Interpretation:
The yield that can be measured and not calculated has to be chosen from the given options.
Concept Introduction:
In a
Theoretical yield of a chemical reaction is the maximum amount of the product that can be obtained from the given amount of reactants provided there is no loss or inefficiencies occur. The actual yield of the chemical reaction is the experimental yield that is obtained. Actual yield of the product is always lesser than the theoretical yield. For this, there are two reasons. They are,
- In mechanical process, some of the product is lost. Mechanical process involves the transfer of materials from a container to another container.
- Unwanted side reactions occur in the actual chemical reaction due to impurities present. These are not considered in theoretical yield.
Actual yield is the amount of product that is got from a chemical reaction. The actual yield has to be measured and not calculated.
Percent yield is the term that is used to tell about the product loss. It is the ratio of the actual amount of product that is obtained in a chemical reaction to the theoretical yield multiplied by 100 to give percent. Mathematical equation for percent yield is given as,
Want to see the full answer?
Check out a sample textbook solutionChapter 6 Solutions
General, Organic, and Biological Chemistry
- QUESTION 3 After balancing the following chemical equation, what are the coefficient FeCl2 + NazPO4 - Fe3(РОд)2 + NaCl O A. 3,2,1,6 ОВ. 3,1,1,3 O C. 3,1,1,6 O D. 6,2,2,6 O E. 3,2,1,3 QUESTION 4arrow_forwardQuestion 33 When this equation is fully balanced with the smallest set of whole numbers, what is the stoichiometric coefficient for water? ____ Cu(OH)2 + ____ H3PO4 --> ____ Cu3(PO4)2 + ____ H2O Group of answer choices 6 2 3 4arrow_forwardQuestion 1 Homework Complete the mass data table given below. B I X, x' n Undo C Start Over O Row Column Table Title Mass data table Column 1 Column 2 Column 3 Data set name Trial 1 Trial 2 Mass of empty crucible and cover 25.165 g 24.931 g Mass of cover 10.731 g 10.278 g Mass of magnesium ribbon 0.350 g 0.375 g Mass of magnesium ribbon, crucible, 14.784 g 15.028 g Mass of magnesium ribbon, crucible, 25.745 g 25.522 g mass of product 0.580 g 0.591 g mass of oxygen 0.230 g 0.216 g Answered A Resubmit Question 2 Homework Calculate the Empirical formula for Trial 1 by completing the table given below. B I X, x' 2- n Undo C Start Over Column Row Table Title Calculate the Empirical formula for Trial 1 Column 1 Column 2 Column 3 Column 4 Column 5 Trial 1 grams Molar mass moles molar ratio Mgarrow_forward
- Please correct answer and don't use hand ratingarrow_forwardI need help with the last question, balanced chemical equationarrow_forwardProblem 7.64 - Enhanced - with Feedback 25 of 33 I Review | Constants | Periodic Table You may want to reference (Pages 245 - 246) Section 7.8 while completing this problem. Part A Calcium cyanamide reacts with water to form calcium carbonate and ammonia via the following reaction: How many grams of water are needed to react with 78.0 g CACN,? CACN2(s) + 3H20(1) → CACO3 (s) + 2NH3(g) ΑΣφ mass H20 = g Submit Previous Answers Request Answer X Incorrect; Try Again Part B How many grams of NH3 are produced from 5.19 g CACN2? ? mass NH3 = g Submit Request Answerarrow_forward
- Question 2 of 16 How many moles of H2SO. are required to completely react with 7.20 mol of AlI according to the balanced chemical reaction: Al(s) + H2SO (aq)A:(SO4)s(aq) + 3 H2(g) STARTING AMOUNT ANSWER RESET ADD FACTOR *( ) 1 26.98 98.08 21.6 342.14 3 7.20 10.8 2.02 6.022 x 1023 2.40 3.60 O Type here to searcharrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_ios
- Chemistry: Matter and ChangeChemistryISBN:9780078746376Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl WistromPublisher:Glencoe/McGraw-Hill School Pub Co