Explanation Given: The demand of gas and electricity is $ 12 million, $ 15 million respectively, each dollar’s worth of the electric company’s output requires $0 .4 of its own output and $0 .5 of the gas company’s output, each dollar’s worth of the electric company’s output requires $0 .25 of its own output and $0 .60 of the electricity company’s output. Calculation: Let the output of electricity is x and the output of gas is y . From the provided conditions system equations are, 0.4 x + 0.6 y = 15 0.5 x + 0.25 y = 12 Write it into matrix form as shown below, Coefficient Matrix: A = [ 0.4 0.6 0.5 0.25 ] Matrix of Variables: X = [ x y ] Matrix of Constants: B = [ 15 12 ] Therefore, the Input-Output matrix A is, [ 0.4 0.6 0.5 0.25 ] Now, write it into a form of [ I − A ] as shown below, [ I − A ] = [ 1 0 0 1 ] − [ 0.4 0.6 0.5 0.25 ] = [ 0.6 − 0.6 − 0.5 0.75 ] The augmented matrix of the matrix [ I − A ] can be written as shown below, [ I − A | I ] = [ 0.6 − 0.6 1 0 − 0.5 0

MATH W/APPLICAT.W/NOTES GDE +ACCESS CODE

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Chapter 6.6, Problem 29E

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To calculate: The production of electricity and gas if there is a $12 million demand for gas and a $15 million demand for electricity.

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Chapter 6.6, Problem 27E

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MATH W/APPLICAT.W/NOTES GDE +ACCESS CODE

Ch. 6.1 - Checkpoint1 Use the substitution method tosolve...Ch. 6.1 - Checkpoint 2 Use the elimination method to solve...Ch. 6.1 - Checkpoint 3 Solve the system of equations . Draw...Ch. 6.1 - Checkpoint 4 Solve the following system: Ch. 6.1 - Checkpoint 5 Solve the system Draw the graph of...Ch. 6.1 - Prob. 6CP Ch. 6.1 - Prob. 1E Ch. 6.1 - Prob. 2E Ch. 6.1 - Use substitution to solve each system. (See...Ch. 6.1 - Use substitution to solve each system. (See...

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The production of electricity and gas if there is a $ 12 million demand for gas and a $ 15 million demand for electricity.

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