some unpaired electrons, and from the realignment of the electron paths caused by the external magnetic field.

Diamagnetic properties: In diamagnetic materials all the electron are paired so there is no permanent net magnetic moment per atom.

Explanation of Solution

Let us consider the orbital filling method of Manganese (Mn) element

  AtomicnumberofManganese(Mn)=25spdfwith orbtital notation=[1s22s22p63s23p63d54s2Orbital filling method       1s22s22p63s23p63d54s2spdfwith noble gas notation=[Ar]3d54s2Orbitalboxnotation       =  [Ar]3d54s2

Hence, the electronic configuration of Manganese (Mn) = 1s22s22p63s23p63d54s2 and noble gas configuration of [Ar]3d54s2 

(b)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation:

The electronic configuration of Manganese ion (Mn4+) has to be depicted using its orbital notation box and noble gas electron filling methods.

Concept Introduction:

Electronic configuration: The electronic configuration is the distribution of electrons of an given molecule or respective atoms in atomic or molecular orbitals.

The important there rules for electronic configuration given below:

Aufbau principle: This rule statues that ground state of an atom or ions electrons fill atomic orbitals of the lowest available energy levels before occupying higher levels. If consider the 1s shell is filled the 2s subshell is occupied.

Hund's Rule: The every orbital in a subshell is singly occupied with one electron before any one orbital is doubly occupied, and all electrons in singly occupied orbitals have the same spin.

Pauli exclusion rule: an atomic orbital may describe at most two electrons, each with opposite spin direction.

Paramagnetic: The Paramagnetic properties are due to the presence of some unpaired electrons, and from the realignment of the electron paths caused by the external magnetic field.

Diamagnetic properties: In diamagnetic materials all the electron are paired so there is no permanent net magnetic moment per atom.

Explanation of Solution

 Let us consider the orbital filling method of Manganese (Mn4+) element

Than manganese (Mn) atom was oxidized to (Mn4+) ions, it lost for four electrons in outermost (4s and 3d) orbitals.

  AtomicnumberofManganese(Mn)=25Loss of four electrons in Manganeseatoms=25-4=21spdfwith orbtital notation=[1s22s22p63s23p63d34s0Orbital filling method       1s22s22p63s23p63d34s0spdfwith noble gas notation=[Ar]3d34s0Orbitalboxnotation       =  [Ar]3d34s0

Hence, the electronic configuration of Manganese (Mn4+) = 1s22s22p63s23p63d34s0 and noble gas configuration of [Ar]3d34s0 

(c)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation:

Mn4+ ion is paramagnetic or not has to be predicted.

Concept Introduction:

Electronic configuration: The electronic configuration is the distribution of electrons of an given molecule or respective atoms in atomic or molecular orbitals.

The important there rules for electronic configuration given below:

Aufbau principle: This rule statues that ground state of an atom or ions electrons fill atomic orbitals of the lowest available energy levels before occupying higher levels. If consider the 1s shell is filled the 2s subshell is occupied.

Hund's Rule: The every orbital in a subshell is singly occupied with one electron before any one orbital is doubly occupied, and all electrons in singly occupied orbitals have the same spin.

Pauli exclusion rule: an atomic orbital may describe at most two electrons, each with opposite spin direction.

Paramagnetic: The Paramagnetic properties are due to the presence of some unpaired electrons, and from the realignment of the electron paths caused by the external magnetic field.

Diamagnetic properties: In diamagnetic materials all the electron are paired so there is no permanent net magnetic moment per atom.

Explanation of Solution

AtomicnumberofManganese(Mn)=25Loss of four electrons in Manganeseatoms=25-4=21spdfwith orbtital notation=[1s22s22p63s23p63d34s0Orbital filling method       1s22s22p63s23p63d34s0spdfwith noble gas notation=[Ar]3d34s0Orbitalboxnotation       =  [Ar]3d34s0

The manganese (Mn4+) ion has three unpaired electrons in (3d) shells. Hence this system completely obeyed for paramagnetic nature, because all unpaired electrons occupying in each single shell, so this (Mn4+) is paramagnetic.

(d)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation:

The number of unpaired electrons the Mn4+ion possess has to be predicted.

Concept Introduction:

Electronic configuration: The electronic configuration is the distribution of electrons of an given molecule or respective atoms in atomic or molecular orbitals.

The important there rules for electronic configuration given below:

Aufbau principle: This rule statues that ground state of an atom or ions electrons fill atomic orbitals of the lowest available energy levels before occupying higher levels. If consider the 1s shell is filled the 2s subshell is occupied.

Hund's Rule: The every orbital in a subshell is singly occupied with one electron before any one orbital is doubly occupied, and all electrons in singly occupied orbitals have the same spin.

Pauli exclusion rule: an atomic orbital may describe at most two electrons, each with opposite spin direction.

Paramagnetic: The Paramagnetic properties are due to the presence of some unpaired electrons, and from the realignment of the electron paths caused by the external magnetic field.

Diamagnetic properties: In diamagnetic materials all the electron are paired so there is no permanent net magnetic moment per atom.

Explanation of Solution

     spdfwith orbtital notation=Mn[1s22s22p63s23p63d34s0Orbital filling method       1s22s22p63s23p63d34s0spdfwith noble gas notation=[Ar]3d34s0Orbitalboxnotation       =  [Ar]3d34s0

The manganese (Mn4+) system having three unpaired electrons, see the above electronic configuration diagram.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
A first order reaction is 46.0% complete at the end of 59.0 minutes. What is the value of k? What is the half-life for this reaction? HOW DO WE GET THERE? The integrated rate law will be used to determine the value of k. In [A] [A]。 = = -kt What is the value of [A] [A]。 when the reaction is 46.0% complete?
3. Provide the missing compounds or reagents. 1. H,NNH КОН 4 EN MN. 1. HBUCK = 8 хно Panely prowseful kanti-chuprccant fad, winddively, can lead to the crading of deduc din-willed, tica, The that chemooices in redimi Грин. " like (for alongan Ridovi MN نيا . 2. Cl -BuO 1. NUH 2.A A -BuOK THE CF,00,H Ex 5)
2. Write a complete mechanism for the reaction shown below. NaOCH LOCH₁ O₂N NO2 CH₂OH, 20 °C O₂N NO2

Chapter 7 Solutions

Chemistry & Chemical Reactivity, Hybrid Edition (with OWLv2 24-Months Printed Access Card)

Ch. 7.4 - Prob. 2RCCh. 7.4 - Which of the following species is most...Ch. 7.5 - Without looking at the figures for the periodic...Ch. 7.5 - What is the trend in sizes of the ions K+, S2, and...Ch. 7.5 - Prob. 2RCCh. 7.6 - Give the electron configurations for iron and the...Ch. 7.6 - Prob. 2QCh. 7.6 - Prob. 3QCh. 7.6 - Prob. 4QCh. 7.6 - Prob. 1RCCh. 7.6 - Prob. 2RCCh. 7.6 - The most common oxidation state of a rare earth...Ch. 7.6 - Prob. 6QCh. 7.6 - Prob. 7QCh. 7.6 - Use the atomic radii of scandium, yttrium,...Ch. 7.6 - Prob. 9QCh. 7.6 - Prob. 10QCh. 7 - Write the electron configurations for P and CI...Ch. 7 - Write the electron configurations for Mg and Ar...Ch. 7 - Using spdf notation, write the electron...Ch. 7 - Using spdf notation, give the electron...Ch. 7 - Prob. 5PSCh. 7 - Prob. 6PSCh. 7 - Use noble gas and spdf notations to depict...Ch. 7 - The lanthanides, once called the rare earth...Ch. 7 - Prob. 9PSCh. 7 - Prob. 10PSCh. 7 - What is the maximum number of electrons that can...Ch. 7 - What is the maximum number of electrons that can...Ch. 7 - Depict the electron configuration for magnesium...Ch. 7 - Depict the electron configuration for phosphorus...Ch. 7 - Using an orbital box diagram and noble gas...Ch. 7 - Using an orbital box diagram and noble gas...Ch. 7 - Using orbital box diagrams, depict an electron...Ch. 7 - Prob. 18PSCh. 7 - Prob. 19PSCh. 7 - Using orbital box diagrams and noble gas notation,...Ch. 7 - Manganese is found as MnO2 in deep ocean deposits....Ch. 7 - One compound found in alkaline batteries is NiOOH,...Ch. 7 - Prob. 23PSCh. 7 - Arrange the following elements in order of...Ch. 7 - Prob. 25PSCh. 7 - Prob. 26PSCh. 7 - Which of the following groups of elements is...Ch. 7 - Arrange the following atoms in order of increasing...Ch. 7 - Compare the elements Na, Mg, O, and P. (a) Which...Ch. 7 - Compare the elements B. Al, C, and Si. (a) Which...Ch. 7 - Explain each answer briefly. (a) Place the...Ch. 7 - Explain each answer briefly. (a) Rank the...Ch. 7 - Identify the element that corresponds to each of...Ch. 7 - Identify the element that corresponds to each of...Ch. 7 - Explain why the photoelectron spectra of hydrogen...Ch. 7 - Sketch the major features (number of peaks and...Ch. 7 - These questions are not designated as to type or...Ch. 7 - The deep blue color of sapphires comes from the...Ch. 7 - Using an orbital box diagram and noble gas...Ch. 7 - Prob. 40GQCh. 7 - Prob. 41GQCh. 7 - Prob. 42GQCh. 7 - Which of the following is not an allowable set of...Ch. 7 - A possible excited state for the H atom has an...Ch. 7 - The magnet in the following photo is made from...Ch. 7 - Name the element corresponding to each...Ch. 7 - Arrange the following atoms in order of increasing...Ch. 7 - Prob. 48GQCh. 7 - Answer the questions below about the elements A...Ch. 7 - Answer (he following questions about the elements...Ch. 7 - Which of the following ions are unlikely to be...Ch. 7 - Prob. 52GQCh. 7 - Answer each of the following questions: (a) Of the...Ch. 7 - Prob. 54GQCh. 7 - Prob. 55GQCh. 7 - Two elements in the second transition series (Y...Ch. 7 - Prob. 57GQCh. 7 - The configuration of an element is given here. (a)...Ch. 7 - Answer the questions below about the elements A...Ch. 7 - Answer the questions below concerning ground state...Ch. 7 - Nickel(II) formate [Ni(HCO2)2] is widely used as a...Ch. 7 - Spinets are solids with the general formula M2+...Ch. 7 - The following questions use concepts from this and...Ch. 7 - Which ions in the following list are not likely to...Ch. 7 - Answer the following questions about first...Ch. 7 - The ionization of the hydrogen atom can be...Ch. 7 - Compare the configurations below with two...Ch. 7 - Prob. 68SCQCh. 7 - Write electron configurations to show the first...Ch. 7 - Prob. 70SCQCh. 7 - (a) Explain why the sizes of atoms change when...Ch. 7 - Which of the following elements has the greatest...Ch. 7 - Prob. 73SCQCh. 7 - Prob. 74SCQCh. 7 - The energies of the orbitals in many elements have...Ch. 7 - The ionization energies for the removal of the...Ch. 7 - Using your knowledge of the trends in element...Ch. 7 - Prob. 78SCQCh. 7 - Prob. 79SCQCh. 7 - Prob. 80SCQCh. 7 - Thionyl chloride. SOCl2, is an important...Ch. 7 - Prob. 82SCQCh. 7 - Slaters rules are a way to estimate the effective...
Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Chemistry: Principles and Practice
Chemistry
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Cengage Learning
Text book image
Introductory Chemistry: A Foundation
Chemistry
ISBN:9781337399425
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Text book image
Chemistry: The Molecular Science
Chemistry
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:Cengage Learning
Atomic Number, Atomic Mass, and the Atomic Structure | How to Pass ChemistryThe Nucleus: Crash Course Chemistry #1; Author: Crash Course;https://www.youtube.com/watch?v=FSyAehMdpyI;License: Standard YouTube License, CC-BY