Chapter 6.6, Problem 4STP

A student spends no more than 2 hours on his math and English homework. If math takes about twice as long as English, what is the maximum time that the student can spend on English?

F. $\frac{1}{3}$ hour

G. $\frac{1}{2}$ hour

H. l hour

I. $\frac{2}{3}$ hour

To determine

To identify correct answer:The maximum time the student can spend on English.

Answer to Problem 4STP

Option I. $\frac{2}{3}hours$ .

Explanation of Solution

Given information:

Student spends time in English and Math’s homework = 2 hours

Math’s take twice as time English.

Let us consider,

English homework= E and

Math homework= M ;

According to question,

  $M+E \le 2hour\dots .\left(i\right)$

  $M=2E$

Putting the value of M in equation (i),

  $2E+E \le 2hours$

  $3E \le 2hours=120minutes \left(1hours=60minutes\right).$

  $E \le 120/3$

  $E \le 40minutes=\frac{2}{3}hours.$

So,

The student will be able to finish his English homework in less or equal $40minutesi.e.\frac{2}{3}hours$ .