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Organic Chemistry Third Edition + Electronic Solutions Manual And Study Guide
3rd Edition
ISBN: 9781119351610
Author: David Klein
Publisher: Wiley Plus
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Question
Chapter 6.7, Problem 2LTS
Interpretation Introduction
Interpretation:
For the given molecule nucleophilic and electrophilic centers should be identified
Concept introduction:
Nucleophiles (positive-charge loving): A nucleophile is a more reactant species that affords a pair of electrons to the electrophile or electrophilic center and forms a new covalent bond.
The carbon or other hetero atom in a molecule which is bearing negative charge or lone pair of electron is called as nucleophiles.
Electrophile (negative-charge loving): An electrophile is a species that accepts a pair of electrons to form a new covalent bond.
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Students have asked these similar questions
Part I.
a) Elucidate
the structure of compound A using the following information.
• mass spectrum: m+ = 102, m/2=57
312=29
• IR spectrum:
1002.5
% TRANSMITTANCE
Ngg
50
40
30
20
90
80
70
60
MICRONS
5
8
9 10
12
13
14 15 16
19
1740 cm
M
10
0
4000
3600
3200
2800
2400
2000
1800
1600
13
• CNMR
'H
-NMR
Peak
8
ppm (H)
Integration
multiplicity
a
1.5 (3H)
triplet
b
1.3
1.5 (3H)
triplet
C
2.3
1 (2H)
quartet
d
4.1
1 (2H)
quartet
& ppm (c)
10
15
28
60
177 (C=0)
b) Elucidate the structure of compound B using the following information
13C/DEPT NMR 150.9 MHz
IIL
1400
WAVENUMBERS (CM-1)
DEPT-90
DEPT-135
85 80 75
70
65
60
55
50
45 40
35
30 25 20
ppm
1200
1000
800
600
400
•
Part II.
a) Elucidate The structure of compound c w/ molecular formula C10 11202 and the following data below:
• IR spectra
% TRANSMITTANCE
1002.5
90
80
70
60
50
40
30
20
10
0
4000
3600
3200
2800
2400
2000
1800
1600
• Information from 'HAMR
MICRONS
8 9 10
11
14 15 16
19
25
1400
WAVENUMBERS (CM-1)
1200
1000
800
600
400
peak
8 ppm
Integration
multiplicity
a
2.1
1.5 (3H)
Singlet
b
3.6
1 (2H)
singlet
с
3.8
1.5 (3H)
Singlet
d
6.8
1(2H)
doublet
7.1
1(2H)
doublet
Information from 13C-nmR
Normal carbon
29ppm
Dept 135
Dept -90
+
NO peak
NO peak
50 ppm
55 ppm
+
NO peak
114 ppm
t
126 ppm
No peak
NO peak
130 ppm
t
+
159 ppm
No peak
NO peak
207 ppm
по реак
NO peak
Could you redraw these and also explain how to solve them for me pleas
Chapter 6 Solutions
Organic Chemistry Third Edition + Electronic Solutions Manual And Study Guide
Ch. 6.1 - Prob. 1LTSCh. 6.1 - Prob. 1PTSCh. 6.1 - Prob. 2ATSCh. 6.2 - Prob. 3CCCh. 6.3 - Prob. 4CCCh. 6.3 - Prob. 5CCCh. 6.4 - Prob. 6CCCh. 6.6 - Prob. 7CCCh. 6.7 - Prob. 2LTSCh. 6.7 - Prob. 8PTS
Ch. 6.7 - Prob. 9PTSCh. 6.7 - (R)-(–)-Carvone is responsible for the...Ch. 6.8 - Prob. 3LTSCh. 6.8 - Most fabrics do a good job at protecting skin from...Ch. 6.9 - Prob. 4LTSCh. 6.9 - For each of the following multistep reactions,...Ch. 6.9 - Prob. 14ATSCh. 6.10 - Prob. 5LTSCh. 6.10 - Prob. 15PTSCh. 6.11 - Prob. 6LTSCh. 6.11 - Prob. 17PTSCh. 6.11 - George Olah was awarded the 1994 Nobel Prize in...Ch. 6 - Prob. 19PPCh. 6 - Prob. 20PPCh. 6 - For each of the following cases use the...Ch. 6 - Prob. 22PPCh. 6 - Prob. 23PPCh. 6 - Prob. 24PPCh. 6 - Prob. 25PPCh. 6 - Prob. 26PPCh. 6 - Prob. 27PPCh. 6 - Prob. 28PPCh. 6 - Prob. 29PPCh. 6 - Each of the following compounds exhibits two...Ch. 6 - Prob. 31PPCh. 6 - Prob. 32PPCh. 6 - Prob. 33PPCh. 6 - Prob. 34PPCh. 6 - Prob. 35PPCh. 6 - Prob. 36PPCh. 6 - Prob. 37PPCh. 6 - Prob. 38PPCh. 6 - Prob. 39PPCh. 6 - Prob. 40PPCh. 6 - Prob. 41PPCh. 6 - Prob. 42IPCh. 6 - Prob. 43IPCh. 6 - Prob. 44IPCh. 6 - Prob. 45IPCh. 6 - Prob. 46IPCh. 6 - Prob. 47IPCh. 6 - Prob. 48IPCh. 6 - Prob. 49IPCh. 6 - Prob. 50IPCh. 6 - Prob. 51IPCh. 6 - Prob. 52IPCh. 6 - Strychnine (6), a notorious poison isolated from...Ch. 6 - Prob. 54IPCh. 6 - Prob. 55IPCh. 6 - Prob. 56IPCh. 6 -
There are many examples of carbocation...Ch. 6 - Compound 1 undergoes a thermal elimination of...Ch. 6 - Prob. 59CP
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Similar questions
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- Nonearrow_forwardWhat spectral features allow you to differentiate the product from the starting material? Use four separate paragraphs for each set of comparisons. You should have one paragraph each devoted to MS, HNMR, CNMR and IR. 2) For MS, the differing masses of molecular ions are a popular starting point. Including a unique fragmentation is important, too. 3) For HNMR, CNMR and IR state the peaks that are different and what makes them different (usually the presence or absence of certain groups). See if you can find two differences (in each set of IR, HNMR and CNMR spectra) due to the presence or absence of a functional group. Include peak locations. Alternatively, you can state a shift of a peak due to a change near a given functional group. Including peak locations for shifted peaks, as well as what these peaks are due to. Ideally, your focus should be on not just identifying the differences but explaining them in terms of functional group changes.arrow_forwardQuestion 6 What is the major product of the following Diels-Alder reaction? ? Aldy by day of A. H о B. C. D. E. OB OD Oc OE OAarrow_forward
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