Materials Science and Engineering Properties, SI Edition
1st Edition
ISBN: 9781305178175
Author: GILMORE, Charles
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Question
Chapter 7, Problem 1CQ
To determine
The reason for plastic strain in metals at temperature below half of melting temperature.
Expert Solution & Answer
Answer to Problem 1CQ
The motion of dislocation is the main reason for plastic strain in metals at temperature below half of melting temperature.
Explanation of Solution
Plastic strain is the strain obtained in material when the material is stretched beyond its elastic limit. Plastic strain is the permanent strain as material do not regains its original shape after the removal of force. The unloading curve on stress-strain curve follows a very different path from its original one.
The defects present in crystalline metals are the main reason for the plastic strain in them. The dislocations formed in metals during the solidification are one of the defects in it. In crystalline metals the motion of dislocation is the main reason for plastic strain in metals at temperature below half of melting temperature.
Conclusion:
Thus, motion of dislocation is the main reason for plastic strain in metals at temperature below half of melting temperature.
Want to see more full solutions like this?
Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
A floor consists of 8 steel beams/girders supporting three 1-way slab panels. The
beams are supported on 6 columns around the perimeter of the roof. The roof is
subjected to a uniform pressure of 150 psf . All beams and girders weigh 90lb//ft.
Use free-body diagrams and statics equations to determine the load and reactions
on all the beams (Beam 1, 2, 3 and 4), girders (Girders 1 and 2), and columns
(Columns 1, 2 and 3).
(we only focused on one-way slabs in the class + pls include FBDs)
Design an intake tower with gates meet the following requirement:
• Normal water surface elevation = 100 m mean sea level
• Max. reservoir elevation = 106 m msl
• Min. reservoir elevation = 90 m msl
• Bottom elevation = 81m msl
• Flow rate=57369.6 m³/day.. Velocity = 0.083 m/s
⚫c=0.6, Density for water =1000 kg/m³. Density for concrete =2310 kg/m³
Estimate water elevation that make safety factor =1
ร
4 m
Uppr gate
2m
1 m
Lower gate
2m
Gate
6m
2m
4 m
ร
2 m
wz
4. The storm hyetograph below produced 530 acre-ft of runoff
over the 725-acre Green River watershed. Plot the storm
hyetograph and compute and plot the excess rainfall
hyetograph using the op-index method.
Time (hours)
0-33-66-99-12 12-15
Rainfall Intensity (in/hr) 0.2 0.8|1.2 1.8 0.9
Chapter 7 Solutions
Materials Science and Engineering Properties, SI Edition
Ch. 7 - Prob. 1CQCh. 7 - Prob. 2CQCh. 7 - Prob. 3CQCh. 7 - Prob. 4CQCh. 7 - Prob. 5CQCh. 7 - Prob. 6CQCh. 7 - Prob. 7CQCh. 7 - Prob. 8CQCh. 7 - Prob. 9CQCh. 7 - Prob. 10CQ
Ch. 7 - Prob. 11CQCh. 7 - Prob. 12CQCh. 7 - Prob. 13CQCh. 7 - Prob. 14CQCh. 7 - Prob. 15CQCh. 7 - Prob. 16CQCh. 7 - Prob. 17CQCh. 7 - Prob. 18CQCh. 7 - Prob. 19CQCh. 7 - Prob. 20CQCh. 7 - Prob. 21CQCh. 7 - Prob. 22CQCh. 7 - Prob. 23CQCh. 7 - Prob. 24CQCh. 7 - Prob. 25CQCh. 7 - Prob. 26CQCh. 7 - Prob. 27CQCh. 7 - Prob. 28CQCh. 7 - Prob. 29CQCh. 7 - Prob. 30CQCh. 7 - Prob. 31CQCh. 7 - Prob. 32CQCh. 7 - Prob. 33CQCh. 7 - Prob. 34CQCh. 7 - Prob. 35CQCh. 7 - Prob. 36CQCh. 7 - Prob. 37CQCh. 7 - Prob. 38CQCh. 7 - Prob. 39CQCh. 7 - Prob. 40CQCh. 7 - Prob. 41CQCh. 7 - Prob. 42CQCh. 7 - Prob. 43CQCh. 7 - Prob. 44CQCh. 7 - Prob. 45CQCh. 7 - Prob. 46CQCh. 7 - Prob. 47CQCh. 7 - Prob. 48CQCh. 7 - Prob. 49CQCh. 7 - Prob. 50CQCh. 7 - Prob. 51CQCh. 7 - Prob. 52CQCh. 7 - Prob. 1DRQCh. 7 - Prob. 2DRQCh. 7 - Prob. 3DRQCh. 7 - Prob. 4DRQCh. 7 - Prob. 5DRQCh. 7 - Prob. 6DRQCh. 7 - Prob. 7DRQCh. 7 - Prob. 8DRQCh. 7 - Prob. 1ETSQCh. 7 - Prob. 2ETSQCh. 7 - Prob. 3ETSQCh. 7 - Prob. 4ETSQCh. 7 - Prob. 5ETSQCh. 7 - Prob. 6ETSQCh. 7 - Prob. 7ETSQCh. 7 - Prob. 8ETSQCh. 7 - Prob. 9ETSQCh. 7 - Prob. 7.1PCh. 7 - Prob. 7.2PCh. 7 - Prob. 7.3PCh. 7 - Prob. 7.4PCh. 7 - Prob. 7.5PCh. 7 - Prob. 7.6PCh. 7 - Prob. 7.7PCh. 7 - Prob. 7.8PCh. 7 - Prob. 7.9PCh. 7 - Prob. 7.10PCh. 7 - Prob. 7.11PCh. 7 - Prob. 7.13P
Knowledge Booster
Similar questions
- -125 mm -125 mm -125 mm 100 mm P A C 310 x 45 made of A36 is connected to a plate and carries a load P in tension. The bolts are 22-mm in diameter and is staggered as shown in figure PSAD-016. Properties of C 310 x 45 A = 5680 mm² d = 305 mm t = 12.7 mm tw = 13.0 mm b = 80.5 mm x = 17.1 mm Determine the shear lag factor of the channel. Determine the effective net area of the section in mm². Compute the design capacity of the section.arrow_forwardPlease answer the following and show the step by step answer on clear paperarrow_forwardProblem #1 (Beam optimization). Calculate the length "a" of AB such that the bending moment diagram is optimized (the absolute value of the max and the min is at its lowest). Then draw the shear and moment diagram for the optimized length. Optimize the length to the nearest 0.1 m. You can use RISA 2D as a tool to find the optimized length, however you need to solve for the support reactions at A, B and C by hand and draw the shear and moment diagram by hand. w=20 kN/m A + + a 12 m B Carrow_forward
- 2. Using the Green-Ampt Model, compute the infiltration rate, f, and cumulative infiltration, F, after one hour of infiltration into a sandy clay loam soil. Assume initial moisture conditions are midway between the field capacity and wilting point and that water is ponded to a small but negligible depth on the surface.arrow_forwardAssignment 1 Q1) Determine the member end forces of the frames shown by utilizing structural symmetry and anti-symm. (Derive each member forces and show BMD,SD,AFD) 20 kN/m 40 kN/m C D Hinge Ẹ G A -3m 5m B 5 m 3 m- E, I, A constant 12 marrow_forwardA1.3- Given the floor plan shown in Figure 3. The thickness of the slab is 150mm. The floor finish, ceiling and partition load is 1.8 kN/m². The live load on the floor is 2.4 kN/m². The beams cross section dimension is 300mmx600mm. Assuming the unit weight of concrete is equal to 24 kN/m². It is required to: a) Show tributary areas for all the beams on the plan; b) Calculate the load carried by beams B1 (on gridline A, between 1 and 3), B2 (on gridline B, between 1 and 3)and B3 (on gridline 3, between A and C); c) Calculate the load carried by column C1 per floor (ignore the self weight of the column). A 1 B1 2 B2 B Cl 8.0 m Figure 3 8.0 m B3 23 3 *2.0m 5.0 m 4.0 m +1.5m+arrow_forward
- Please show all steps and make sure to use the type of coordinate system (tangential/normal) specified.arrow_forwardFind required inlet length to intercept the entire flow and the capacity of a 3m long curb inlet. A gutter with z=20, n=0.015 and a slope of %1 caring a flow of 0.25 S m³/s curb depression (a=60 mm). Assume the only %75 of the upstream flow will be intercepted, what the length of curb inlet will be needed.arrow_forwardPlease answer this and show me the step by step solutiarrow_forward
- •Two types of concrete storm water drains are comparing: 1-pipe diameter 2m running full. 2-open channel rectangular profile, bottom width 2m and water depth 1.0 m. The drains are laid at gradient of %1.0; manning coefficient=0.013. Determine the velocity of flow and discharge rate for the circular drain. Determine the velocity of flow and discharge rate for the rectangular open culvert.arrow_forwardA1.2- For the frame shown in Figure 2, draw the bending moment, shear force, and axial force diagrams for the shown factored loading case. Note: All loads indicated in Figure 2 are already factored. W₁ = 25 kN/m Figure 2 777 6.0 m M= 10 kN.m P₁ = 20 kN 2.5 marrow_forwardPlease calculate the Centroid and the Moment of Inertia of the two shapes and submit your solution here in one PDF file with detailed calculationsarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Materials Science And Engineering PropertiesCivil EngineeringISBN:9781111988609Author:Charles GilmorePublisher:Cengage Learning
Principles of Foundation Engineering (MindTap Cou...Civil EngineeringISBN:9781337705028Author:Braja M. Das, Nagaratnam SivakuganPublisher:Cengage Learning
Materials Science And Engineering Properties
Civil Engineering
ISBN:9781111988609
Author:Charles Gilmore
Publisher:Cengage Learning
Principles of Foundation Engineering (MindTap Cou...
Civil Engineering
ISBN:9781337705028
Author:Braja M. Das, Nagaratnam Sivakugan
Publisher:Cengage Learning