The amount of work done by John and Alex.
Answer to Problem 1OQ
Option (c) is correct. John does more work than Alex.
Explanation of Solution
Consider the speed of the carrier is negligible while it is lifted.
As Alex lifts his cabinet straight up from the ground to the bed of the truck work down by him is only due to gravitational potential energy of the cabinet.
While John slides his cabinet up a rough ramp to the truck he has to overcome friction force between the ramp and the cabinet and also gravitational potential energy of the cabinet.
So total work done by John is due to both energy due to friction and potential energy and work done by Alex is only due to gravitational energy.
Therefore, John does more work than Alex.
Conclusion:
John does more work than Alex. Thus, Option (c) is correct.
Alex and John do not do same amount of work as john does more work. Thus, Option (a) is incorrect.
Alex does more work than John is incorrect as Alex do not faces work done by friction on the cabinet. Thus, Option (b) is incorrect.
It is possible to determine who has done more work done without knowing the value of
The angle of the incline is not needed to determine who has done more work done. Thus, Option (e) is incorrect
Want to see more full solutions like this?
Chapter 7 Solutions
Physics for Scientists and Engineers with Modern, Revised Hybrid (with Enhanced WebAssign Printed Access Card for Physics, Multi-Term Courses)
- What is the resistance (in (2) of a 27.5 m long piece of 17 gauge copper wire having a 1.150 mm diameter? 0.445 ΧΩarrow_forwardFind the ratio of the diameter of silver to iron wire, if they have the same resistance per unit length (as they might in household wiring). d. Ag dFe = 2.47 ×arrow_forwardFind the ratio of the diameter of silver to iron wire, if they have the same resistance per unit length (as they might in household wiring). d Ag = 2.51 dFe ×arrow_forward
- Show that the units 1 v2/Q = 1 W, as implied by the equation P = V²/R. Starting with the equation P = V²/R, we can get an expression for a watt in terms of voltage and resistance. The units for voltage, V, are equivalent to [? v2 v2 A, are equivalent to J/C ✓ X . Therefore, 1 = 1 = 1 A V1 J/s Ω V-A X = 1 W. . The units for resistance, Q, are equivalent to ? The units for current,arrow_forwardPlease solve and answer the question correctly please. Thank you!!arrow_forwardPlease solve and answer the question correctly please. Thank you!!arrow_forward
- Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningUniversity Physics Volume 1PhysicsISBN:9781938168277Author:William Moebs, Samuel J. Ling, Jeff SannyPublisher:OpenStax - Rice UniversityGlencoe Physics: Principles and Problems, Student...PhysicsISBN:9780078807213Author:Paul W. ZitzewitzPublisher:Glencoe/McGraw-Hill
- College PhysicsPhysicsISBN:9781285737027Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningCollege PhysicsPhysicsISBN:9781938168000Author:Paul Peter Urone, Roger HinrichsPublisher:OpenStax CollegePhysics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning