Explanation Procedure used: “ Factoring a x 2 + b x + c , a ≠ 1 using trial and error, where a, band c have no common factors: Step 1: List the possibilities for the first terms of each binomial whose product is a x 2 . Step 2: List the possibilities for the last terms of each binomial. Step 3: Write all the combinations of factors found in step 1 and step 2. Multiply the binomials until a product that equals the trinomial is found.” Calculation: The given polynomial is 27 h − 5 + 18 h 2 can be written as 18 h 2 + 27 h − 5 . The first term of the trinomial can be factorized as, ( 3 h + _ _ _ ) ( 6 h + _ _ _ ) . The product of the second term of the factor, ( 3 h + _ _ _ ) ( 6 h + _ _ _ ) should be –5. List the possibilities for the last terms of each binomial whose product is –5 as shown below in table 1. Factors of –5 –5, 1 5, –1 Table 1 Write all the combinations of factors found in above steps. Multiply the binomials until a product that equals the trinomial is found. The second term of ( 3 h + _ _ _ ) ( 6 h + _ _ _ ) has the only possibilities and the product is shown in Table 2

3rd Edition

ISBN: 9780321880116

Author: Michael Sullivan III, Katherine R. Struve, Janet Mazzarella

Publisher: PEARSON

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Chapter 6.5, Problem 74E

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To factorize: The polynomial 27h−5+18h2.

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Chapter 6.5, Problem 73E

Chapter 6.5, Problem 75E

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Elementary & Intermediate Algebra

Ch. 6.1 - The largest polynomial that divides evenly into a...Ch. 6.1 - Prob. 2E Ch. 6.1 - Prob. 3E Ch. 6.1 - Prob. 4E Ch. 6.1 - Prob. 5E Ch. 6.1 - Prob. 6E Ch. 6.1 - Prob. 7E Ch. 6.1 - Prob. 8E Ch. 6.1 - Prob. 9E Ch. 6.1 - Prob. 10E

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To factorize: The polynomial 27 h − 5 + 18 h 2 .

Solution Summary: The author calculates the polynomial 27h-5+18h2 using trial and error, where a, band c have no common factors.

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To factorize: The polynomial 27h−5+18h2.

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Chapter 6 Solutions