1 Problem 2 (a), (b) from the textbook [8 points] Prove that the following equations have at least one solution in the given interval. (a) √√x cos(x) = 0, interval [0, 1]. - (b) ex²+3x-2 = 0, interval [0, 1]. 2 Problem 4 (b), (c) from the textbook [8 points] Find intervals containing solutions to the following equations. (a) 4x² - ex = 0, (b) x3 2x24x + 2 = 0. 3 Problem 6 (d) from the textbook [8 points] Find maxo≤x≤1 |f(x)|, where f(x) = x√√3x². Hint: One of the possible method is to consi g(x) = f(x) instead of f. 4 Taylor series [8 points] Let f(x) = cos(x³)+(x+1)². Find the second Taylor polynomial P2(x) and sixth Taylor polynom P6(x) at x=0 and use it to approximate f(0.1). 5 Problem 14 (a), (b) from the textbook [8 points] Let f(x) = 2x cos(2x) - (x-2)². Find the third Taylor polynomial P3(x) at x0 = 0 and use it approximate f(0.4). Then use the error formula in Taylor's Theorem to find an upper bound the error |f(0.4) − P3(0.4)| < 0.1.
1 Problem 2 (a), (b) from the textbook [8 points] Prove that the following equations have at least one solution in the given interval. (a) √√x cos(x) = 0, interval [0, 1]. - (b) ex²+3x-2 = 0, interval [0, 1]. 2 Problem 4 (b), (c) from the textbook [8 points] Find intervals containing solutions to the following equations. (a) 4x² - ex = 0, (b) x3 2x24x + 2 = 0. 3 Problem 6 (d) from the textbook [8 points] Find maxo≤x≤1 |f(x)|, where f(x) = x√√3x². Hint: One of the possible method is to consi g(x) = f(x) instead of f. 4 Taylor series [8 points] Let f(x) = cos(x³)+(x+1)². Find the second Taylor polynomial P2(x) and sixth Taylor polynom P6(x) at x=0 and use it to approximate f(0.1). 5 Problem 14 (a), (b) from the textbook [8 points] Let f(x) = 2x cos(2x) - (x-2)². Find the third Taylor polynomial P3(x) at x0 = 0 and use it approximate f(0.4). Then use the error formula in Taylor's Theorem to find an upper bound the error |f(0.4) − P3(0.4)| < 0.1.
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.2: Trigonometric Equations
Problem 30E
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numerical ana
![1 Problem 2 (a), (b) from the textbook [8 points]
Prove that the following equations have at least one solution in the given interval.
(a) √√x cos(x) = 0, interval [0, 1].
-
(b) ex²+3x-2 = 0, interval [0, 1].
2 Problem 4 (b), (c) from the textbook [8 points]
Find intervals containing solutions to the following equations.
(a) 4x² - ex = 0,
(b) x3 2x24x + 2 = 0.
3 Problem 6 (d) from the textbook [8 points]
Find maxo≤x≤1 |f(x)|, where f(x) = x√√3x². Hint: One of the possible method is to consi
g(x) = f(x) instead of f.
4 Taylor series [8 points]
Let f(x) = cos(x³)+(x+1)². Find the second Taylor polynomial P2(x) and sixth Taylor polynom
P6(x) at x=0 and use it to approximate f(0.1).
5 Problem 14 (a), (b) from the textbook [8 points]
Let f(x) = 2x cos(2x) - (x-2)². Find the third Taylor polynomial P3(x) at x0 = 0 and use it
approximate f(0.4). Then use the error formula in Taylor's Theorem to find an upper bound
the error |f(0.4) − P3(0.4)| < 0.1.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd597ffd2-5c4b-4c2e-8332-77ce1607dac1%2Fd4d52faf-d5f9-477f-8418-54f357a051e3%2Fjr2btwo_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1 Problem 2 (a), (b) from the textbook [8 points]
Prove that the following equations have at least one solution in the given interval.
(a) √√x cos(x) = 0, interval [0, 1].
-
(b) ex²+3x-2 = 0, interval [0, 1].
2 Problem 4 (b), (c) from the textbook [8 points]
Find intervals containing solutions to the following equations.
(a) 4x² - ex = 0,
(b) x3 2x24x + 2 = 0.
3 Problem 6 (d) from the textbook [8 points]
Find maxo≤x≤1 |f(x)|, where f(x) = x√√3x². Hint: One of the possible method is to consi
g(x) = f(x) instead of f.
4 Taylor series [8 points]
Let f(x) = cos(x³)+(x+1)². Find the second Taylor polynomial P2(x) and sixth Taylor polynom
P6(x) at x=0 and use it to approximate f(0.1).
5 Problem 14 (a), (b) from the textbook [8 points]
Let f(x) = 2x cos(2x) - (x-2)². Find the third Taylor polynomial P3(x) at x0 = 0 and use it
approximate f(0.4). Then use the error formula in Taylor's Theorem to find an upper bound
the error |f(0.4) − P3(0.4)| < 0.1.
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